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Allushta [10]
2 years ago
8

The process of __________ encourages members to accept responsibility for the outcomes of a group and for changing the style in

which they relate to others. a. selective feedback b. interpersonal feedback c. confrontive feedback d. aggressive feedback
Computers and Technology
1 answer:
soldier1979 [14.2K]2 years ago
8 0

Answer:

The correct answer to the following question will be Option B (Interpersonal feedback).

Explanation:

  • Interpersonal feedback seems to be a mechanism under which someone talks. Individuals deliver a message regarding their sensations and expectations of actions by another.
  • It encourages employees to take obligation for a group's results and to change the look they correspond to many other people in.

Therefore, Interpersonal feedback is the right answer.

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The bit width of the LRU counter for a 32 KB 16-way set associative cache with 32 Byte line size is
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Answer:

your answer would be A

Explanation:

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Splunk uses ________ to categorize the type of data being indexed..
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Splunk uses sourcetypes to categorize the type of data being indexed.
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Write a method that will receive 2 numbers as parameters and will return a string containing the pattern based on those two numb
Kipish [7]

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The purpose of the Java compiler is to translate source code into instructions  public static void main(String[] args)  Arity is the number of arguments passed to a constructor or method or the number ... and objects, which are the focus of object-based programs.  Remove the 2 from between the square brackets to make.

Explanation:

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In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation dur
masha68 [24]

Answer:

B. The process will be terminated by the operating system.

Explanation:

When Round Robin is used for CPU scheduling, a time scheduler which is a component of the operating system is used in regulating the operation. A time limit is set for each of the processes to be run.

So, when a process fails to complete running before its time elapses, the time scheduler would log it off and return it to the queue. This queue is in a circular form and gives each of the processes a chance to run its course.

7 0
2 years ago
Write an expression that continues to bid until the user enters 'n'.
alisha [4.7K]

Answer:

1)

Add this while statement to the code:

while(keep_going!='n'):  

#the program keeps asking user to continue bidding until the user enter 'n' to stop.

2)

Here is the code for ACTIVITY 53.3. While loop: Insect growth:

num_insects = int(input())

while num_insects <= 100:

   print(num_insects, end=' ')

   num_insects = num_insects * 2

 

Explanation:

Here is the complete code for 1)

import random

random.seed (5)

keep_going='-'

next_bid = 0

while(keep_going!='n'):

   next_bid = next_bid + random.randint(1, 10)

   print('I\'ll bid $%d!' % (next_bid))

   print('continue bidding?', end='')

   keep_going = input()

Here the the variable keep_going is initialized to a character dash keep_going='-'

The statement keep_going = input() has an input() function which is used to take input from user and this input value entered by user is stored in keep_going variable. while(keep_going!='n'):  is a while loop that keeps iterating until keep_going is not equal to 'n'.    print('continue bidding?', end='')  statement prints the continue bidding? message on the output screen. For example the user enters 'y' when this message appears on screen. So keep_going = 'y' . So the operation in this statement next_bid = next_bid + random.randint(1, 10) is executed in which next_bid is added to some randomly generated integer within the range of 1 to 10 and print('I\'ll bid $%d!' % (next_bid))  prints the result on the screen. Then the user is prompted again to continue biffing. Lets say user enters 'n' this time. So keep_going = 'n'. Now the while loop breaks when user enters 'n' and the program ends.

2)

num_insects = int(input()) #the user is prompted to input an integer

while num_insects <= 100: #the loop keeps iterating until value of num_insects exceeds 100

   print(num_insects, end=' ') #prints the value of num_insects  

   num_insects = num_insects * 2 #the value of num_insects is doubled

For example user enters 8. So

num_insects = 8

Now the while loop checks if this value is less than or equal to 100. This is true because 8 is less than 100. So the body of while loop executes:

   print(num_insects, end=' ') statement prints the value of num_insects

So 8 is printed on the screen.

num_insects = num_insects * 2 statement doubles the value of num_insects So this becomes:

num_insects = 8 * 2

num_insects = 16

Now while loop checks if 16 is less than 100 which is again true so next 16 is printed on the output screen and doubled as:

num_insects = 16 * 2

num_insects = 32

Now while loop checks if 32 is less than 100 which is again true so next 32 is printed on the output screen and doubled as:

num_insects = 32 * 2

num_insects = 64

Now while loop checks if 64 is less than 100 which is again true so next 64 is printed on the output screen and doubled as:

num_insects = 64 * 2

num_insects = 128

Now while loop checks if 128 is less than 100 which is false so the program stops and the output is:

8 16 32 64  

The programs along with their output is attached.

7 0
2 years ago
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