Answer:
def cal(n):
s=0
while n>0:
r=n%10
if(r==0 or r==4 or r==6 or r==9):
s=s+1
elif r==8:
s=s+2
n=n//10
print(s)
n=int(input("enter number:"))
print(n)
cal(n)
Explanation:
- Create a function to calculate count of closed path
.
- Create a variable to store count of closed path
.
- While number is positive
, extract last digit of n
.
- Reduce number by truncating last digit
.
- Make a function call to compute count of path.
A saftey issue because what is the car malfunctions or red light or police jus drive yo own car
The answer & explanation for this question is given in the attachment below.
Answer:
false
Explanation:
it depends most of time so false
