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Natali5045456 [20]
1 year ago
5

In the game of $Mindmaster$, secret codes are created by placing pegs of any of seven different colors into four slots. Colors m

ay be repeated, and no slot may remain empty. How many secret codes are possible?
Computers and Technology
1 answer:
Artemon [7]1 year ago
3 0

In the game of $Mindmaster$, secret codes are created by placing pegs of any of seven different colors into four slots. Colors may be repeated, and no slot may remain empty. 2401 secret codes are possible.

<u>Explanation:</u>

Mastermind is a board game that was developed by Mordecai Meirowitz, in 1971. The Code maker sets a secret code, then the Codebreaker attempts to meet the code using logic, deduction. Behind each move, the Code maker provides hints to the Codebreaker. Make the code even more indirect by using multiple pegs of the same color or by leaving one or more peg holes empty. With so many feasible code sequences, every game is confirmed to be a brain teaser.

7 colors with 4 slots and repetition of color are accepted so 7^4 is 2401.

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Recall the problem of finding the number of inversions. As in the text, we are given a sequence of n numbers a1, . . . , an, whi
Kay [80]

Answer:

The algorithm is very similar to the algorithm of counting inversions. The only change is that here we separate the counting of significant inversions from the merge-sort process.

Algorithm:

Let A = (a1, a2, . . . , an).

Function CountSigInv(A[1...n])

if n = 1 return 0; //base case

Let L := A[1...floor(n/2)]; // Get the first half of A

Let R := A[floor(n/2)+1...n]; // Get the second half of A

//Recurse on L. Return B, the sorted L,

//and x, the number of significant inversions in $L$

Let B, x := CountSigInv(L);

Let C, y := CountSigInv(R); //Do the counting of significant split inversions

Let i := 1;

Let j := 1;

Let z := 0;

// to count the number of significant split inversions while(i <= length(B) and j <= length(C)) if(B[i] > 2*C[j]) z += length(B)-i+1; j += 1; else i += 1;

//the normal merge-sort process i := 1; j := 1;

//the sorted A to be output Let D[1...n] be an array of length n, and every entry is initialized with 0; for k = 1 to n if B[i] < C[j] D[k] = B[i]; i += 1; else D[k] = C[j]; j += 1; return D, (x + y + z);

Runtime Analysis: At each level, both the counting of significant split inversions and the normal merge-sort process take O(n) time, because we take a linear scan in both cases. Also, at each level, we break the problem into two subproblems and the size of each subproblem is n/2. Hence, the recurrence relation is T(n) = 2T(n/2) + O(n). So in total, the time complexity is O(n log n).

Explanation:

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2 years ago
"Create a Python program named detect_column_level_data_entry_errors. When complete, you will run this program to produce a diag
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Answer:

See explaination

Explanation:

Code for detect_column_level_data_entry_errors.py:

# File: detect_column_level_data_entry_errors.py

# The program will produce a diagnostic report that shows data entry errors that cause column

# totals in the data to be out of balance. Will need to fix cleaned_data.txt until errors resolved.

def main():

input_filename = input('Please enter the input filename: ')

infile = open(input_filename, 'r', encoding='utf8')

total_males = 0

total_females = 0

sum_total = 0

print('\n{0:^40}'.format('Column-Level Data Entry Errors'))

print('\n{0:<10}{1:>10}{2:>10}{3:>10}'.format(

'Age Group', 'Males', 'Females', 'Total'))

for line in infile:

age_group, males, females, total = line.split()

males = int(males)

females = int(females)

total = int(total)

print('{0:<10}{1:>10,}{2:>10,}{3:>10,}'.format(

age_group, males, females, total))

if age_group != 'Total':

total_males = males + total_males

total_females = females + total_females

sum_total = total + sum_total

else:

print('{0:<10}{1:>10,}{2:>10,}{3:>10,}'.format(

'Error', (males-total_males), (females-total_females), (total-sum_total)))

infile.close()

main()

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2 years ago
Why can a failure in a database environment be more serious than an error in a nondatabase environment?
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Failure in a database environment is more serious then a non data base because if you lose important information you may not get it back and failure in a nondatabase environment the problem may be more easier to solve
5 0
2 years ago
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Dante wants to calculate the currently monthly subtotals for the sales of golf balls in his store. Which of the following will h
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I believe the answer is B
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Mark and John are developing a program using Python. They name a variable 24_hour_mart, but then recognize that this name violat
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Answer:

Option 2: Variable names can not begin with a number.

Explanation:

As given Mark and John named a variable as 24_hour_mart while writing a program in python.

While it is forbidden to name a variable starting with any digit, only alphabets (capital and smaller) and underscore can be the first letter of the variable name.

Moreover, by considering the other options given:

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Variables named in python language must not be the keywords as they are reserved for other purposes.

i hope it will help you!

3 0
2 years ago
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