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HACTEHA [7]
2 years ago
8

Consider a DASH system for which there are N video versions (at N different rates and qualities) and N audio versions (at N diff

erent rates and qualities). Suppose we want to allow the player to choose at any time any of the N video versions and any of the N audio versions. a. If we create files so that the audio is mixed in with the video, so server sends only one media stream at given time, how many files will the server need to store (each a different URL)? b. If the server instead sends the audio and video streams separately and has the client synchronize the streams, how many files will the server need to store?
Computers and Technology
1 answer:
Ksju [112]2 years ago
5 0

Answer: a) N² files. b) 2N files.

Explanation:

If an user can choose freely both the video and the audio quality, if they are stored separately, but the user can download any mix of them as a single file, the server must store one audio version for each video version, so it will need to store NxN = N² files.

If, instead, the server can send the audio and video streams separately, so the user can choose one of the N videos available, and one of the N audio versions, the server will need to store only N video files + N audio audio files, i.e. , 2 N files.

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John works for Internal Computer Specialists, which focuses on helping small business owners resolve MIS infrastructure issues.
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Answer:

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Poor quality lateral communication will result in which ofthe
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b

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Lynn runs the locate command and the results include many files from a directory that she doesn't want to include in her search.
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C) /etc/updatedb.conf

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2 years ago
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Write a program to input value of three sides, to check triangle is triangle is possible to form of not​
NeTakaya

Answer:

Explanation:

import java.util.Scanner;

public class KboatTriangleAngle

{

  public static void main(String args[]) {

      Scanner in = new Scanner(System.in);

      System.out.print("Enter first angle: ");

      int a1 = in.nextInt();

      System.out.print("Enter second angle: ");

      int a2 = in.nextInt();

      System.out.print("Enter third angle: ");

      int a3 = in.nextInt();

      int angleSum = a1 + a2 + a3;

       

      if (angleSum == 180 && a1 > 0 && a2 > 0 && a3 > 0) {

          if (a1 < 90 && a2 < 90 && a3 < 90) {

              System.out.println("Acute-angled Triangle");

          }

          else if (a1 == 90 || a2 == 90 || a3 == 90) {

              System.out.println("Right-angled Triangle");

          }

          else {

              System.out.println("Obtuse-angled Triangle");

          }

      }

      else {

          System.out.println("Triangle not possible");

      }

  }

}

OUTPUT:

3 0
2 years ago
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