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astraxan [27]
2 years ago
11

Information systems cannot solve some business problems. Give three examples and explain why technology cannot help.

Computers and Technology
1 answer:
artcher [175]2 years ago
6 0

Answer:

1. cant make decision on its own

2. Can't feed data on its own

3. cant help in saving cost

Explanation:

a.

Systme cannot make decision:- Information system can only provide data in a way so that analysis can be done. But system cannot take a business decision on its on. It requires experience and knowledge of how to use the data available.

b.

System Cannot feed data on its own:- System cannot make reports and customize them as per the situation need. This has to be done manually.

c.

Information system cannot help in cost saving:- For this Humans are required to identify the areas of opportunities and to act on it.

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The number of operations executed by algorithms A and B is 40n2 and 2n3, respectively. Determine n0 such that A is better than B
Tom [10]

Answer:

Given that:

A= 40n^2

B = 2n^3

By given scenario:

40n^2=2n^3

dividing both sides by 2

20n^2=n^3

dividing both sides by n^2 we get

20 = n

Now putting n=20 in algorithms A and B:

A=40n^2

= 40 (20)^2

= 40 * (400)

A= 16000

B= 2n^3

= 2 (20)^3

= 2(8000)

B= 16000

Now as A and B got same on n = 20, then as given:

n0 <20 for n =20

Let us take n0 = 19, it will prove A is better than B.

We can also match the respective graphs of algorithms of A and B to see which one leads and which one lags, before they cross at n= 20.

8 0
2 years ago
Determining the Services Running on a Network Alexander Rocco Corporation has multiple OSs running in its many branch offices. B
Sladkaya [172]

Answer: provided in the explanation section

Explanation:

 Network’s vulnerabilities:

           Vulnerability is a weak spot in your network that might be exploited by a security threat. Risks are the potential consequences and impacts of unaddressed vulnerabilities. In other words, failing to do Windows Updates on your Web server is vulnerability.

           Regularly scheduled network vulnerability scanning can help an organization identify weaknesses in their network security before the bad guys can mount an attack. The goal of running a vulnerability scanner or conducting an external vulnerability assessments is to identify devices on your network that are open to known vulnerabilities without actually compromising your systems.

           The overall objective of a Vulnerability Assessment is to scan, investigate, analyze and report on the level of risk associated with any security vulnerabilities discovered on the public, internet-facing devices and to provide your organization with appropriate mitigation strategies to address those discovered vulnerabilities.

         

Network topology issues:

Coverage Topology

           Coverage problem reflects how well an area is monitored or tracked. The coverage and connectivity problems in networks have received considerable attention in the research community in recent years

 

Geographic routing

           Geographic routing uses geographic and topological information of the network to achieve optimal routing schemes with high routing efficiency and low power consumption

Port Numbers

           Port Numbers While IP addresses determine the physical endpoints of a network connection, port numbers determine the logical endpoints of the connection. Port numbers are 16-bit integers with a useful range from 1 to 65535.

Port numbers are assigned by an organization called IANA and ports are allocated to various needs to avoid confusion.

Ports are classified into 3 main categories.

Well Known Ports (Port numbers 0 - 1023)

           In a client-server application, the server usually provides its service on a well-known port number. Well-known port numbers are a subset of the numbers which are assigned to applications. According to RFC1700 [5], well-known port numbers are managed by the Internet Assigned Numbers Authority (IANA). They used to be in the range from 1 to 255, but in 1992 the range was increased up to 1023.

Registered Ports (Port numbers1024 - 49151)

Such ports are used by programs run by users in the system.

           In addition to the well-known ports below 1024 there are more port numbers assigned to applications but are located anywhere from 1024 to 65535.

Private or Dynamic Ports (Port numbers 49152 - 65535)

           Private ports are not assigned for any specific purpose.

         

Discuss the concepts of well-known ports and give a brief description of the most commonly used ports: 20, 21, 23, 25, 53, and 110.

Commonly Used Port Numbers

The following port numbers are unofficial list of commonly used for linux/unix based servers.

         

20&21               TCP                FTP (File server protocol)

           FTP is one of the most commonly used file transfer protocols on the Internet and within private networks. An FTP server can easily be set up with little networking knowledge and provides the ability to easily relocate files from one system to another. FTP control is handled on TCP port 21 and its data transfer can use TCP port 20 as well as dynamic ports depending on the specific configuration.

23                   TCP/UDP          Telnet

           Telnet is the primary method used to manage network devices at the command level. Unlike SSH which provides a secure connection, Telnet does not, it simply provides a basic unsecured connection. Many lower level network devices support Telnet and not SSH as it required some additional processing. Caution should be used when connecting to a device using Telnet over a public network as the login credentials will be transmitted in the clear.

25                   TCP/UDP         SMTP   (for sending outgoing emails)

           SMTP is used for two primary functions, it is used to transfer mail (email) from source to destination between mail servers and it is used by end users to send email to a mail system.

53         TCP/UDP        DNS Server (Domain name service for DNS request)

           The DNS is used widely on the public internet and on private networks to translate domain names into IP addresses, typically for network routing. DNS is hieratical with main root servers that contain databases that list the managers of high level Top Level Domains (TLD) (such as .com). T

110             TCP                 POP3 (For receiving emails)

           POP version 3 is one of the two main protocols used to retrieve mail from a server. POP was designed to be very simple by allowing a client to retrieve the complete contents of a server mailbox and then deleting the contents from the server.

4 0
2 years ago
A ______________ deals with the potential for weaknesses within the existing infrastructure to be exploited.
algol [13]

Answer:

Threat assessment

Explanation:

A threat assessment deals with the potential for weaknesses within the existing infrastructure to be exploited.

Threat Assessment is further explained as the practice of determining or ascertaining the credibility and seriousness of a potential threat, and also the probability or chases of the threat will becoming a reality.

Threat assessment is separate to the more established procedure of violence-risk assessment, which seek to forcast an individual's general capacity and tendency to respond to situations violently. Instead, threat assessment aims to interrupt people on a route to commit "predatory or instrumental violence, the type of behavior connected with targeted attacks".

3 0
2 years ago
Read 2 more answers
Assign max_sum with the greater of num_a and num_b, PLUS the greater of num_y and num_z. Use just one statement. Hint: Call find
Gnoma [55]

Answer:

def find_max(num_1, num_2):

   max_val = 0.0

   if (num_1 > num_2): # if num1 is greater than num2,

       max_val = num_1 # then num1 is the maxVal.

   else: # Otherwise,

       max_val = num_2 # num2 is the maxVal

   return max_val

max_sum = 0.0

num_a = float(input())

num_b = float(input())

num_y = float(input())

num_z = float(input())

max_sum = find_max(num_a, num_b) + find_max(num_y, num_z)

print('max_sum is:', max_sum)

Explanation:

I added the missing part. Also, you forgot the put parentheses. I highlighted all.

To find the max_sum, you need to call the find_max twice and sum the result of these. In the first call, use the parameters num_a and num_b (This will give you greater among them). In the second call, use the parameters num_y and num_z (This will again give you greater among them)

5 0
2 years ago
Information is stored on a compact disk in a coded pattern of tiny pits arranged in a track that spirals outward toward the rim
Maksim231197 [3]

Answer:

(i) The rotation speed must stay the same.

(ii) The rotation speed must increase.

(iii) The rotation speed must decrease.

Explanation:

According to Equation

10.10, the angular speed must therefore vary as the laser–lens system moves

radially along the disc. In a typical CD player, the constant speed of the surface at

the point of the laser–lens system is 1.3 m/s.

5 0
2 years ago
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