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natita [175]
2 years ago
11

assume that name is a variable of type stirng that has been assigned a value write an expression whose value is the last charact

er of the value of name..."blair"...'r'....
Computers and Technology
1 answer:
Snezhnost [94]2 years ago
7 0

Answer:

The most straight forward way to do it: in general string are zero index based array of characters, so you need to get the length of the string, subtract one and that will be the last character, some expressions in concrete languages would be:

In Python:

name = "blair"

name[len(name) - 1]

In JavaScript:

name = "blair"

name[name.length - 1]

In C++:

#include <string>

string name = "blair";

name[name.length() - 1];

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Answer:

Motivation? The search problem.

Sorting algorithms: insertion sort, shellsort, heapsort, mergesort, quicksort, bubblesort

At the very least, "general purpose" sorting algorithms require O(n log n) comparisons

Explanation:

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2 years ago
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A variable like user_num can store a value like an integer. Extend the given program as indicated. Output the user's input. (2 p
lapo4ka [179]

Answer:

The answer to this question is given below in the explanation section. It is noted that this program is written in C++ using online C++ compiler.

Explanation:

#include <iostream>

using namespace std;

int squared(int num)// this is the function to compute square

   {

       return num*num;

   }

int cube(int num)// this is the function to compute cube

   {

       return num*num*num;

   }

int main()

{

   int user_num, user_num2; // variable declaration

   

       cout<<"Enter the first number: ";//prompt user to enter the number

       cin>>user_num;//store the user entered number into variable

       cout<<"\nEnter the second number: ";//prompt the user to enter the second number

       cin>>user_num2;//store the user entered number into variable

   

   

   cout<<"\nSquared of first number is: "<<squared(user_num);//compute square of user_num and display

   cout<<"\nCube of first number is: "<<cube(user_num);//compute the cube of the user_num and display

   cout<<"\nSquare of second number is: "<<squared(user_num2);//compute the square of user_num2 and display

   cout<<"\nCube of second number is: "<<cube(user_num2);//compute the cube of user_num2 and display

   

   cout<<"\nSum of number 1 and number 2 is: "<<user_num2 + user_num2;//display the sum of user_num2 and user_num

   cout<<"\nProduct of number 1 and number 2 is: "<<user_num2 * user_num;//display the product of user_num and user_num2

   

   

   return 0;//terminate the program

}

                               

7 0
2 years ago
Chinh wants to have a program print, "Sorry, but that isn’t one of your options" until the user enters the correct information.
kolbaska11 [484]

Answer:

a wile loop

Explanation:

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