Because, they are all required to configure to it to be recognized by an operating system.
Explanation:
It is the Operating System Software that instructs the hardware and puts them together to work well. When the manufacturer does not configure the device to be recognized by an operating system, then it will not work with other components.
Example.
If an Apple machine's sound card is being put in an HP machine which uses Microsoft designed operating system, won't work due to the operating system that the sound card has been designed for.
The elements in a string type array will be initialized to "Null".
The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}
Answer:
Option a
Explanation:
The Critical Path Method is the arrangement of booked exercises that decides the term of the task. These planned exercises must be performed if the venture is to be viewed as a triumph.
Therefore, options b, c, d and e can't be true because:
b. Activities in the Critical Path Method has no or zero slack.
c. The duration of the critical path in CPM determined on the basis of the latest activity and the earliest initiation.
d. The CPM method schedules the activity of the longest duration.
Answer:
Pseudo CODE
a)
n= Input “Enter 5 integer value”
b)
sum=0.0
For loop with i ranging from 0 - 5
Inside loop sum=n[i]+sum
Outside loop avg= sum/5
Print avg
c)
small=n[0] # assume the first number in the list is smallest
large= n[0] # assume the first number in the list is largest
For loop with i ranging from 0 - 5
Inside loop if n[i]<small #if any another number is smaller than small(variable)
Inside if Then small=n[i]
Inside loop if n[i]>large # if any another number is larger than large(variable)
Inside if then large=n[i]
Print small
Print large
d)
print avg
print small
print large
