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cestrela7 [59]
2 years ago
14

c++ Consider this data sequence: "3 11 5 5 5 2 4 6 6 7 3 -8". Any value that is the same as the immediately preceding value is c

onsidered a CONSECUTIVE DUPLICATE. In this example, there are three such consecutive duplicates: the 2nd and 3rd 5s and the second 6. Note that the last 3 is not a consecutive duplicate because it was preceded by a 7. Write some code that uses a loop to read such a sequence of non-negative integers, terminated by a negative number. When the code exits the loop it should print the number of consecutive duplicates encountered. In the above case, that value would be 3.
Computers and Technology
2 answers:
Ludmilka [50]2 years ago
8 0

Answer:

int firstNumber,secondNumber = -1, duplicates = 0;

do {

   cin >> firstNumber;

   if ( secondNumber == -1) {

       secondNumber = firstNumber;

   }else {

       if ( secondNumber == firstNumber )

           duplicates++;

       else

           secondNumber = firstNumber;

   }

} while(firstNumber > 0 );

 

cout << duplicates;

Explanation:

Write some code that uses a loop to read such a sequence of non-negative integers, terminated by a negative number. When the code exits the loop it should print the number of consecutive duplicates encountered. In the above case, that value would be 3. We test the following on a C++ platform.

int firstNumber,secondNumber = -1, duplicates = 0;

do {

   cin >> firstNumber;

   if ( secondNumber == -1) {

       secondNumber = firstNumber;

   }else {

       if ( secondNumber == firstNumber )

           duplicates++;

       else

           secondNumber = firstNumber;

   }

} while(firstNumber > 0 );

 

cout << duplicates;

Ksivusya [100]2 years ago
4 0

<u>Answer:</u>

<em>int fNumber,scndNumber = -1,  </em>

<em>dup = 0; </em>

<em>do { </em>

<em>cin >> fNumber; </em>

<em>if ( scndNumber == -1) { </em>

<em>scndNumber = fNumber; </em>

<em>} </em>

<em>else { </em>

<em>if ( scndNumber == fNumber ) </em>

<em>duplicates++; </em>

<em>else </em>

<em>scndNumber = fNumber; </em>

<em>} </em>

<em>} while(fNumber > 0 );  </em>

<em>cout << dup; </em>

<u>Explanation:</u>

Here three variables are declared to hold the first number which is used obtain all the inputs given by the user, second number to hold the value of <em>last encountered number and “dup” variable to count the number of duplicate values.</em>

<em>“Do-while”</em> loop help us to get the input check whether it is same as previous input if yes then it <em>adds to the duplicate</em> value otherwise the new previous value if stored.

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NikAS [45]

Answer:

C++.

Explanation:

<em>Code snippet.</em>

#include <map>

#include <iterator>

cin<<N;

cout<<endl;

/////////////////////////////////////////////////

map<string, string> contacts;

string name, number;

for (int i = 0; i < N; i++) {

   cin<<name;

   cin<<number;

   cout<<endl;

   contacts.insert(pair<string, string> (name, number));

}

/////////////////////////////////////////////////////////////////////

map<string, string>::iterator it = contacts.begin();

while (it != contacts.end())  {

   name= it->first;

   number = it->second;

   cout<<word<<" : "<< count<<endl;

   it++;

}

/////////////////////////////////////////////////////////////////////////////////////////////////////////

I have used a C++ data structure or collection called Maps for the solution to the question.

Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.

8 0
2 years ago
The processing of data in a computer involves the interplay between its various hardware components.
Ronch [10]

True.

Data processing involves the conversion of raw data and the flow of data through the Central Processing Unit and Memory to output devices. Each CPU in a computer contains two primary elements: the Arithmetic Logic Unit (ALU) and the control unit. The Arithmetic Logic Unit performs complex mathematical calculations and logical comparisons. On the other hand, the control unit accesses computer instructions, decodes them, and controls the flow of data in and out of the Memory, ALU, primary and secondary storage, and various other output devices.  


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2 years ago
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The power of science of course
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Consider an improved version of the Vigen ere cipher, where instead of using multiple shift ciphers, multiple mono-alphabetic su
anzhelika [568]

Answer:

Kasiski’s method for determining 't' works for Vigenère cipher as well. The only difference is therefore in the second stage of the attack. In the second stage, one needs to build a frequency table for each of the 't' keys, and carry out an attack like on the mono-alphabetic cipher. Given a long enough plaintext, this will work successfully.

Explanation:

Kasiski method is a method of attacking polyalphabetic substitution ciphers such as Vigenère cipher. It is also called Kasiski test or Kasiski examination.

The method involve finding the length of the keyword and then dividing the message into that many simple substitution cryptograms. Frequency analysis could then be used to solve the resulting simple substitution.

6 0
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