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1 year ago

Explain the emerging trends in microcomputer technology in relation to size

Computers and Technology

1 answer:

n200080 [17]1 year ago

4 0

Answer:

The answer to this question is given below in the explanation section.

Explanation:

"emerging trends in microcomputer technology"

At International data corporation we do market and competitive analysis for both vendors and users of information processing equipment. Therefore,when i look at where the technology has been and where it is going.I see it from two views point where the industry is moving and how well users are adapting to the changes,But from both view point the movement can be summarized in three words faster smaller and cheaper.

It may be helpful to think in terms of micro computer life cycle.The first is hard were introduction during which time users have the opportunity to review hardware capabilities.The second phase is response to that original debut whatever it attracts peripheral vendors of hardware and stimulate software development that provide a wide and rich work development.No corporation not even IBM can stand alone in this marketplace.All need the diversity of the expansion board vendors,the software vendors,the whole new industry that the emerged over the last few years.

In this first stage we dealt with the personal computer as an individual workstation,as an independent processing unit rather than as a part of larger organizational framework.We also had to deal with the whole all of shared peripherals,secondary to whatever unit was on the desk.

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Use the loop invariant (I) to show that the code below correctly computes the product of all elements in an array A of n integer

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Given Loop Variant P = a[0], a[1] ... a[i]

It is product of n terms in array

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The Basic Step: i = 0, loop invariant p=a[0], it is true because of 'p' initialized as a[0].

Induction Step: Assume that for i = n - 3, loop invariant p is product of a[0], a[1], a[2] .... a[n - 3].

So, after that multiply a[n - 2] with p, i.e P = a[0], a[1], a[2] .... a[n - 3].a[n - 2].

After execution of while loop, loop variant p becomes: P = a[0], a[1], a[2] .... a[n -3].a[n -2].

for the case i = n-2, invariant p is product of a[0], a[1], a[2] .... a[n-3].a[n-2]. It is the product of (n-1) terms. In while loop, incrementing the value of i, so i=n-1

And multiply a[n-1] with p, i.e P = a[0].a[1].a[2].... a[n-2].

a[n-1]. i.e. P=P.a[n-1]

By the assumption for i=n-3 loop invariant is true, therefore for i=n-2 also it is true.

By induction method proved that for all n > = 1 Code will return product of n array elements.

While loop check the condition i < n - 1. therefore the conditional statement is n - i > 1

If i = n , n - i = 0 , it will violate condition of while loop, so, the while loop will terminate at i = n at this time loop invariant P = a[0].a[1].a[2]....a[n-2].a[n-1]

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Explain the emerging trends in microcomputer technology in relation to size​

Explain the emerging trends in microcomputer technology in relation to size