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Tema [17]
2 years ago
5

Thomas has signed a deal with a production house that allows them to use his images on their website. What is required when imag

eers permit
usage of their images for commercial or editorial purposes?
A. copyright
B licensing
c. permit
D. fair use
Computers and Technology
2 answers:
BaLLatris [955]2 years ago
6 0

Answer:

copyright ( A )

Explanation:

copyright law is required to be followed when granting permit to a second party who is not a co-owner of a property the usage of the property be it intellectual or an invention created by the original owner.

Thomas is the owner of the image to be used by the company so before Thomas will go into signing a deal with the company who wants to use its invention which in this case is his images, the copyright law that protects the ownership of such Image will have to be viewed by the company to ensure that the image truly belongs to Thomas so that no copyright laws will be contravened.

Phoenix [80]2 years ago
4 0
D. Fair use. Because you need to give credit to the owner.
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Mrs. Johnson is here today to receive an intercostal nerve block to mitigate the debilitating pain of her malignancy. Her cancer
Furkat [3]

Answer:

The correct answer is:

a. M54.6, C79.51, C80.1

Explanation:

-  M54.6 Pain in thoracic spine. It is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

- C79.51: Secondary malignant neoplasm of bone, it is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes.

- G89. 3 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM G89.

Malignant neoplasm of anus, unspecified

Neoplasm related pain (acute) (chronic)

Pain in thoracic spine. M54. 6 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM M54.

Malignant (primary) neoplasm, unspecified

- C80. 1 is a billable/specific ICD-10-CM code that can be used to indicate a diagnosis for reimbursement purposes. The 2020 edition of ICD-10-CM C80.

5 0
2 years ago
A bicycle sharing company is developing a multi-tier architecture to track the location of its bicycles during peak operating ho
fgiga [73]

Answer:

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5 0
2 years ago
A time-saving strategy that helps define unfamiliar words involves using
yuradex [85]

The correct answer is A. Familiar words for clues

Explanation:

Finding unfamiliar words is common while reading, especially in texts that belong to a specific field such as medicine, technology, etc. This can be handled through multiple strategies such as using a dictionary, guessing the meaning of the word based on its parts, and using context clues.

In this context, one of the easiest and most time-saving strategy is the use of context clues that implies using the familiar words as clues to guess the meaning of an unfamiliar word. This is effective because in most cases the meaning of an unknown word can be determined using the context of the word or words around the unknown word. Also, this strategy takes little time because you only need to analyze the sentence or paragraph where the unknown word is. Thus, the time-saving strategy to define unfamiliar words involves using familiar words for clues.

6 0
1 year ago
Read 2 more answers
A blood bank maintains two tables - DONOR, with information about people who are willing to donate blood and ACCEPTOR, with info
Kipish [7]

Answer:

The sql query is given below.

Since we need to count of males and females for a particular blood group, we put xxx for the blood group.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors,

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

Explanation:

The clauses in the query are as follows.

1. SELECT: all the columns required in the output are put in this clause.

2. FROM JOIN ON: the table(s) from which the above columns are taken are put in this clause.

3. WHERE: any condition required to filter the output is put in this clause.

The query is explained below.

1. Find the number of male donors. Number of anything can be found using COUNT() function. A query is required since gender is included in deciding the type of donor.

2. The query is defined to find number of male donors as follows.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "M%"; )

3. In the previous query, LIKE operator is used since it is not defined what value is stored for male donors.

4. Similarly, the query to find the number of female donors is formed.

COUNT( SELECT DID FROM DONOR WHERE GENDER LIKE "F%"; )

5. Next, the final query is formed as follows.

SELECT: both COUNT() functions will come here.

FROM: table name

WHERE: specific blood group will be put here

GROUP BY: this clause is optional and is not used in this query.

HAVING: this clause is optional and is not used in this query.

6. The query after putting all clauses is shown below.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%"),

COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%")

FROM DONOR

WHERE BG = xxx;

7. Alias is used in the above query for each column to get the final query.

SELECT COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "M%") as Male_Donors, COUNT(SELECT DID FROM DONOR WHERE GENDER LIKE "F%") as Female_Donors

FROM DONOR

WHERE BG = xxx;

7 0
2 years ago
(1) Prompt the user to enter five numbers, being five people's weights. Store the numbers in an array of doubles. Output the arr
Mashutka [201]

Answer:

weights = []

total = 0

max = 0

for i in range(5):

   weight = float(input("Enter weight " + str(i+1) + ": "))

   weights.append(weight)

   total += weights[i]

   if weights[i] > max:

       max = weights[i]

average = total / 5

print("Your entered: " + str(weights))

print("Total weight: " + str(total))

print("Average weight: " + str(average))

print("Max weight: " + str(max))

Explanation:

Initialize the variables

Create a for loop that iterates 5 times

Get the values from the user

Put them inside the array

Calculate the total by adding each value to the total

Calculate the max value by comparing each value

When the loop is done, find the average - divide the total by 5

Print the results

6 0
2 years ago
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