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leonid [27]
2 years ago
15

Write a second constructor as indicated. Sample output: User1: Minutes: 0, Messages: 0 User2: Minutes: 1000, Messages: 5000

Computers and Technology
1 answer:
Mashcka [7]2 years ago
6 0

Complete Question:

Write a second constructor as indicated. Sample output:User1: Minutes: 0, Messages: 0User2: Minutes: 1000, Messages: 5000// ===== Code from file PhonePlan.java =====public class PhonePlan { private int freeMinutes; private int freeMessages; public PhonePlan() { freeMinutes = 0; freeMessages = 0; } // FIXME: Create a second constructor with numMinutes and numMessages parameters. /* Your solution goes here */ public void print() { System.out.println("Minutes: " + freeMinutes + ", Messages: " + freeMessages); return; }}

Answer:

The second constructor is given as:

//This defines the constructor, the name has to be the same as the class //name

PhonePlan(int numOfMinutes, int numberOfMessages) {

this.freeMinutes = numOfMinutes;

this.freeMessages = numberOfMessages

}

Explanation:

The second constructor is defined using java programming language.

  1. The given class has two constructors This is called "Constructor Overloading) which implements polymophism
  2. In the second constructor that we created, we pass in two arguments of type integer numOfMinutes and numberOfMessages.
  3. In the constructor's body we assign these values to the initially declared variables freeMinutes and freeMessages
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Consider a short, 10-meter link, over which a sender can transmit at a rate of 150 bits/sec in both directions. Suppose that pac
Katarina [22]

Answer:

The Tp value 0.03 micro seconds as calculated in the explanation below is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP.

Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

Explanation:

Given details are below:

Length of the link = 10 meters

Bandwidth = 150 bits/sec

Size of a data packet = 100,000 bits

Size of a control packet = 200 bits

Size of the downloaded object = 100Kbits

No. of referenced objects = 10

Ler Tp to be the propagation delay between the client and the server, dp be the propagation delay and dt be the transmission delay.

The formula below is used to calculate the total time delay for sending and receiving packets :

d = dp (propagation delay) + dt (transmission delay)

For Parallel downloads through parallel instances of non-persistent HTTP :

Bandwidth = 150 bits/sec

No. of referenced objects = 10

For each parallel download, the bandwith = 150/10

  = 15 bits/sec

10 independent connections are established, during parallel downloads,  and the objects are downloaded simultaneously on these networks. First, a request for the object was sent by a client . Then, the request was processed by the server and once the connection is set, the server sends the object in response.

Therefore, for parallel downloads, the total time required  is calculated as:

(200/150 + Tp + 200/150 + Tp + 200/150 + Tp + 100,000/150 + Tp) + (200/15 + Tp + 200/15 + Tp + 200/150 + Tp + 100,000/15 + Tp)

= ((200+200+200+100,00)/150 + 4Tp) + ((200+200+200+100,00)/15 + 4Tp)

= ((100,600)/150 + 4Tp) + ((100,600)/15 + 4Tp)

= (670 + 4Tp) + (6706 + 4Tp)

= 7377 + 8 Tp seconds

Thus, parallel instances of non-persistent HTTP makes sense in this case.

Let the speed of propogation  of the medium be 300*106 m/sec.

Then, Tp = 10/(300*106)

               = 0.03 micro seconds

The Tp value 0.03 micro seconds as calculated above is negligible. This would lead to a similar value of time delay for both persistent HTTP and non-persistent HTTP. Thus, persistent HTTP is not faster than non-persistent HTTP with parallel downloads.

4 0
2 years ago
A slide in Blake's presentation contained the following information:
deff fn [24]

Answer:

consistent phrasing is missing

Explanation:

If you will note carefully, the bullets are not in correct format. The model is missing. The correct one is as below.

Risks

The correct form of presentation is as below:

1. Risks

a. employees  

              a. physical illness

              b. mental illness

              c. death  

2. Customers  

              a.   complaints

              b.   downtime

3.  Benefits

However, the content seems to be complete now, and hence not anything else is required. And since its not something very tough to decide to go with, bite the bullet is certainly not an issue.  

3 0
2 years ago
You want to register the domain name ABCcompany.org, but the registration service is not allowing you to do that. What's the mos
Andreyy89

Options :

The domain name is registered to someone else.

Domain names must end in ".com".

You are not the legal owner of ABC Company.

Domain names must be all in lowercase.

Answer:

The domain name is registered to someone else.

Explanation: In the scenario above, ABCcompany.org represents the domain name of a particular person or establishment which provides access to the website of the owner. The domain name given to an individual or website must be distinct, that is no two different organizations or persons can use exactly the same domain name. Domain names can end with :. com, org, ng and various other and they aren't case sensitive. Therefore, the inability to register the domain name abive will likely stem from the fact that the domain name has is already registered to someone else.

6 0
2 years ago
Write the recursive function max_depth; it is passed a binary (any binary tree, not necessarily a binary search tree) and a valu
OleMash [197]

Answer:

A python code was used in writing of the recursive function max_depth; and passed a binary (any binary tree, not necessarily a binary search tree) and a value as arguments.

Explanation:

Solution

To solve this given question we make use of Python programming language.

Thus

THE CODE:

class BinaryTreeNode:

def __init__(self, value, left=None, right=None):

self.value = value

self.left = left

self.right = right

# recursive max_depth function implementation

def max_depth(tree, value):

if tree == None:

return -1

# recursive calls to this function

leftDepth = max_depth(tree.left, value)

rightDepth = max_depth(tree.right, value)

# return the maximum depth

if tree.value == value or leftDepth > -1 or rightDepth > -1:

return 1 + max(leftDepth, rightDepth)

else:

return max(leftDepth, rightDepth)

btn1 = BinaryTreeNode(2)

btn2 = BinaryTreeNode(3, None, btn1)

btn3 = BinaryTreeNode(3)

btn4 = BinaryTreeNode(3)

btn5 = BinaryTreeNode(2, btn2, btn3)

btn6 = BinaryTreeNode(1, btn4)

tree = BinaryTreeNode(3, btn5, btn6)

print('max_depth(tree, 1):',max_depth(tree, 1))

print('max_depth(tree, 2):',max_depth(tree, 2))

print('max_depth(tree, 3):',max_depth(tree, 3))

Note: Kindly find an attached copy of the Implementation of max_depth() function, Code to test the max_depth() function and the sample output below.

8 0
2 years ago
Which of the following statements is incorrect? An operating system provides an environment for the execution of programs. An op
rosijanka [135]

Answer:

command line and graphical user interface

Explanation:

there were (and still are) operating system with no graphical user interface at all, as for example some Unix releases

8 0
2 years ago
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