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Blababa [14]
1 year ago
11

Create a program named Auction that allows a user to enter an amount bid on an online auction item. Include three overloaded met

hods that accept an int, double, or string bid. Each method should display the bid and indicate whether it is over the minimum acceptable bid of $10. If the bid is greater than or equal to $10, display Bid accepted. If the bid is less than $10, display Bid not high enough. If the bid is a string, accept it only if one of the following is true: It is numeric and preceded with a dollar sign. It is numeric and followed by the word dollars. Otherwise, display a message that says Bid was not in correct format. Grading When you have completed your program, click the Submit button to record your score.
Computers and Technology
1 answer:
Olin [163]1 year ago
3 0

Answer:

Explanation:

The following code is written in Java and creates the overloaded methods as requested. It has been tested and is working without bugs. The test cases are shown in the first red square within the main method and the output results are shown in the bottom red square...

class Auction {

   public static void main(String[] args) {

       bid(10);

       bid(10.00);

       bid("10 dollars");

       bid("$10");

       bid("150 bills");

   }

   public static void bid(int bid) {

       if(bid >= 10) {

           System.out.println("Bid Accepted");

       } else {

           System.out.println("Bid not high enough");

       }

   }

   public static void bid(double bid) {

       if(bid >= 10) {

           System.out.println("Bid Accepted");

       } else {

           System.out.println("Bid not high enough");

       }

   }

   public static void bid(String bid) {

       if (bid.charAt(0) == '$') {

           if (Integer.parseInt(bid.substring(1, bid.length())) > 0) {

               System.out.println("Bid Accepted");

               return;

           } else {

               System.out.println("Bid not in correct Format");

               return;

           }

       }

       int dollarStartingPoint = 0;

       for (int x = 0; x < bid.length(); x++) {

           if (bid.charAt(x) == 'd') {

               if (bid.substring(x, x + 7).equals("dollars")) {

                   dollarStartingPoint = x;

               } else {

                   break;

               }

           }

       }

       if (dollarStartingPoint > 1) {

           if (Integer.parseInt(bid.substring(0, dollarStartingPoint-1)) > 0) {

               System.out.println("Bid Accepted");

               return;

           } else {

               System.out.println("Bid not in correct format");

               return;

           }

       } else {

           System.out.println("Bid not in correct format");

           return;

       }

   }

}

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Answer:

The advantage for the above condition is as follows:-

Explanation:

  • If a user creates a defined constant variable and assigns a value on its and then uses that variable instead of the value, then it will a great advantage.
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Which of the following statements regarding critical paths is true? a. On a specific project, there can be multiple critical pat
iVinArrow [24]

Answer:

Option a

Explanation:

The Critical Path Method is the arrangement of booked exercises that decides the term of the task. These planned exercises must be performed if the venture is to be viewed as a triumph.

Therefore, options b, c, d and e can't be true because:

b. Activities in the Critical Path Method has no or zero slack.

c. The duration of the critical path in CPM determined on the basis of the latest activity and the earliest initiation.

d. The CPM method schedules the activity of the longest duration.

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2 years ago
Constantine forms the following hypothesis. Let n be any non-negative number that meets the following condition: when n is divid
notka56 [123]

Answer:

n=5

Explanation:

if n= 5

i.     n/5=5/5=1  so it divides completely the remainder is 0

ii.  97 - 6(5) = 97 - 30 = 67,   67 is a prime number.

8 0
2 years ago
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
2 years ago
Write a method printShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, prin
iogann1982 [59]

Answer:

import java.util.Scanner;

public class nu3 {

   public static void main(String[] args) {

       Scanner in = new Scanner(System.in);

       System.out.println("Enter number of cycles");

       int numCycles = in.nextInt();

       //Call the method

       printShampooInstructions(numCycles);

   }

   public static void printShampooInstructions(int numCycles){

                if (numCycles<1){

              System.out.println("Too few");

          }

          if (numCycles>4){

              System.out.println("Too Many");

          }

          else {

              for (int i = 1;i <= numCycles; i++) {

                  System.out.println( numCycles+ ": Lather and rinse");

                  numCycles--;

              }

              System.out.println("     Done");

          }

   }

}

Explanation:

This is solved using Java programming language

The method printShampooInstructions() is in bold in the answer section

I have also provided a complete program that request user to enter value for number of cycles, calls the method and passes that value to it

The logic here is using if .... else statements to handle the different possible values of Number of cycles.

In the Else Section a loop is used to decrementally print the number of cycles

4 0
2 years ago
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