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Alexandra [31]
1 year ago
7

Write a method named removeDuplicates that accepts a string parameter and returns a new string with all consecutive occurrences

of the same character in the string replaced by a single occurrence of that character. For example, the call of removeDuplicates("bookkeeeeeper") should return "bokeper" .
Computers and Technology
1 answer:
Nitella [24]1 year ago
7 0

Answer:

//Method definition

//Method receives a String argument and returns a String value

public static String removeDuplicates(String str){

       //Create a new string to hold the unique characters

       String newString = "";

       

       //Create a loop to cycle through each of the characters in the

       //original string.

       for(int i=0; i<str.length(); i++){

           // For each of the cycles, using the indexOf() method,

           // check if the character at that position

           // already exists in the new string.

           if(newString.indexOf(str.charAt(i)) == -1){

               //if it does not exist, add it to the new string

               newString += str.charAt(i);

           }  //End of if statement

       }   //End of for statement

       

       return newString;   // return the new string

   }  //End of method definition

Sample Output:

removeDuplicates("bookkeeeeeper") => "bokeper"

Explanation:

The above code has been written in Java. It contains comments explaining every line of the code. Please go through the comments.

The actual lines of codes are written in bold-face to distinguish them from comments. The program has been re-written without comments as follows:

public static String removeDuplicates(String str){

       String newString = "";

       

       for(int i=0; i<str.length(); i++){

           if(newString.indexOf(str.charAt(i)) == -1){

               newString += str.charAt(i);

           }

       }

       

       return newString;

   }

From the sample output, when tested in a main application, a call to removeDuplicates("bookkeeeeeper") would return "bokeper"

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Answer:

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   double n1, n2, n3;

   cout<<"Enter 3 inputs: ";

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   double *p;

   p = sum_n_avg(n1,n2,n3);

   cout<<"Sum: "<<*(p + 0) << endl;

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  arr[0] = n1 + n2 + n3;

  arr[1] = arr[0]/3;

  return arr;

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Explanation:

This defines the function prototype

double *sum_n_avg(double n1, double n2, double n3);

The main begins here

int main () {

This declares variables for input

   double n1, n2, n3;

This prompts the user for 3 inputs

   cout<<"Enter 3 inputs: ";

This gets user inputs

   cin>>n1>>n2>>n3;

This declares a pointer to get the returned values from the function

   double *p;

This passes n1, n2 and n3 to the function and gets the sum and average, in return.

   p = sum_n_avg(n1,n2,n3);

Print sum and average

<em>    cout<<"Sum: "<<*(p + 0) << endl;</em>

<em>    cout<<"Average: "<<*(p + 1) << endl;</em>

  return 0;

}

The function begins here

double *sum_n_avg(double n1, double n2, double n3) {

Declare a static array

  static double arr[2];

Calculate sum

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  arr[1] = arr[0]/3;

Return the array to main

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Answer:

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Explanation:

Following is the description of Statement

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Answer:

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<em>Code snippet.</em>

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/////////////////////////////////////////////////////////////////////

map<string, string>::iterator it = contacts.begin();

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/////////////////////////////////////////////////////////////////////////////////////////////////////////

I have used a C++ data structure or collection called Maps for the solution to the question.

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