Answer:
Option (c) is the correct answer of this question.
Explanation:
RAM (Random Access Memory) It is a type of computer memory which can also be retrieved and adjusted in either sequence, usually still had to preserve operating memory and bytecode.
It is a type storage device, and maintains the data used when the device is operating.RAM makes file access more frequently compared with certain digital storage types.
<u>For Example</u>:- PCs, tablets, smartphones ,printers etc.
Other options are not related to the given scenario.
Answer:
False
Explanation:
The private member of a class is not accessible by using the Dot notation ,however the private member are those which are not accessible inside the class they are accessible outside the class .The public member are accessible inside the class so they are accessible by using the dot operator .
<u>Following are the example is given below in C++ Language </u>
#include<iostream> // header file
using namespace std;
class Rectangle
{
private:
double r; // private member
public:
double area()
{ return 3.14*r*r;
}
};
int main()
{
Rectangle r1;// creating the object
r1.r = 3.5;
double t= r1.area(); // calling
cout<<" Area is:"<<t;
return 0;
}
Output:
compile time error is generated
<u>The correct program to access the private member of class is given below </u>
#include<iostream> // header file
using namespace std;
class Rectangle
{
private:
double r; // private member
public:
double area()
{
r1=r;
double t2=3.14*r2*r2;
return(t2); // return the value
}
};
int main()
{
Rectangle r1;// creating the object
r1.r = 1.5;
double t= r1.area(); // calling
cout<<" Area is:"<<t;
return 0;
}
Therefore the given statement is False
Answer:
Let's convert the decimals into signed 8-bit binary numbers.
As we need to find the 8-bit magnitude, so write the powers at each bit.
<u>Sign -bit</u> <u>64</u> <u>32</u> <u>16</u> <u>8</u> <u>4</u> <u>2</u> <u>1</u>
+25 - 0 0 0 1 1 0 0 1
+120- 0 1 1 1 1 0 0 0
+82 - 0 1 0 1 0 0 1 0
-42 - 1 0 1 0 1 0 1 0
-111 - 1 1 1 0 1 1 1 1
One’s Complements:
+25 (00011001) – 11100110
+120(01111000) - 10000111
+82(01010010) - 10101101
-42(10101010) - 01010101
-111(11101111)- 00010000
Two’s Complements:
+25 (00011001) – 11100110+1 = 11100111
+120(01111000) – 10000111+1 = 10001000
+82(01010010) – 10101101+1= 10101110
-42(10101010) – 01010101+1= 01010110
-111(11101111)- 00010000+1= 00010001
Explanation:
To find the 8-bit signed magnitude follow this process:
For +120
- put 0 at Sign-bit as there is plus sign before 120.
- Put 1 at the largest power of 2 near to 120 and less than 120, so put 1 at 64.
- Subtract 64 from 120, i.e. 120-64 = 56.
- Then put 1 at 32, as it is the nearest power of 2 of 56. Then 56-32=24.
- Then put 1 at 16 and 24-16 = 8.
- Now put 1 at 8. 8-8 = 0, so put 0 at all rest places.
To find one’s complement of a number 00011001, find 11111111 – 00011001 or put 0 in place each 1 and 1 in place of each 0., i.e., 11100110.
Now to find Two’s complement of a number, just do binary addition of the number with 1.
Answer:
- #include <stdio.h>
- int main()
- {
- const double piVal = 3.14159;
- double sphereVolume = 0.0;
- double sphereRadius = 0.0;
-
- sphereRadius = 1.0;
- sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
-
-
- printf("Sphere volume: %lf\n", sphereVolume);
- return 0;
- }
Explanation:
Firstly we can identify the formula to calculate volume of sphere which is
Volume = 4/3 
With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.
At last, display the sphere volume using printf method (Line 13).
