Answer:
- def is_prime(n):
- for i in range(2, n):
- if(n % i == 0):
- return False
- return True
-
- prime_truths = [is_prime(x) for x in range(2,101)]
- print(prime_truths)
Explanation:
The solution code is written in Python 3.
Presume there is a given function is_prime (Line 1 - 5) which will return True if the n is a prime number and return False if n is not prime.
Next, we can use the list comprehension to generate a list of True and False based on the prime status (Line 7). To do so, we use is_prime function as the expression in the comprehension list and use for loop to traverse through the number from 2 to 100. The every loop, one value x will be passed to is_prime and the function will return either true or false and add the result to prime_truth list.
After completion of loop within the comprehension list, we can print the generated prime_truths list (Line 8).
I believe the word you're looking for is properties.
Answer: I'd say (B) Two months
Explanation: Hope its correct and helps, Good luck :)
Answer:
Following are the code in the Java Programming Language:
try{ //try block.
processor.process(); //
call the function through the object.
}
catch(Exception e){ //catch block .
System.out.println( "process failure"); //if any exception occurs then print.
}
Explanation:
In the following code, we set two blocks in Java Programming Language of the exception handling which is try block or catch block.
- In try block we call the function "process()" through the "processor" object.
- If any exception occurs in the program then the catch block print the following message is "process failure"
Answer:
// program in C++ to check leap year.
// include header
#include<iostream>
using namespace std;
// main function
int main() {
// variable
int inp_year ;
// ask user to enter year
cout<<"Enter year:";
// read year
cin>>inp_year;
// check year is leap or not
if (((inp_year % 4 == 0) && (inp_year % 100 != 0)) || (inp_year % 400 == 0))
// if leap year , print leap year
cout<<inp_year<<" is a leap year.";
else
// print not leap year
cout<<inp_year<<" is not a leap year.";
return 0;
}
Explanation:
Read year from user.Then check if year is divisible by 4 and not divisible by 100 or year is divisible by 400 then year is leap year.otherwise year is not leap year.
Output:
Enter year:1712
1712 is a leap year.
