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earnstyle [38]
1 year ago
10

A school has 100 lockers and 100 students. All lockers are closed on the first day of school. As the students enter, the first s

tudent, denoted S1, opens every locker. Then the second student, S2, begins with the second locker, denoted L2, and closes every other locker (i.e. every even numbered locker). Student S3 begins with the third locker and changes every third locker (closes it if it was open, and opens it if it was closed). Student S4 begins with locker L4 and changes every fourth locker. StudentS5 starts with L5 and changes every fifth locker, and so on, until student S100 changes L100.After all the students have passed through the building and changed the lockers, which lockers areopen? Write a program to find your answer.(Hint: Use an array of 100 boolean elements. each of which indicates whether a locker is open (true) or closed (false). Initially, all lockers are closed.)
Computers and Technology
1 answer:
kati45 [8]1 year ago
5 0

Solution :

public class NewMain {  

   public_static void main_(String[] args) {  

       boolean[] _locker = new boolean_[101];  

       // to set all the locks to a false NOTE:  first locker is the number 0. Last locker is the 99.

       for (int_i=1;i<locker_length; i++)

       {

       locker[i] = false;

       }

       // first student opens all lockers.

       for (int i=1;i<locker.length; i++)        {

       locker[i] = true;

       }

       for(int S=2; S<locker.length; S++)

       {

          for(int k=S; k<locker.length; k=k+S)

          {

              if(locker[k]==false) locker[k] = true;

              else locker[k] = false;      

          }            

       }

       for(int S=1; S<locker.length; S++)

       {

           if (locker[S] == true) {

               System.out.println("Locker " + S + " Open");

           }

         /* else {

               System.out.println("Locker " + S + " Close");

           } */

       }

   }

}

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Answer:

  1. #include <stdio.h>
  2. int main()
  3. {
  4.    const double piVal = 3.14159;
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  6.    double sphereRadius = 0.0;
  7.    
  8.    sphereRadius = 1.0;
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  10.    
  11.    
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Explanation:

Firstly we can identify the formula to calculate volume of sphere which is

Volume = 4/3 \pi r^{3}

With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.

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highlights job roles and skills rather than positions

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Answer:

  1. from matplotlib import pyplot as plt
  2. with open("text.txt") as file:
  3.    data = file.readlines()
  4.    category = []
  5.    amount = []
  6.    for row in data:
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  9.        amount.append(float(values[1]))
  10.    
  11. figure = plt.figure()
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Firstly, we need to import matplotlib library (Line 1).

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Answer:

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Explanation:

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This translation into machine language is done in two ways – compilation or interpretation.

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Compiler

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Debugging is defined as removal of errors in the programs.

A compiler is responsible for converting high level language code into machine level code.

The complete program undergoes compilation at the same time.

A compiled program executes faster than an interpreted program.

A compiled program produce machine code which is a collection of 0 and 1, hence, it takes less time to execute.

Examples of compiled languages are C and C++.

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The analysis of the program takes less time and takes place before interpretation begins. The analysis phase is called pre processing.

An interpreted program is translated one line at a time.

The program interpretation stops when an error is encountered. This makes debugging easy.

Debugging is defined as removal of errors in the programs.

Examples of interpreted languages include Python and Ruby.

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