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Mila [183]
2 years ago
7

If you have long column labels with columns so wide that they affect the readability of a worksheet, you should first

Computers and Technology
1 answer:
Anon25 [30]2 years ago
3 0
You can format the columns for a certain width or you can use format cells, word wrap.
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g Fill the validateForm function to check that the phone number is 10 characters long and that the user name is less than 11 cha
Rom4ik [11]

Answer:

function validateForm(event)

{

event.preventDefault();

var phoneNumber = form.phoneNumber.value;

var userName = form.userName.value;

if(phoneNumber.length!=10)

console.log("Phone Number is Invalid");

if(userName.length<11)

console.log("User Name is Invalid"); }

8 0
2 years ago
First, open two separate terminal connections to the same machine, so that you can easily run something in one window and the ot
dusya [7]
Dnt listen to da file shi
7 0
2 years ago
One subtask in the game is to roll the dice. explain why is roll the dice an abstraction.
LUCKY_DIMON [66]

Answer:

A game is built from a combination of sub-tasks in order to provide the best experience to the user and make sure that the interface is comprises of only the results of the ongoing sub-tasks to provide a higher degree of data abstraction.

Data abstraction refers to the process of representing the essential information without including the background details. Rolling a dice is preferred to be a sub-task so that the user only gets to know about the result of the roll and does not have to wait for or anticipate the result. Moreover, a game may consist of n number of sub-tasks so it is not a good idea to include them in the main framework and are preferred to be abstracted.

4 0
2 years ago
Write a while loop that prints user_num divided by 2 until user_num is less than 1. The value of user_num changes inside of the
WITCHER [35]

Answer:

The code to this question can be defined as follows:

Code:

#include <stdio.h> //defining header file

int main() //defining main method

{

float user_num; //defining float variable

printf("Enter a value: "); //message

scanf("%f",&user_num); //input value from user end

printf("%f, ",user_num); //print value

while (user_num>1) //loop to calculte value

{

user_num=user_num/2; //diving value

printf("%f, ",user_num); //print value.

}

   return 0;

}

Output:

Enter a value: 20

20.000000, 10.000000, 5.000000, 2.500000, 1.250000, 0.625000,  

Explanation:

Description of the code as follows:

  • First, a float variable "user_num" is declared, in which we take input from the user-end.
  • In the next step, a while loop is declared, that uses the above variable to calculates its value.
  • Inside the loop variable "user_num" divide its value by 2 and holds its calculated value, to print its value the "printf" method is used that prints its value.  
8 0
2 years ago
How to write a program that prompts the user to input two POSITIVE numbers — a dividend (numerator) and a divisor (denominator).
fomenos

Answer:

num1 = int(input("Numerator: "))

num2 = int(input("Denominator: "))

if num1 < 1 or num2<1:

     print("Input must be greater than 1")

else:

     print("Quotient: "+str(num1//num2))

     print("Remainder: "+str(num1%num2))

Explanation

The next two lines prompts the user for two numbers

<em>num1 = int(input("Numerator: "))</em>

<em>num2 = int(input("Denominator: "))</em>

The following if statement checks if one or both of the inputs is not positive

<em>if num1 < 1 or num2<1:</em>

<em>      print("Input must be greater than 1")-> If yes, the print statement is executed</em>

If otherwise, the quotient and remainder is printed

<em>else:</em>

<em>      print("Quotient: "+str(num1//num2))</em>

<em>      print("Remainder: "+str(num1%num2))</em>

<em />

3 0
2 years ago
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