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guapka [62]
2 years ago
9

SHOW ALL YOUR WORK. REMEMBER THAT PROGRAM SEGMENTS ARE TO BE WRITTEN IN JAVA. Assume that the classes listed in the Java Quick R

eference have been imported where appropriate. Unless otherwise noted in the question, assume that parameters in method calls are not null and that methods are called only when their preconditions are satisfied. In writing solutions for each question, you may use any of the accessible methods that are listed in classes defined in that question. Writing significant amounts of code that can be replaced by a call to one of these methods will not receive full credit. This question involves a game that is played with multiple spinners. You will write two methods in the SpinnerGame class below. public class SpinnerGame { /** Precondition: min < max * Simulates a spin of a spinner by returning a random integer * between min and max, inclusive. */ public int spin(int min, int max) { /* to be implemented in part (a) */ } /** Simulates one round of the game as described in part (b). */ public void playRound() { /* to be implemented in part (b) */ } } (a) The spin method simulates a spin of a fair spinner. The method returns a random integer between min and max, inclusive. Complete the spin method below by assigning this random integer to result. /** Precondition: min < max * Simulates a spin of a spinner by returning a random integer * between min and max, inclusive. */ public int spin(int min, int max) { int result; return result; }

Computers and Technology
1 answer:
adoni [48]2 years ago
4 0

Answer:

Check the explanation

Explanation:

Player 1 Coin

Player 2 Coin

Player 1

Player 2

Round

Count at

Count at

Player

Player

Coin

Coin

Number

Beginning of

Beginning of

1

2

Outcome

Count at

Count at

Round

Round

Spends

Spends

End of

End of

Round

Round

Off-by-

one,

10 - 1

10

10

2

player 2

10 - 2

+

= 8

1

gains 1

= 10

coin

Same,

10 - 2

2

8

10

2

2

player 2

-

gains 1

6

+

=

1

=

9

coin

Off-by-

two,

6 - 1

+

3

6

9

3

player 1

2

9 - 3

gains 2

=

=

7

6

coins

Same,

4

7

6

2

2

player 2

7 - 2

6 - 2+

gains 1

=

5

=

coin

5

Kindly check the attached image below to see the well arranged table to solve the above question.

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Which phrase best describes a scenario in Excel 2016?
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Answer:

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Consider the following skeletal C program: void fun1(void); /* prototype */ void fun2(void); /* prototype */ void fun3(void); /*
natita [175]

Answer:

Check the explanation

Explanation:

a) main calls fun1; fun1 calls fun2; fun2 calls fun3

fun3()                                        d, e, f

fun2()                                        c, d, e

fun1()                                        b, c, d

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun3().

   In fun3(), the local variables "d, e, f" of fun3() will be visible

   variable "c" of fun2() will be visible

   variable "b" of fun1() will be visible

   variable "a" of main() will be visible

b) main calls fun1; fun1 calls fun3

fun3()                                        d, e, f

fun1()                                        b, c, d

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun3().

   In fun3(), the local variables "d, e, f" of fun3() will be visible

   variable "b, c" of fun1() will be visible

   variable "a" of main() will be visible

c) main calls fun2; fun2 calls fun3; fun3 calls fun1

fun1()                                        b, c, d

fun3()                                        d, e, f

fun2()                                        c, d, e

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun1().

   In fun1(), the local variables "b, c, d" of fun1() will be visible

   variable "e, f" of fun3() will be visible

   variable "a" of main() will be visible

d) main calls fun1; fun1 calls fun3; fun3 calls fun2

fun2()                                        c, d, e

fun3()                                        d, e, f

fun1()                                        b, c, d,

main()                                        a, b,c

CALL STACK SHOWING THE VARIABLES OF EVERY FUNCTION

   From the above call stack diagram, it is very clear that the last function call is made to fun2().

   In fun2(), the local variables "c, d, e" of fun2() will be visible

   variable "f" of fun3() will be visible

     variable "b" of fun1() will be visible

   variable "a" of main() will be visible

The last function called will comprise of all its local variables and the variables other than its local variables from all its preceding function calls till the main function.

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leonid [27]

Answer:

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Explanation:

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You can select multiple rows or columns by holding Shift and pressing the Arrow Keys multiple times.

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