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Neporo4naja [7]
2 years ago
13

A computer system uses passwords that are six characters and each character is one of the 26 letters (a-z) or 10 integers (0-9).

Uppercase letters are not used. Let A denote the event that a password begins with a vowel (either a, e, i, o, u) and let B denote the event that a password ends with an even number (either 0, 2, 4, 6, or 8). Suppose a hacker selects a password at random. Determine the following probabilities. Round your answers to four decimal places (e.g. 98.7654).
Computers and Technology
1 answer:
lesantik [10]2 years ago
4 0

Question continuation

Determine the following probabilities:

a. P(A)

b. P(B)

c. P(A ∩ B)

d. P(A ∪ B)

Answer:

a. P(A) = 0.1389

b. P(B) = 0.1389

c. P(AnB) = 0.0193

d. P(AuB) = 0.2585

Explanation:

Given

Password length = 6

Letters (a-z) = 26

Integers (0-9) = 10

Total usable characters = 26 + 10 = 36

a. P(A) = Probability that a password begins with vowel (a,e,i,o,u)

Probability = Number of required outcomes/ Number of possible outcomes

Number of required outcomes = Number of vowels = 5

Number of possible outcomes = Total usable characters = 36

P(A) = 5/36

P(A) = 0.13888888888

P(A) = 0.1389

b. P(B) = Probability that the password ends with an even number (0,2,4,6,8)

Probability = Number of required outcomes/ Number of possible outcomes

Number of required outcomes = Number of even numbers = 5

Number of possible outcomes = Total usable characters = 36

P(B) = 5/36

P(B) = 0.13888888888

P(B) = 0.1389

c. P(AnB)

This means that the probability that a password starts with a vowel and ends with an even number

P(AnB) = P(A) and P(B)

P(AnB) = P(A) * P(B)

P(AnB) = 5/36 * 5/36

P(AnB) = 25/1296

P(AnB) = 0.01929012345

P(AnB) = 0.0193 ----_---- Approximately

d. P(AuB)

This means that the probability that a password either starts with a vowel or ends with an even number

P(AuB) = P(A) or P(B)

P(AuB) = P(A) + P(B) - P(AnB)

P(AuB) = 5/36 + 5/36 - 25/1296

P(AuB) = 335/1296

P(AuB) = 0.25848765432

P(AuB) = 0.2585 ----_---- Approximately

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Leona [35]

Answer:

d) Social networking sites

Explanation:

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According to this, the collaboration technology that is becoming more and more popular within organizations because it provides a means for forming ad hoc groups, networking and locating potential business allies is social networking sites.

8 0
1 year ago
With Voice over Internet Protocol (VoIP), _____. a. voicemails cannot be received on the computer b. call quality is significant
Pachacha [2.7K]

Answer:

c. Users can have calls forwarded from anywhere in the world

Explanation:

As all you need is the internet, there would be no need to try to sort out roaming as you would on a regular phone line

4 0
1 year ago
Write a method named lastFirst that accepts a string as its parameter representing a person's first and last name. The method sh
Usimov [2.4K]

I'm going to assume this is Java, because you said "method" meaning it will be some sort of object oriented language, and Java's really common. Here would be the full program, but you can just take the method out isolated if you need it.

package lastname;

public class LastName {

   public static void main(String[] args) {

       // Example usage:

       String name = LastName.lastName("Garrett Acord");

       System.out.println(name);

       // Output: Acord G.

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   public static String lastName(String fullName)

   {

       String[] splitName = fullName.split(" ");

       return String.format("%s %s.", splitName[1], splitName[0].substring(0,1) );

       

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7 0
2 years ago
What will be displayed after code corresponding to the following pseudocode is run? Main Set OldPrice = 100 Set SalePrice = 70 C
Tatiana [17]

Answer:

A jacket that originally costs $ 100 is on sale today for $ 80                                    

Explanation:

Main : From here the execution of the program begins

Set OldPrice = 100  -> This line assigns 100 to the OldPrice variable

Set SalePrice = 70   -> This line assigns 70to the SalePrice variable

Call BigSale(OldPrice, SalePrice)  -> This line calls BigSale method by passing OldPrice and SalePrice to that method

Write "A jacket that originally costs $ ", OldPrice  -> This line prints/displays the line: "A jacket that originally costs $ " with the resultant value in OldPrice variable that is 100

Write "is on sale today for $ ", SalePrice  -> This line prints/displays the line: "is on sale today for $ " with the resultant value in SalePrice variable that is 80

End Program -> the main program ends

Subprogram BigSale(Cost, Sale As Ref)  -> this is a definition of BigSale method which has two parameters i.e. Cost and Sale. Note that the Sale is declared as reference type

Set Sale = Cost * .80  -> This line multiplies the value of Cost with 0.80 and assigns the result to Sale variable

Set Cost = Cost + 20  -> This line adds 20 to the value of Cost  and assigns the result to Cost variable

End Subprogram  -> the method ends

This is the example of call by reference. So when the method BigSale is called in Main by reference by passing argument SalePrice to it, then this call copies the reference of SalePrice argument into formal parameter Sale. Inside BigSale method the reference &Sale is used to access actual argument i.e. SalePrice which is used in BigSale(OldPrice, SalePrice) call. So any changes made to value of Sale will affect the value of SalePrice

So when the method BigSale is called two arguments are passed to it OldPrice argument and SalePrice is passed by reference.

The value of OldPrice is 100 and SalePrice is 70

Now when method BigSale is called, the reference &Sale is used to access actual argument SalePrice = 70

In the body of this method there are two statements:

Sale = Cost * .80;

Cost = Cost + 20;

So when these statement execute:

Sale = 100 * 0.80 = 80

Cost = 100 + 20 = 120

Any changes made to value of Sale will affect the value of SalePrice as it is passed by reference. So when the Write "A jacket that originally costs $ " + OldPrice Write "is on sale today for $ " + SalePrice statement executes, the value of OldPrice remains 100 same as it does not affect this passed argument, but SalePrice was passed by reference so the changes made to &Sale by statement in method BigSale i.e.  Sale = Cost * .80; has changed the value of SalePrice from 70 to 80 because Sale = 100 * 0.80 = 80. So the output produced is:

A jacket that originally costs $ 100 is on sale today for $ 80                              

7 0
2 years ago
Given the dictionary, d, find the largest key in the dictionary and associate the corresponding value with the variable val_of_m
geniusboy [140]

Answer:

Here is the Python program:

d = {5:3, 4:1, 12:2}

val_of_max = d[max(d.keys())]

print(val_of_max)

Explanation:

The program works as follows:

So we have a dictionary named d which is not empty and has the following key-value pairs:

5:3

4:1

12:2

where 5 , 4 and 12 are the keys and 3, 1 and 2 are the values

As we can see that the largest key is 12. So in order to find the largest key we use max() method which returns the largest key in the dictionary and we also use keys() which returns a view object i.e. the key of dictionary. So

max(d.keys()) as a whole gives 12

Next d[max(d.keys())]  returns the corresponding value of this largest key. The corresponding value is 2 so this entire statement gives 2.

val_of_max = d[max(d.keys())] Thus this complete statement gives 2 and assigns to the val_of_max variable.

Next print(val_of_max) displays 2 on the output screen.

The screenshot of program along with its output is attached.

4 0
2 years ago
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