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nikklg [1K]
2 years ago
10

The elements of an integer-valued array can be initialized so that a[i] == i in a recursive fashion as follows: An array of size

0 is already initialized; Otherwise set the last element of the array to n-1 (where n is the number of elements in the array, for example, an array of size 3 will have its last element -- index 2-- set to 2; and initialize the portion of the array consisting of the first n-1 elements (i.e., the other elements of the array) Write a void method named init that accepts an integer array, and the number of elements in the array and recursively initializes the array so that a[i] == i.
Computers and Technology
1 answer:
blondinia [14]2 years ago
4 0

Answer:

public static void init(int[] arr, int n) {

    if (n==0)

        arr[0] = 0;

    else {

        arr[n-1] = n - 1;

        init(arr, n-1);

    }

}

Explanation:

Create a method called init that takes two parameters, an array and the number of elements in the array

When n reaches 0, set the first element to 0 (This is a base for our recursive method)

Otherwise, set the element in index i to i

Call the init inside the init, this is the recursion part, with same array but decrease the number of elements by 1 (We decrease the number of element by 1 in each time so that it goes through all the elements in the array)

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A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info
Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

7 0
2 years ago
Object-oriented development could potentially reduce the time and cost of writing software because: Group of answer choices a) i
spayn [35]

Answer:

b) objects are resuable

Explanation:

In OOP there's code reuse where a method or any other body of code is defined once and called or reused severally.

3 0
2 years ago
Consider the following classes:
aleksandrvk [35]

Answer:

The answer is toy

Explanation:

I think toy is the odd one out

4 0
2 years ago
In the graph shown here, by what percentage are the number of people in computer occupations in general projected to increase?
SOVA2 [1]

Answer:

12% or 21%

Explanation:

not really sure

8 0
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Read 2 more answers
What is retrieved from a search containing two terms separated<br> by the AND operator?
egoroff_w [7]

Answer:

A AND B= 1 or 0

1 1  1

0 1  0

1 0  0

0 0 0

So, as explained above if both are 1 we then only get 1, or else we get 0 always in case of AND which is a logical operator, whose output can be 0 or 1 only. This is being depicted above.

Explanation:

If both are 1 we get 1 or always else, we get the output =0.

8 0
2 years ago
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