Which feature of Badoo helped members make their profile more prominent?

A school has 100 lockers and 100 students. All lockers are closed on the first day of school. As the students enter, the first s

kati45 [8]

Solution :

public class NewMain {

public_static void main_(String[] args) {

boolean[] _locker = new boolean_[101];

// to set all the locks to a false NOTE: first locker is the number 0. Last locker is the 99.

for (int_i=1;i<locker_length; i++)

{

locker[i] = false;

}

// first student opens all lockers.

for (int i=1;i<locker.length; i++) {

locker[i] = true;

}

for(int S=2; S<locker.length; S++)

{

for(int k=S; k<locker.length; k=k+S)

{

if(locker[k]==false) locker[k] = true;

else locker[k] = false;

}

for(int S=1; S<locker.length; S++)

{

if (locker[S] == true) {

System.out.println("Locker " + S + " Open");

}

/* else {

System.out.println("Locker " + S + " Close");

} */

}

5 0

1 year ago

List at least six things you would check for if you were asked to evaluate the workspace of an employee for ergonomics

Evgen [1.6K]

Assessing the risk that surrounds stationary work of employees spending hours at their stations is essential. Below is a list of fundamental ergonomic principles that help identify ergonomic risk factors.

1. Are the employees maintained in a neutral posture?

2. Does the stationery allow for movement and stretching?

3. Is there adequate lighting?

4. Are chairs adequately adjustable?

5. Are there appropriate foot rest?

6. Is there extra storage for better desk organization?

0 0

2 years ago

You are describing the boot process to a friend and get to the step where the device loads the operating files into RAM, includi

EastWind [94]

I would say, "not those kinds of kernels, when I say kernel, I mean the core of your computers operating system. It controls all of the system components and tell specific parts of the computer to do certain things." or in more compact terms, "think of the kernel as the brain of the computer, telling each system component what to do."

5 0

2 years ago

Generating a signature with RSA alone on a long message would be too slow (presumably using cipher block chaining). Suppose we c

boyakko [2]

Answer:

Following are the algorithm to this question:

Explanation:

In the RSA algorithm can be defined as follows:

In this algorithm, we select two separate prime numbers that are the "P and Q", To protection purposes, both p and q combines are supposed to become dynamically chosen but must be similar in scale but 'unique in length' so render it easier to influence. Its value can be found by the main analysis effectively.

Computing N = PQ.

In this, N can be used for key pair, that is public and private together as the unit and the Length was its key length, normally is spoken bits. Measure,

$\lambda (N) = \ lcm( \lambda (P), \lambda (Q)) = \ lcm(P- 1, Q - 1)$ where $\lambda$ is the total function of Carmichaels. It is a privately held value. Selecting the integer E to be relatively prime from $1$ and $gcd(E, \lambda (N) ) = 1;$ that is $E \ \ and \ \ \lambda (N)$ . D was its complex number equivalent to E (modulo $\lambda (N)$ ); that is d was its design multiplicative equivalent of E-1.

It's more evident as a fix for d provided of DE ≡ 1 (modulo $\lambda (N)$ ).E with an automatic warning latitude or little mass of bigging contribute most frequently to 216 + 1 = 65,537 more qualified encrypted data.

In some situations it's was shown that far lower E values (such as 3) are less stable.

E is eligible as a supporter of the public key.

D is retained as the personal supporter of its key.

Its digital signature was its module N and the assistance for the community (or authentication). Its secret key includes that modulus N and coded (or decoding) sponsor D, that must be kept private. P, Q, and $\lambda (N)$ will also be confined as they can be used in measuring D. The Euler totient operates $\varphi (N) = (P-1)(Q - 1)$ however, could even, as mentioned throughout the initial RSA paper, have been used to compute the private exponent D rather than λ(N).

It applies because $\varphi (N)$ , which can always be split into $\lambda (N)$ , and thus any D satisfying DE ≡ 1, it can also satisfy (mod $\lambda (N)$ ). It works because $\varphi (N)$ , will always be divided by $\varphi (N)$ ,. That d issue, in this case, measurement provides a result which is larger than necessary (i.e. D > $\lambda (N)$ ) for time - to - time). Many RSA frameworks assume notation are generated either by methodology, however, some concepts like fips, 186-4, may demand that D< $\lambda (N)$ . if they use a private follower D, rather than by streamlined decoding method mostly based on a china rest theorem. Every sensitive "over-sized" exponential which does not cooperate may always be reduced to a shorter corresponding exponential by modulo $\lambda (N)$ .

As there are common threads (P− 1) and (Q – 1) which are present throughout the $N-1 = PQ-1 = (P -1)(Q - 1)+ (P-1) + (Q- 1))$ , it's also possible, if there are any, for all the common factors $(P -1) \ \ \ and \ \ (Q - 1)$ to become very small, if necessary.

Indication: Its original writers of RSA articles conduct their main age range by choosing E as a modular D-reverse (module $\varphi (N)$ ) multiplying. Because a low value (e.g. 65,537) is beneficial for E to improve the testing purpose, existing RSA implementation, such as PKCS#1, rather use E and compute D.

8 0

2 years ago

Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re

aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=2.938$

The sample deviation calculated $s=0.472$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.78$

Now we have everything in order to replace into formula (1):

$2.938-2.78\frac{0.472}{\sqrt{5}}=2.351$

$2.938+2.78\frac{0.472}{\sqrt{5}}=3.525$

So on this case the 95% confidence interval would be given by (2.351;3.525)

5 0

2 years ago