All categories

1 year ago

5.19 LAB: Exact change - functions

Computers and Technology

2 answers:

matrenka [14]1 year ago

6 0

Answer:

def exact_change(user_total):

if user_total <=0:

print("No change")

else:

num_dollars = int(user_total/100)

user_total = user_total % 100

num_quarters= int(user_total/25)

user_total = user_total % 25

num_dimes= int(user_total/10)

user_total = user_total % 10

num_nickels= int(user_total/5)

num_pennies= user_total % 5

if num_dollars >= 1:

if num_dollars == 1:

print(str(num_dollars)+" num_dollars")

else:

print(str(num_dollars)+" amountdollars")

if num_quarters>= 1:

if num_quarters== 1:

print(str(num_quarters)+" quarter")

else:

print(str(num_quarters)+" quarters")

if num_dimes>= 1:

if num_dimes== 1:

print(str(num_dimes)+" dime")

else:

print(str(num_dimes)+" dimes")

if num_nickels>= 1:

if num_nickels== 1:

print(str(num_nickels)+" nickel")

else:

print(str(num_nickels)+" nickels")

if num_pennies>= 1:

if num_pennies== 1:

print(str(num_pennies)+" penny")

else:

print(str(num_pennies)+" pennies")

user_total = int(input("Enter user_total Here: "))

exact_change(user_total)

Explanation:

The explanation is long. So, I added it as an attachment.

Download txt

Reptile [31]1 year ago

6 0

Answer:

Written in Python:

def exact_change(user_total):

num_dollars = user_total // 100 #convert to dollars

user_total %= 100 #get remainder after conversion

num_quarters = user_total // 25 #convert to quarters

user_total %= 25 #get remainder after conversion

num_dimes = user_total // 10 #convert to dimes

user_total %= 10 #get remainder after conversion

num_nickels = user_total // 5 #convert to nickels

user_total %= 5 #get remainder after conversion

num_pennies = user_total

return(num_dollars, num_quarters, num_dimes, num_nickels, num_pennies)

if __name__ == '__main__':

input_val = int(input()) #prompt user to input an integer

num_dollars, num_quarters, num_dimes, num_nickels, num_pennies = exact_change(input_val) #recall exact_change function

#define output statements to output number of exact_change variables:

#num_dollars, num_quarters, num_dimes, num_nickels, num_pennies

if input_val <=0: #if amount is zero

print('no change') #print output

else:

if num_dollars > 1: #if number of dollars is greater than one

print('%d dollars' % num_dollars) #print number of dollars

elif num_dollars == 1: # if number of dollars equal 1

print('%d dollar' % num_dollars) #print dollar in singular

if num_quarters > 1: #if number of quarters is greater than one

print('%d quarters' % num_quarters) #print number of quarters

elif num_quarters ==1: # if number of quarters equal 1

print('%d quarter' % num_quarters) #print quarter in singular

if num_dimes > 1: #if number of dimes is greater than one

print('%d dimes' % num_dimes) #print number of dimes

elif num_dimes == 1: # if number of dimes equal 1

print('%d dime' % num_dimes) #print dime in singular

if num_nickels > 1: #if number of nickels is greater than one

print('%d nickels' % num_nickels) #print number of nickels

elif num_nickels == 1: # if number of nickels equal 1

print('%d nickel' % num_nickels) #print nickel in singular

if num_pennies >1: #if number pennies is greater than one

print('%d pennies' % num_pennies) #print number of pennies

elif num_pennies ==1: # if number of pennies equal 1

print('%d penny' % num_pennies) #print penny in singular

Explanation:

It's really long, but it's necessary to get all the correct answers.

You might be interested in

There are two cons to an OLTP database. Which of the following are a solution of these cons?

Delicious77 [7]

Answer:

The answer is below

Explanation:

An OLTP (Online transaction processing) database is a database that allows for quick transaction processing. It involves inserting, deleting, updating data in the database.

OLTP has many drawbacks like if the system fails, all transactions are going to have problems. Also, since multiple users are allowed to access the data, it makes it prone to hackers.

The solution to the problems associated to the OLTP database is the OLAP (online analytical processing) database.

The OLAP systems allow users to analyze database information from multiple database systems at one time thereby allowing analysis for business decisions.

6 0

2 years ago

Suppose that cells B1 through B100 of an Excel spreadsheet contain the quantity of units ordered on each of 100 different days.

11111nata11111 [884]

Answer:

The "a" Option is correct.

Explanation:

The "COUNTIF" function counts every cell that, given a condition (value), suits into it. As you want to know the number of cells that contain a value of at least 50, the condition must be properly written to get the correct answer. Unless it is a cell value (e.g. B3), the condition must always be written with quotes (""). So, the options b and c are automatically discarded.

The d option appears to be correct, but it's not. If the condition is written ">50", the function will count every cell with a value above 50. But we're searching values at least (including) 50. So the correct answer is the a option.

7 0

1 year ago

4.17 LAB: Data File A comma separated value (.csv) file has been included to be used for this program. Each line contains two va

Andrej [43]

Answer:

import csv

def Csvreader(filename):

with open("filename", "r") as file:

content = file.csv_reader()

list_content = list(content)

file.close

return list_content

Explanation:

This is a python description of the function that reads the csv file and converts it to a list, from the list, each item can accessed with its index and updated directly. Use this to draw the same conclusion for a java program.

7 0

1 year ago

If there are 8 opcodes and 10 registers, a. What is the minimum number of bits required to represent the OPCODE? b. What is the

Nimfa-mama [501]

Answer:

For 32 bits Instruction Format:

OPCODE DR SR1 SR2 Unused bits

a) Minimum number of bits required to represent the OPCODE = 3 bits

There are 8 opcodes. Patterns required for these opcodes must be unique. For this purpose, take log base 2 of 8 and then ceil the result.

Ceil (log2 (8)) = 3

b) Minimum number of bits For Destination Register(DR) = 4 bits

There are 10 registers. For unique register values take log base 2 of 10 and then ceil the value. 4 bits are required for each register. Hence, DR, SR1 and SR2 all require 12 bits in all.

Ceil (log2 (10)) = 4

c) Maximum number of UNUSED bits in Instruction encoding = 17 bits

Total number of bits used = bits used for registers + bits used for OPCODE

= 12 + 3 = 15

Total number of bits for instruction format = 32

Maximum No. of Unused bits = 32 – 15 = 17 bits

OPCODE DR SR1 SR2 Unused bits

3 bits 4 bits 4 bits 4 bits 17 bits

7 0

1 year ago

_____ remove the part of an image starting from an edge

Lapatulllka [165]

I think it’s cropping could be wrong though

4 0

1 year ago