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WARRIOR [948]
2 years ago
8

g Suppose the information content of a packet is the bit pattern 1110 0110 1001 1101 and an even parity scheme is being used. Wh

at would the value of the field containing the parity bits be for the case of a two-dimensional parity scheme? Your answer should be such that a minimum- length checksum field is used.
Computers and Technology
1 answer:
erma4kov [3.2K]2 years ago
4 0

Answer: see description

Explanation:

first we accommodate the bit pattern in a matrix of 4x4 which is the minimum length checksum field, now with even parity two-dimensional scheme we need to complete this matrix by adding one row and one column by adding at the end of each row a 1 or a 0 to complete pairs of 1's:

we have

\left[\begin{array}{cccc}1&1&1&0\\0&1&1&0\\1&0&0&1\\1&1&0&1\end{array}\right]

so we complete with this, adding a row at the end which matches a pair number of 1's

\left[\begin{array}{ccccc}1&1&1&0&1\\0&1&1&0&0\\1&0&0&1&0\\1&1&0&1&1\\1&1&0&0&0\end{array}\right]

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using static System.Console;

class DebugTwo2{

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       string name;string firstString, secondString; ----- Replace secondSting with secondString,

<em>        int first, second, product;</em>

       Write("Enter your name >> "); --- Here, the quotes must be closed with corresponding quotes "

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<em>        Write("Enter another integer >> ");</em>

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<em>        second = Convert.ToInt32(secondString);</em>

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