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maria [59]
2 years ago
7

For his class project, Matt has to create an image in a color scheme that has shade or tint variations of the same hue. Which co

lor scheme should he use?
A.
achromatic
B.
monochromatic
C.
tetradic
D.
split-complementary
E.
square
Computers and Technology
1 answer:
Alex2 years ago
5 0

Answer:

B.Monochromatic

Explanation:

mono means one

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BlockPy: #35.2) Animal Splits Write a function all_cats that consumes a comma-separated string of animals and prints whether all
maks197457 [2]

Answer:

def all_cats(data):

 dataArray = data.split(',')

 if(data==""):

   return True

 for i in dataArray:

   if('cat' not in i):

     return False

 

 return True

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

Explanation:

Step 1: define de function and the parameters

def all_cats(data):

Step 2: split the data by ,

dataArray = data.split(',')

Step 3 : validate if is an empty data and return true

if(data==""):

   return True

Step 4: Loop over de array data and validate if have cat in each data if not, then return false

for i in dataArray:

   if('cat' not in i):

     return False

Step 5 if have cat in each one return true

return True

Step 6 Validate with examples

print(all_cats("gerbil,catfish,dog,cat"))

print(all_cats("cat,catfish"))

print(all_cats(""))

6 0
2 years ago
Create a single list that contains the following collection of data in the order provided:
ivann1987 [24]

Answer:

A code was created to single list that contains the following collection of data in the order provided

Explanation:

Solution

#list that stores employee numbers

employeee_numbers=[1121,1122,1127,1132,1137,1138,1152,1157]

#list that stores employee names

employee_name=["Jackie Grainger","Jignesh Thrakkar","Dion Green","Jacob Gerber","Sarah Sanderson","Brandon Heck","David Toma","Charles King"]

#list that stores wages per hour employee

hourly_rate=[22.22,25.25,28.75,24.32,23.45,25.84,22.65,23.75]

#list that stores salary employee

company_raises=[]

max_value=0

#list used to store total_hourly_rate

total_hourly_rate=[]

underpaid_salaries=[]

#loop used to musltiply values in hourly_wages with 1.3

#and store in new list called total_hourly_rate

#len() is used to get length of list

for i in range(0,len(hourly_rate)):

#append value to the list total_hourly_rate

total_hourly_rate.append(hourly_rate[i]*1.3)

for i in range(0,len(total_hourly_rate)):

#finds the maximum value

if(total_hourly_rate[i]>max_value):

max_value=total_hourly_rate[i] #stores the maximum value

if(max_value>37.30):

print("\nSomeone's salary may be a budget concern.\n")

for i in range(0,len(total_hourly_rate)):

#check anyone's total_hourly_rate is between 28.15 and 30.65

if(total_hourly_rate[i]>=28.15 and total_hourly_rate[i]<=28.15):

underpaid_salaries.append(total_hourly_rate[i])

for i in range(0,len(hourly_rate)):

#check anyone's hourly_rate is between 22 and 24

if(hourly_rate[i]>22 and hourly_rate[i]<24):

#adding 5%

hourly_rate[i]+=((hourly_rate[i]/100)*5)

elif(hourly_rate[i]>24 and hourly_rate[i]<26):

#adding 4%

hourly_rate[i]+=((hourly_rate[i]/100)*4)

elif(hourly_rate[i]>26 and hourly_rate[i]<28):

#adding 3%

hourly_rate[i]+=((hourly_rate[i]/100)*3)

else:

#adding 2% for all other salaries

hourly_rate[i]+=((hourly_rate[i]/100)*2)

#adding all raised value to company_raises

company_raises.extend(hourly_rate)

#The comparison in single line

for i in range(0,len(hourly_rate)):

 For this exercise i used ternary

operator hourly_rate[i]= (hourly_rate[i]+((hourly_rate[i]/100)*5)) if (hourly_rate[i]>22 and hourly_rate[i]<24) else (hourly_rate[i]+((hourly_rate[i]/100)*4)) if (hourly_rate[i]>24 and hourly_rate[i]<26) else hourly_rate[i]+((hourly_rate[i]/100)*2)

8 0
2 years ago
Another solution to minimize resonance is to ________ the bridge.
lakkis [162]
I believe the answer is d
7 0
2 years ago
Reputable firms often ask recent graduates to pay an up-front fee for a job.
koban [17]

Answer:

What is your question?

Explanation:

5 0
2 years ago
Read 2 more answers
Suppose that a 10-Mbps wireless station is transmitting 50-byte frames one immediately after the other.
Andre45 [30]
8 bits = 1 byte

10 Mbps = 10/8 M bytes per second

1 frame = 50 bytes

Frame rate = 10 M / (8 x 50) =  10 M / 400 = <em>25,000 frames per second</em>

========================

If each frame has an error probability of 0.004, then (0.004 x 25,000) = 100 frames per second are damaged.

1 hour = 3,600 seconds.

100 damaged frames per second = (100 x 3,600) = <em>360,000 damaged frames per hour.</em>
7 0
2 years ago
Read 2 more answers
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