Which of the following statements is incorrect? An operating system provides an environment for the execution of programs. An op
1 answer:
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Answer:
The 95% confidence interval would be given by (2.351;3.525)
Explanation:
1) Previous concepts
A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".
The margin of error is the range of values below and above the sample statistic in a confidence interval.
Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".
represent the sample mean
population mean (variable of interest)
s represent the sample standard deviation
n represent the sample size
2) Confidence interval
The confidence interval for the mean is given by the following formula:
(1)
In order to calculate the mean and the sample deviation we can use the following formulas:
(2)
(3)
The mean calculated for this case is
The sample deviation calculated
In order to calculate the critical value we need to find first the degrees of freedom, given by:
Since the Confidence is 0.95 or 95%, the value of and
, and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that
Now we have everything in order to replace into formula (1):
So on this case the 95% confidence interval would be given by (2.351;3.525)
Answer:
See explaination
Explanation:
public class Payroll
{
private int[] itemsSold;
private double[] wages;
//constructor is just kept for demonstrating the code output
public Payroll()
{
itemsSold = new int[] {48,50,37,62,38,70,55,37,64,60};
wages = new double[10];
}
/*
to compute Bonus Threshold, you have to find sum Of Items Sold, highest and lowest
deduct highest and lowest from sum Of Items Sold and then divide by number of items -2
to find the bonus Threshold
*/
public double computeBonusThreshold()
{
int highest = itemsSold[0];
int lowest = itemsSold[0];
int sumOfItemsSold = itemsSold[0];
double bonusThreshold =0;
//iterate over items , find sum of items sold and highest and lowest
for (int i = 1; i < itemsSold.length ; i++)
{
sumOfItemsSold += itemsSold[i];
if(itemsSold[i] > highest)
highest = itemsSold[i];
if(itemsSold[i] < lowest )
lowest = itemsSold[i];
}
bonusThreshold = (sumOfItemsSold - lowest - highest ) / (itemsSold.length -2.0);
return bonusThreshold;
}
/*
Compute wages as asked, wage for an employee is fixed wage added with itemSold * perItemWage
When an employee sold items more than bonus Threshold Items then he will get extra 10%
*/
public void computeWages(double fixedWage, double perItemWage)
{
double bonusThresholdForWages = computeBonusThreshold();
for (int i = 0; i < wages.length ; i++)
{
wages[i] = fixedWage + ( itemsSold[i] * perItemWage);
if(itemsSold[i] > bonusThresholdForWages)
{
wages[i] = wages[i] * 1.1 ; //which is 10 % extra of current wage of employee
}
}
}
/*
Method to show itemsold, wages for the employee
*/
public void printWages()
{
for (int i = 0; i < wages.length ; i++)
{
System.out.printf("Employee =%d , ItemsSold = %d, Wage = %.2f\n",i,itemsSold[i], wages[i]);
}
}
}
=========main.java======
public class Main
{
public static void main(String[] args) {
//create an object of payroll class, where itemsSolds are hard coded for demo
Payroll payroll = new Payroll();
System.out.println("Bonus threshold items are : " + payroll.computeBonusThreshold());
//call computeWages which will internally class bonus threshold as well
payroll.computeWages(10.0,1.5);
payroll.printWages();
}
}
See attachment for screenshot of codes for indentation.
