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Stels [109]
2 years ago
9

Write the definition of a class Telephone. The class has no constructors, one instance variable of type String called number, an

d two static variables. One is of type int called quantity, initialized to 250; the other is of type double called total, initialized to 15658.92.
Computers and Technology
1 answer:
balu736 [363]2 years ago
5 0

Answer:

The definition of a class Telephone is given as  

public class Telephone // class telephone

{

String number; // variable  number of type string

static int quantity = 250; // variable  quantity  of type int

static double total = 1565.92;  // variable  total  of type double

}

Explanation:

Following is the description of Statement

  • Create a class "Telephone" by using the keyword class.In that class we declared data member .
  • We declared a variable "number" of type "string" which has no constructor.
  • We declared a variable  "quantity" of type "int" which is a static type variable. The static type variable retains the value during the program execution.
  • We declared a variable  "total" of type "double" which is a static type variable. The static type variable retain the value during the program execution .
You might be interested in
JAVA Write a program that first asks the user to type a letter grade and then translates the letter grade into a number grade. L
ale4655 [162]

Answer:

Follows are the code to this question:

import java.util.*;//import package for user input

class GradePrinter//defining class GradePrinter

{

double numericValue = 0;//defining double variable

String grade = "";//defining String variable

GradePrinter()//defining default constructor  

{

Scanner xb = new Scanner(System. in );//defining Scanner  class object

System.out.print("Enter Grade: ");//print message

grade = xb.nextLine();//input string value  

}

double getNumericGrade()//defining double method getNumericGrade

{

if (grade.equals("A+") || grade.equals("A"))//defining if block that check input is A+ or A

{

numericValue = 4.0;//using  numericValue variable that hold float value 4.0

}

else if (grade.equals("A-"))//defining else if that check grade equals to A-

{

numericValue = 3.7;//using  numericValue variable that hold float value 3.7

}

else if (grade.equals("B+"))//defining else if that check grade equals to B-

{

numericValue = 3.3;//using  numericValue variable that hold float value 3.3

}

else if (grade.equals("B"))//defining else if that check grade equals to B

{

numericValue = 3.0;//using  numericValue variable that hold float value 3.0

}

else if (grade.equals("B-"))//defining else if that check grade equals to B-  

{

numericValue = 2.7;//using  numericValue variable that hold float value 2.7

}

else if (grade.equals("C+"))//defining else if that check grade equals to C+  

{

numericValue = 2.3; //using  numericValue variable that hold float value 2.3

}

else if (grade.equals("C")) //defining else if that check grade equals to C  

{

numericValue = 2.0; //using numericValue variable that hold float value 2.0

}

else if (grade.equals("C-")) //defining else if that check grade equals to C-  

{

numericValue = 1.7;//using umericValue variable that hold float value 1.7

}

else if (grade.equals("D+"))//defining else if that check grade equals to D+  

{

numericValue = 1.3;//using umericValue variable that hold float value 1.3

}

else if (grade.equals("D"))//defining else if that check grade equals to D

{

numericValue = 1.0;//using umericValue variable that hold float value 1.0

}

else if (grade.equals("F"))//defining else if that check grade equals to F

{

numericValue = 0;//using umericValue variable that hold value 0

}

else//defining else block

{

System.out.println("Letter not in grading system");//print message

}

return numericValue;//return numericValue

}

}

class Main//defining a class main

{

public static void main(String[] args)//defining main method

{

GradePrinter ob = new GradePrinter();// creating class GradePrinter object

double numericGrade = ob.getNumericGrade();//defining double variable numericGrade that holds method Value

System.out.println("Numeric Value: "+numericGrade); //print Value numericgrade.

}

}

Output:

Enter Grade: B

Numeric Value: 3.0

Explanation:

In the above-given code, a class "GradePrinter" is defined inside the class a string, and double variable "grade and numericValue" is defined, in which the grade variable is used for input string value from the user end.

After input, the sting value a method getNumericGrade is defined, which uses multiple conditional statements is used, which holds double value in the which is defined in the question.

In the main class, the "GradePrinter" object is created and defines a double variable "numericGrade", that calling method and store its value, and also use print method to print its value.

4 0
2 years ago
At one college, the tuition for a full-time student is $8,000 per semester. It has been announced that the tuition will increase
inn [45]

Answer:

#include <iostream>

using namespace std;

 

int main () {

  // for loop execution

  int semester_fees=8000;

  int b=1;

  cout<<"there are 5 years or 10 semester fees breakdown is given below"<<endl;

  for( int a = 1; a <=5; a++ ) {

     semester_fees = semester_fees*1.03;

     cout<<"Semester fees for each of semester"<<b++<<"and"<<b++<<"is:$"<<semester_fees<<endl;

     

  }

 

  return 0;

}

Explanation:

code is in c++ language

Fees is incremented yearly and i have considered only two semester per year

3 0
1 year ago
In a situation where handicapped person can only input data into the computer using a stylus or light pen, which keyboard config
asambeis [7]
I think the best one is voice recognition keyboards.


Would perfect work there



Mark as brainliest
8 0
2 years ago
Read 2 more answers
Given the dictionary, d, find the largest key in the dictionary and associate the corresponding value with the variable val_of_m
geniusboy [140]

Answer:

Here is the Python program:

d = {5:3, 4:1, 12:2}

val_of_max = d[max(d.keys())]

print(val_of_max)

Explanation:

The program works as follows:

So we have a dictionary named d which is not empty and has the following key-value pairs:

5:3

4:1

12:2

where 5 , 4 and 12 are the keys and 3, 1 and 2 are the values

As we can see that the largest key is 12. So in order to find the largest key we use max() method which returns the largest key in the dictionary and we also use keys() which returns a view object i.e. the key of dictionary. So

max(d.keys()) as a whole gives 12

Next d[max(d.keys())]  returns the corresponding value of this largest key. The corresponding value is 2 so this entire statement gives 2.

val_of_max = d[max(d.keys())] Thus this complete statement gives 2 and assigns to the val_of_max variable.

Next print(val_of_max) displays 2 on the output screen.

The screenshot of program along with its output is attached.

4 0
2 years ago
Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re
aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)    

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

\bar X represent the sample mean  

\mu population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size  

2) Confidence interval

The confidence interval for the mean is given by the following formula:

\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}   (1)

In order to calculate the mean and the sample deviation we can use the following formulas:  

\bar X= \sum_{i=1}^n \frac{x_i}{n} (2)  

s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}} (3)  

The mean calculated for this case is \bar X=2.938

The sample deviation calculated s=0.472

In order to calculate the critical value t_{\alpha/2} we need to find first the degrees of freedom, given by:

df=n-1=5-1=4

Since the Confidence is 0.95 or 95%, the value of \alpha=0.05 and \alpha/2 =0.025, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that t_{\alpha/2}=2.78

Now we have everything in order to replace into formula (1):

2.938-2.78\frac{0.472}{\sqrt{5}}=2.351    

2.938+2.78\frac{0.472}{\sqrt{5}}=3.525    

So on this case the 95% confidence interval would be given by (2.351;3.525)    

5 0
2 years ago
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