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Gnom [1K]
1 year ago
8

Animated graphics that are displayed on the screen after a set of time when the computer is unattended.​

Computers and Technology
1 answer:
yan [13]1 year ago
7 0

Answer:

Tab b. CTRL+A c. Alt d. Enter 18. Animated graphics that are displayed on the screen after a set of time when the computer is unattended. a. Screen Saver b. Title Bar c. Scroll Bar d.

Explanation:

Tab b. CTRL+A c. Alt d. Enter 16. Animated graphics that are displayed on the screen after a set of time when the computer is unattended

Computer-generated motion graphics[edit]. Before computers were widely available, motion graphics were costly and time-consuming, limiting their use to high-budget filmmaking and ...

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In this image, which feature did we most likely use to quickly change the background, fonts, and layout?
MAVERICK [17]

Answer: themes

Explanation:

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2 years ago
Write a method for the Customer class that that will return a string representing a bill notice when passed a double value repre
Nesterboy [21]

Answer:

Following are the method definition to this question:

public String notice_bill(double amount) //defining method

{

return this.name+", account number "+this.currAccNum+", please pay $"+amt;  //return value.

}

Explanation:

In the given question some information is missing, that is example So, method definition to this question can be described as follows:

  • In the above method definition a string method "notice_bill" is declared, which accepts a double value in its parameter, that is "amount".
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5 0
2 years ago
Write a program FindDuplicate.java that reads n integer arguments from the command line into an integer array of length n, where
kozerog [31]

Answer:

  1. public class FindDuplicate{
  2.    public static void main(String[] args) {
  3.        Scanner input = new Scanner(System.in);
  4.        int n = 5;
  5.        int arr[] = new int[n];
  6.        for(int i=0; i < arr.length; i++){
  7.            int inputNum = input.nextInt();
  8.            if(inputNum >=1 && inputNum <=n) {
  9.                arr[i] = inputNum;
  10.            }
  11.        }
  12.        for(int j =0; j < arr.length; j++){
  13.            for(int k = 0; k < arr.length; k++){
  14.                if(j == k){
  15.                    continue;
  16.                }else{
  17.                    if(arr[j] == arr[k]){
  18.                        System.out.println("True");
  19.                        return;
  20.                    }
  21.                }
  22.            }
  23.        }
  24.        System.out.println("False");
  25.    }
  26. }

Explanation:

Firstly, create a Scanner object to get user input (Line 4).

Next, create an array with n-size (Line 7) and then create a for-loop to get user repeatedly enter an integer and assign the input value to the array (Line 9 - 14).

Next, create a double layer for-loop to check the each element in the array against the other elements to see if there is any duplication detected and display "True" (Line 21 - 22). If duplication is found the program will display True and terminate the whole program using return (Line 23). The condition set in Line 18 is to ensure the comparison is not between the same element.

If all the elements in the array are unique the if block (Line 21 - 23) won't run and it will proceed to Line 28 to display message "False".

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Explanation:

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