Answer:
Miguel y Maru están muy cansados. - Miguel y Maru están cansadísimos
Felipe es muy joven. - Felipe es jovencísimo
Jimena es muy inteligente. - Jimena es inteligentísima
La madre de Marissa está muy contenta. - La madre de Marissa está contentísima
Estoy muy aburrido. - Estoy aburridísimo
Explanation:
In this activity we have to switch the statements to the absolute superlative of the expressions. In Spanish we can add the suffix -ísimo to an adjective to refer to the highest degree of something. It can be translated in ENglish to "really, extremely, super or quie". The statements in English are:
- Miguel and Maru are very tired - Miguel and Mary are extremely tired
- Felipe is very young - Felipe is super young
- Jimena is very smart - Jimena is really smart
- Marissa´s mother is very happy - Marissa´s mother is extremely happy
- I´m very bored - I´m super bored
The correct answer is A. Familiar words for clues
Explanation:
Finding unfamiliar words is common while reading, especially in texts that belong to a specific field such as medicine, technology, etc. This can be handled through multiple strategies such as using a dictionary, guessing the meaning of the word based on its parts, and using context clues.
In this context, one of the easiest and most time-saving strategy is the use of context clues that implies using the familiar words as clues to guess the meaning of an unfamiliar word. This is effective because in most cases the meaning of an unknown word can be determined using the context of the word or words around the unknown word. Also, this strategy takes little time because you only need to analyze the sentence or paragraph where the unknown word is. Thus, the time-saving strategy to define unfamiliar words involves using familiar words for clues.
Answer:
// here is code in C++
#include <bits/stdc++.h>
using namespace std;
// main function
int main()
{
// variables
int n,no_open=0;
cout<<"enter the number of lockers:";
// read the number of lockers
cin>>n;
// initialize all lockers with 0, 0 for locked and 1 for open
int lock[n]={};
// toggle the locks
// in each pass toggle every ith lock
// if open close it and vice versa
for(int i=1;i<=n;i++)
{
for(int a=0;a<n;a++)
{
if((a+1)%i==0)
{
if(lock[a]==0)
lock[a]=1;
else if(lock[a]==1)
lock[a]=0;
}
}
}
cout<<"After last pass status of all locks:"<<endl;
// print the status of all locks
for(int x=0;x<n;x++)
{
if(lock[x]==0)
{
cout<<"lock "<<x+1<<" is close."<<endl;
}
else if(lock[x]==1)
{
cout<<"lock "<<x+1<<" is open."<<endl;
// count the open locks
no_open++;
}
}
// print the open locks
cout<<"total open locks are :"<<no_open<<endl;
return 0;
}
Explanation:
First read the number of lockers from user.Create an array of size n, and make all the locks closed.Then run a for loop to toggle locks.In pass i, toggle every ith lock.If lock is open then close it and vice versa.After the last pass print the status of each lock and print count of open locks.
Output:
enter the number of lockers:9
After last pass status of all locks:
lock 1 is open.
lock 2 is close.
lock 3 is close.
lock 4 is open.
lock 5 is close.
lock 6 is close.
lock 7 is close.
lock 8 is close.
lock 9 is open.
total open locks are :3
Microsoft Online is free to use. It includes Microsoft Excel, Word, One - Note and PowerPoint. Microsoft Outlook (email app) is free as well, although it is a seperate download.
Another way to go is via Google docs, The Google drive is rather large and safe to store reports, docs, images, etc.
Both Microsoft online and Google Docs are accessible to use on virtually any device as in: PCs, Laptops, Tablets, Androids and Iphones.
Answer:
Text watermarking involves adding the photographer's name at the corner of the image.
Explanation:
This was one of the correct answers when I took the test, I got it wrong because I didn't pick all the correct answers. I hope that this was helpful to you! If you know the other correct answer(s) please comment and let me know and i'll edit this answer! :)
