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Vinvika [58]
2 years ago
11

When conducting research, protecting the privacy of patients requires careful attention to ensure ?

Computers and Technology
2 answers:
vichka [17]2 years ago
6 0

Answer:

Connections or secure HTTP to mantain security.

Explanation:

When conducting research you should create a safe and secure connections and HTTP to mantain security of your data and the data of your patients in order to keep the donfidentiality agreement between you and your patients and the funders of your research. That is why you truly need to have a safe connecto and secure HTTP to mantain security.

Eddi Din [679]2 years ago
3 0
When conducting research, protecting the privacy of patients requires careful attention to ensure PRIVACY/CONFIDENTIALITY.
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Whoever helps me with these questions i will help them with the same number of questions in any subject: 1. As the operations ma
mezya [45]
I'm going have to go with with 1.b and 2.d hope this helps and I don't need help right now.
6 0
1 year ago
Write a fragment of code that reads in strings from standard input, until end-of-file and prints to standard output the largest
Nady [450]

Answer:

Explanation:

Sample input file: numbers.txt

8 9 7 67 78 45 67 99 1001

Sample Output:

The largest value is:1001

Code to Copy:

// include stdafx, if using visual studio.

#include "stdafx.h"

// declare the necessary header files.

#include <iostream>

#include <string>

#include <fstream>

using namespace std;

// Start the main function

int main()

{

// create the object of ifstream.

ifstream in_file;

// Open the file

in_file.open("numbers.txt");

// Declare the string variable

string str;

// Declare the integer variables.

int maximum = 0;

int num;

// Check whether the file open

if (in_file.is_open())

{

// Traverse the file till the end.

while (!in_file.eof())

{

// traversing the value.

in_file >> str;

// convert the string into integer.

num = stoi(str);

// Check whether value is max or not.

if (maximum < num)

{

// Update the value of maximum.

maximum = num;

}

}

}

// Display the statement on console.

cout << "The largest value is:" << maximum << endl;

// Close the file.

in_file.close();

system("pause");

return 0;

}

8 0
1 year ago
The maximum number of times the decrease key operation performed in Dijkstra's algorithm will be equal to ___________
katovenus [111]

Answer:

b) Single source shortest path

Explanation:

These are the options for the question

a) All pair shortest path

b) Single source shortest path

c) Network flow

d) Sorting

Dijkstra's algorithm is algorithm by

Edsger Dijkstra arround the year 1956, this algorithm determine the shortest path, this path could be between two nodes/vertice of a graph.

The steps involves are;

✓setting up of the distances base on the algorithm.

✓ calculation of the first vertice up to vertice adjacent to it

✓The shortest path result.

It should be noted that maximum number of times the decrease key operation performed in Dijkstra's algorithm will be equal to Single source shortest path.

3 0
1 year ago
Which of these tools can best be used as a self assessment for career planning purposes? a personality test an asset analysis a
Ivahew [28]

Answer:

a goal development checklist

Explanation:

8 0
1 year ago
A bank in your town updates its customers’ accounts at the end of each month. The bank offers two types of accounts: savings and
Lerok [7]

Answer:

This is your corrected code and the output of each test example. I have also added comments with the provided code to make the code understandable. I have also changed itype variable to from int to String in order to print the account type (Savings or Checking) in output.

import java.util.*;

public class bank{  //class name

public static void main (String [] args)  //start of main function body

{int num,error=1; //declare variables

String itype=" "; //stores Checking or Savings account type

char type =0;  //type variable which is one of savings S or checking C

double min,cur =0,balance =0,rate=0;

//declare variables for minimum balance, current balance, interest rate

Scanner in=new Scanner(System.in);

System.out.println("Enter account number: ");  //prompts user to enter acc no

num=in.nextInt();  //reads input account number

while(error==1) {  

//asks user to enter account type C or S

System.out.println("Enter account type(s-savings or c-checking):");

type=in.next().charAt(0);  //reads the input character of account type

if(type=='c'||type=='C')  //if user inputs c or C

{itype= "Checking";  //set itype to Checking when user input c or C

error=0;  //set value of error to 0 means user entered valid type input

rate=3/100.; }  // Savings accounts receives  3% interest

else if(type=='s'||type=='S')  //if user enters S or s that shows Savings account

{itype= "Savings";  //set itype to Savings when user input s or S

error=0;  //set error to 0 means there is no error

rate=4/100.; }  //Savings accounts receives 4% interest

if(error==1)  //in case of error in giving input

System.out.println("Invalid type-re enter"); }  //asks user to input again

System.out.println("Enter minimum balance: ");  //asks user to enter min bal

min=in.nextDouble();  //reads value of input minimum balance

System.out.println("Enter current balance: ");

// reads value of input current balance

cur=in.nextDouble();

balance = cur;  

if(itype=="Checking") //if the account type is checking

{ if(cur>min+5000) //Checking accounts interest is 5%

{rate=5/100.;

cur=cur+rate*cur; //computes new balance

System.out.printf("New balance: $%.2f\n", cur);} //returns new balance value

/*If a customer’s balance falls below the minimum balance, there is a service charge of $25.00 for checking accounts */

else if(cur<min)

{cur-=25;

System.out.printf("New balance: $%.2f\n", cur);} returns the value of new

}

if(itype=="Savings"){ //if account type is Savings

/*If a customer’s balance falls below the minimum balance, there is a service charge of $10.00 for savings accounts */

if(cur<min)

{cur-=10;

System.out.printf("New balance: $%.2f\n", cur);}

else

//Savings accounts receive 4% interest

{cur=cur+rate*cur;

System.out.printf("New balance: $%.2f\n", cur);}}

/* as the program should output account number, account type, current balance, and new balance so i have commented out the extra print statements below */

//System.out.printf("After interest and fees your balance is = $%.2f\n",cur);

System.out.println("Account Number: " + num);

System.out.println("Account type: " + itype);

System.out.printf("Current balance: $%.2f\n ", balance);  //the result is //displayed up to 2 decimal place .2f   } }

Explanation:

Following is the output of each test example:

46728 S 1000 2700

Account Number: 46728                                            

Account type: Savings                                                                                          

Current balance: $2700.00                                                                                

New balance: $2808.00

87324 C 1500 7689

Account Number: 87324                                                                                      

Account type: Checking                                                                                        

Current balance: $7689.00                                                                                  

New balance: $8073.45

79873 S 1000 800

Account Number: 79873                                                                                    

Account type: Savings                                                                                        

Current balance: $800.00  

New balance: $790

89832 C 2000 3000

Account Number: 89832                                                                                      

Account type: Checking                                                                                        

Current balance: $3000.00                                                                                  

New balance: $3090.00

98322 C 1000 750  

Account Number: 98322

Account Type: Checking  

Current balance: $1000.00

New Balance: $725.00

7 0
2 years ago
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