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abruzzese [7]
2 years ago
14

3.34 LAB: Mad Lib - loops in C++

Computers and Technology
1 answer:
Ganezh [65]2 years ago
7 0

Answer:

A Program was written to carry out some set activities. below is the code program in C++ in the explanation section

Explanation:

Solution

CODE

#include <iostream>

using namespace std;

int main() {

string name; // variables

int number;

cin >> name >> number; // taking user input

while(number != 0)

{

// printing output

cout << "Eating " << number << " " << name << " a day keeps the doctor away." << endl;

// taking user input again

cin >> name >> number;

}

}

Note: Kindly find an attached copy of the compiled program output to this question.

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George has to present the goals of information management to his team member. What is a goal of information management? The goal
Law Incorporation [45]

Answer:

The purpose of information management is to: design, develop, manage, and use information with insight and innovation. support decision making and create value for individuals, organizations, communities, and societies.

Explanation:

5 0
2 years ago
A contact list is a place where you can store a specific contact with other associated information such as a phone number, email
NikAS [45]

Answer:

C++.

Explanation:

<em>Code snippet.</em>

#include <map>

#include <iterator>

cin<<N;

cout<<endl;

/////////////////////////////////////////////////

map<string, string> contacts;

string name, number;

for (int i = 0; i < N; i++) {

   cin<<name;

   cin<<number;

   cout<<endl;

   contacts.insert(pair<string, string> (name, number));

}

/////////////////////////////////////////////////////////////////////

map<string, string>::iterator it = contacts.begin();

while (it != contacts.end())  {

   name= it->first;

   number = it->second;

   cout<<word<<" : "<< count<<endl;

   it++;

}

/////////////////////////////////////////////////////////////////////////////////////////////////////////

I have used a C++ data structure or collection called Maps for the solution to the question.

Maps is part of STL in C++. It stores key value pairs as an element. And is perfect for the task at hand.

8 0
2 years ago
What are two characteristics of a scalable network? (choose two.)?
vampirchik [111]

The two characteristics of scalable network are such that it can easily grow in size without causing any impact to the current users. This means, increase in network capacity and technical capability will not have any detrimental effects to the users.  Another characteristic of this network is that it can work perfectly with modular devices provided they   support expansion process.


7 0
2 years ago
Which of the following is an absolute cell reference
rodikova [14]

Answer:

The content of the cell is called an absolute cell reference.

Explanation:

Ms-excel can hold a value or string or number or formulas in each cell.  

The end-user can input the values to a cell and do any calculation by using inbuilt formulas and do the necessary calculation and get the output in the required cell  

When end-user try to copy and paste the data to another cell he or she can use paste special option where he or she can select values, by selecting values to end-user is just copying the data not formula this is called absolute reference of the cell

By using paste special end users copy the image or Unicode also.

This process is called an absolute cell reference

6 0
1 year ago
Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer
NeTakaya

Answer:

Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

Explanation:

The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

6 0
2 years ago
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