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Ludmilka [50]
2 years ago
11

Joe, Kate and Jody are members of the same family. Kate is 5 years older than Joe. Jody is 6 years older than Kate . The sum of

their ages squared is 961 years. What are their ages?
Computers and Technology
2 answers:
I am Lyosha [343]2 years ago
6 0

Answer:11

Explanation:

mezya [45]2 years ago
5 0

Answer:

5, 10 and 16

Explanation:

The sum of their ages is √961 = 31

If Joe is x years old, the equation that follows is:

x + (x+5) + (x+5+6) = 31

This simplifies to

3x = 31 - 11 - 5 = 15

so x=5

From that you can find

Joe = x = 5

Kate = x+5 = 10

Jody = x+5+6 = 16

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1. Write a set of routines for implementing several stacks and queues within a single array. Hint: Look at the lecture material
JulsSmile [24]

Answer:

Out of the two methods The 2nd method is a better option for implementing several stacks and arrays using the single array system this is because Method 2 makes efficient use of the available space

Explanation:

A) Method 1 ( Divide the given single array in the size of n/k.)

  • How to use method 1 to implement several stacks involves :

i)  To implement several stacks through an array (x) is by dividing the array in n/k parts.

ii) The k represents the slots in which the different stacks will be placed and the n represents the size of the array x.

iii) If you need to implement at least two stacks place the first stack in the slot of a [0] to a [n/k - 1], and another stack in the slot of a[n/k] to a[2n/k-1].

note: The  disadvantage of this method is that the use of the space of the array is not much efficient. therefore method 2 is better

  • How to use method 1 to implement queues involves :

i) queues can also be implemented through an array. applying the same method above

ii) Divide the array in slots and place the queues in that slots.

This method has a problem with  the efficient utilization of the space.therefore method 2 is preferred

B) Method 2 ( uses the space efficiently ) uses two more arrays to implement stacks which are : Top_array and Next_array

  • how to use method 2 to implement several stacks

i) Store the indexes of the next item that will also be stored in all stacks in this initial stack

ii)The initial actual array is x[] and this will store the stacks.

iii)Simultaneously with several stacks, the stack which contain the free slots in the array x[] will also be maintained.

iv)  The entries of the Top_array[] will be initialized to -1. This implies that all the stacks are empty.

v)  Firstly the entries of the array Next_array[i] will be initialized to i+1, since all the slots initially are free and are pointed to the next slot.

vi) Initialize The top of the free stack that is maintaining the free slots  as 0.

vii)  The complexity of push () (method to insert an element) and pop () (method to delete an element) operations by using this method is O (1).

  • How to use method 2 to implement several queues

The same method applicable to implementing several stacks is used here but with a difference is the presence of three extra arrays which are :

Front_array[] = indicates the number of queues. This array stores the indexes of the front elements of the stacks.

Rear_array[] = determines the sizeof the array k . This array stores the indexes of the last elements of the stacks.

Next_array[] = The array n indicates the size of the single array say x. This array stores the indexes of the next items that is being pushed.

i) The initial actual array is a[] which will store the queues. The free slots will also be maintained.

ii)The entries of the Front_array[] will be initialized to -1. This means  that all the queues are empty initially

ii) Initially the entries of the array Next_array[i] will be initialized to i+1, since all the slots initially are free and are pointed to the next slot.

iv) Apply The complexity of enqueue ()  and dequeue ()  by using this method is O (1).

4 0
2 years ago
You are given an array x of string elements along with an int variable n that contains the number of elements in the array. You
Slav-nsk [51]

Answer:

The code to this question can be given as:

Code:

int i,j,count_previous=0,count_next=0; //define variable

for (j=0; j<n; j++) //loop for array

{

if (x[0]==x[j]) //check condition

{

count_previous++; //increment value by 1.

}

}

for (i=0; i<n; i++) //loop

{

for (j=0; j<n; j++)

{

if (x[i]==x[j]) //check condition

{

count_next++; //increment value by 1.

}

}

if (count_previous>count_next) //check condition

{

mode=x[i-1];

}

else

{

mode=x[i];

count_previous=count_next; //change value.

count_next= 0 ; //assign value.

}

}

Explanation:

In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.

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1 year ago
As part of the duties of a digital forensics examiner, creating an investigation plan is a standard practice. Write a 3 to 4 (no
Simora [160]

Answer:

A digital forensic investigation is a special case of a digital investigation. Where the procedure and techniques are used will allow the results to be entered into cost of low foreg on investigation may be started to answer a question about whether or not centraband digital images exist on a computer.

Here we are considering the case of Global Finance Company with wide range of financial products and wide range of customers throughout the world. A suspect of compromise has been detected from the manager's computer. Now the team has been deployed to the branch office and conduct the Digital Forensic Investigation.

Concern of the Company

1. Regular updates for application infrastructure and network infrastructure.

2. One branch managers from porisbane branch felt compromises in his computer.

3. Both the servers and work station from all the offices are based on Microsoft Windows.

4. The firewalls and network segmentation are fully implemented.

5. Through intrasion detection and logging exist in the brances these are hardly used.

Digital Forensic Investigation Approach

The audit term of the Global Finacnce Company can follow four step. The digital forensic investigation model stands to be most effective model for investigation of the compromise happened int he reginal branch of the Global Finance Company.

1. Collection

a. All information from the manager's workstation, servers and other workstations must be collected.

b. Obtain all the important informtation.

c. Identify storage context noth internal and external devices.

d. Forensic tools that are applicable and to be used for the investigation are to be listed and made available for usage.

e. Target computer forensic imaging to be done and hashed to check the integrity of data.

f. Line network traffic has to captured.

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Volatile memory is the temporary memory and primary volatile memory is RAM

By cinning command: Cryptcat6543 -k key

Computer data can now required with the command Cryptcat -1 -p6543 -k key>>

Non volatile Memory Acquisition: Permanent memory or volatile memory stands significant source for the digital forensic investigation.

Parmanent data is collected through both online and offline methods:

Offline data is collected from the hard drive applications tool such as Guymayers etc.

Online data like firewall logs, antivirus logs and domain controller log with help of wires work and ethernal collected.

2. Examination

Once the data collected detailed examination is done by comparing the original and logical copies collected. Such examination gives us clues of how manege for window registry examination. Command used echo text_mess > file1.text : file2.txt

The above file retrieved through the command more < file1.txt : file2.txt

The network forensic is enabled using the tools and techniques so that the following potential information can be accessed.

System Information, Service listing, Process listing, Registry information, Binary dumped of memory

3. Analysis with Assumption

Many tools and methodologies are used by the audit team to analyse the collection and examined evidence. Analysis is done according to the following:

a. Leyword searches in all the files

b. Recovering the deleted files

c. Registry information extraction from the workstation

The tools used in this phase are FTK and ILOOKIX. These tools are helpful to recover the document, chat, logs, emails.

4. Report

The final report is generated by the audit team

Purpose of report Digital Forensic investigation conducted on the compromise of manager's computer

Author of the report Aufit Team

Incident Summery The source of compromise are x, y, x

Evidence All the effected files, registry, log files

Analysis All the analyzed data analyzed

Conclusion All digital evidence are extracted and found from the source

Document support volatile and non volatile data, tools, log info, registry info and so on.

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a_sh-v [17]

Answer:

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Algorithm is A(n) key set of steps used to convert an unencrypted message into an encrypted sequence of bits that represent the message; it sometimes refers to the programs that enable the cryptographic processes.

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