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2 years ago

Which statement regarding dialogues in multiplayer games is true? Dialogues are based only on players’ actions.

Computers and Technology

2 answers:

emmainna [20.7K]2 years ago

8 0

D. Dialogues are based only on events that have occurred in the game.

Paladinen [302]2 years ago

3 0

D the dialogue will change based on what you do in the game

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Hi!

The Clipboard in Microsoft Word is great for having more than just one paste option via the paste command.

Using the Clipboard, you can hold up to 24 items that are copied. This makes it efficient if you have a lot of data you would like to paste.

Hopefully, this helps! =)

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2 years ago

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Match each function with its possible output.

mojhsa [17]

1.) B
2.) A
3.) D
4.) C
rand command returns a random number sqrt is going to return a decimal unless its a perfect square however the rand will not the now is quite obvious because it gives a time and date, while the other simply gives the date.

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2 years ago

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Program MATH_SCORES: Your math instructor gives three tests worth 50 points each. You can drop one of the test scores. The final

Simora [160]

Answer:

import java.util.Scanner;

public class num5 {

public static void main(String[] args) {

Scanner in = new Scanner(System.in);

//Prompt and receive the three Scores

int score1;

int score2;

int score3;

do {

System.out.println("Enter first Score Enter score between 1 -50");

score1 = in.nextInt();

} while(score1>50 || score1<0);

do {

System.out.println("Enter second Score.The second score must be between 1 -50");

score2 = in.nextInt();

} while(score2>50 || score2<0);

do {

System.out.println("Enter Third Score Third score must between 1 -50");

score3 = in.nextInt();

} while(score3>50 || score3<0);

//Find the minimum of the three to drop

int min, min2, max;

if(score1<score2 && score1<score3){

min = score1;

min2 = score2;

max = score3;

}

else if(score2 < score1 && score2<score3){

min = score2;

min2 = score1;

max = score3;

}

else{

min = score3;

min2 = score1;

max = score2;

}

System.out.println("your entered "+max+", "+min2+" and "+min+" the min is");

int total = max+min2;

System.out.println("Total of the two highest is "+total);

//Finding the grade based on the cut-off points given

if(total>=90){

System.out.println("Grade is A");

}

else if(total>=80){

System.out.println("Grade is B");

}

else if(total>=70){

System.out.println("Grade is C");

}

else if(total>=60){

System.out.println("Grade is D");

}

else{

System.out.println("Grade is F");

}

Explanation:

Implemented with Java
Use the scanner class to receive user input
Use a do.....while loop to validate user input for each of the variables. A valid score must be between 0 and 50 while(score>50 || score<0);
Use if and else to find the minimum of the three values and drop
Add the two highest numbers
use if/else if /else statements to print the corresponding grade

8 0

2 years ago

Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:

horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0

2 years ago

Ming is building an inexpensive computer to use for her online classes, and needs to purchase Windows. What is the most cost-eff

kodGreya [7K]

The correct answer is; She can purchase OEM codes from e-commerce sites such as Amazon or eBay.

Further Explanation:

There are some sites where OEM codes cost around 110$ or higher. it will depend on which edition of Windows she plans on purchasing. The official Microsoft website sells the codes for much higher than other e-commerce sites.

There is some ways to get the older Windows for free online using a software key from a previous purchase from a friend or one you have purchased in the past. There is also a free trial that can be used for 7 days and possibly 30 days.

Learn more about Windows at brainly.com/question/1705478

#LearnwithBrainly

5 0

2 years ago