Answer:
The true statements are:
There is an assembler directive to arrange / place floating point values in static data memory
MARS always uses setting '.set boat'
Explanation:
It is the assembler directive who arranges and places the floating point values for the static data memory. Obviously there is no such way for the MIPS assemble programming for reservation of the static data memory without having any initialization for a considerable value.
MARS would definitely use the setting set “noat” ascii would store the string in the memory and then terminate it with respect to NULL character. They cannot reserve the MIPS assembly programming for a considerable value.
Answer:
=IF((D5="Yes"),(C4*1.05),C4)
Explanation:
If condition accepts 3 parameters, where the 1st parameter is the condition and second parameter is the one which needs to be executed “if the condition is true” and the third argument is executed when the “condition is false”.
Here the condition is if there is an delivery ie. D5 = yes, then we add some amount of additional charges through the formula (c4*1.05) and if not we retain the base price C4.
Here the additional delivery charges are considered as 5%. You can change the number according to your need.
Answer:
The data can be safeguarded using key escrow procedure.
Explanation:
Key escrow basically means to store the cryptographic key in an "escrow" by a reputable trusted third party. The copy of the encryption key is kept with the third party. In case the cryptographic key gets lost or destroyed, then the key escrow service helps to access the encrypted data. It also manages the access control to the key in case the key gets lost. So this way in case of security breach at GearOn the key escrow service can be used to re-implement or access the key easily.
Answer:
C++ code is given below
Explanation:
#include<iostream>
#include <cstring>
using namespace std;
int housekeeping(string EOFNAME);
int mainLoop(string name,string EOFNAME);
int finish();
void main()
{
string name;
string EOFNAME = "ZZZZ";
cout << "enter the name" << endl;
cin >> name;
if (name != EOFNAME)
{
housekeeping(EOFNAME);
}
if (name != EOFNAME)
{
mainLoop(name , EOFNAME);
}
if (name != EOFNAME)
{
finish();
}
system("pause");
}
int housekeeping(string EOFNAME)
{
cout << "enter first name " << EOFNAME << " to quit " << endl;
return 0;
}
int mainLoop(string name, string EOFNAME)
{
int hours;
int rate,gross;
int DEDUCTION = 45;
int net;
cout << "enter hours worked for " << name << endl;
cin >> hours;
cout << "enter hourly rate for " << name << endl;
cin >> rate;
gross = hours*rate;
net = gross - DEDUCTION;
if (net > 0)
{
cout << "net pay for " << name << " is " << net << endl;
}
else
{
cout << "dedections not covered.net is 0.";
}
cout << "enter next name or " << EOFNAME << " to quit" << endl;
cin >> name;
return 0;
}
int finish()
{
cout << "end of job"<<endl;
return 0;
}
Answer:
def max_magnitude(user_val1, user_val2):
if abs(user_val1) > abs(user_val2):
return user_val1
else:
return user_val2
if __name__ == '__main__':
n1 = int(input("Enter the first integer number: "))
n2 = int(input("Enter the second integer number: "))
print("The largest magnitude value of", n1, "and", n2, "is", max_magnitude(n1, n2))
Explanation:
