answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Morgarella [4.7K]
2 years ago
10

Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in t

he following skeletal program. Assume bigsub is at level 1. function bigsub() { function a(flag) { function b() { ... a(false); ... } // end of b ... if (flag) b(); else c(); ... } // end of a function c() { function d() { ... <------------------------1 } // end of d ... d(); ... } // end of c ... a(true); ... } // end of bigsub The calling sequence for this program for execution to reach d is bigsub calls a a calls b

Computers and Technology
1 answer:
il63 [147K]2 years ago
8 0

Answer:

<u>Stack for all the active record instances:</u>

The initial calling sequences is bigsub

-The bigsub calls funa.

  • In static chain funa finishes their processes then it return back to bigsub
  • In dynamic chain funa finishes their processes then it return back to bigsub

-The funa calls funb.

  • In static chain funb finishes their processes then it return back to funa
  • In dynamic chain funb finishes their processes then it return back to funa

-The funb calls funa.

  • In static chain funa finishes their processes then it return back to bigsub
  • In dynamic chain funa finishes their processes then it return back to funb

-The funa calls func.

  • In static chain func finishes their processes then it return back to bigsub
  • In dynamic chain func finishes their processes then it return back to funa

-The func calls fund.

  • In static chain fund finishes their processes then it return back to func
  • In dynamic chain fund finishes their processes then it return back to func

Explanation:

See the stack diagram.

You might be interested in
Modify the TimeSpan class from Chapter 8 to include a compareTo method that compares time spans by their length. A time span tha
My name is Ann [436]

Answer:

Check the explanation

Explanation:

Here is the modified code for

TimeSpan.java and TimeSpanClient.java.

// TimeSpan.java

//implemented Comparable interface, which has the compareTo method

//and can be used to sort a list or array of TimeSpan objects without

//using a Comparator

public class TimeSpan implements Comparable<TimeSpan> {

   private int totalMinutes;

   // Constructs a time span with the given interval.

   // pre: hours >= 0 && minutes >= 0

   public TimeSpan(int hours, int minutes) {

        totalMinutes = 0;

        add(hours, minutes);

   }

   // Adds the given interval to this time span.

   // pre: hours >= 0 && minutes >= 0

   public void add(int hours, int minutes) {

        totalMinutes += 60 * hours + minutes;

   }

   // Returns a String for this time span such as "6h15m".

   public String toString() {

        return (totalMinutes / 60) + "h" + (totalMinutes % 60) + "m";

   }

   // method to compare this time span with other

   // returns a negative value if this time span is shorter than other

   // returns 0 if both have same duration

   // returns a positive value if this time span is longer than other

   public int compareTo(TimeSpan other) {

        if (this.totalMinutes < other.totalMinutes) {

            return -1; // this < other

        } else if (this.totalMinutes > other.totalMinutes) {

            return 1; // this > other

        } else {

            return 0; // this = other

        }

   }

}

// TimeSpanClient.java

public class TimeSpanClient {

   public static void main(String[] args) {

        int h1 = 13, m1 = 30;

        TimeSpan t1 = new TimeSpan(h1, m1);

        System.out.println("New object t1: " + t1);

        h1 = 3;

        m1 = 40;

        System.out.println("Adding " + h1 + " hours, " + m1 + " minutes to t1");

        t1.add(h1, m1);

        System.out.println("New t1 state: " + t1);

        // creating another TimeSpan object, testing compareTo method using the

        // two objects

        TimeSpan t2 = new TimeSpan(10, 20);

        System.out.println("New object t2: " + t2);

        System.out.println("t1.compareTo(t2): " + t1.compareTo(t2));

        System.out.println("t2.compareTo(t1): " + t2.compareTo(t1));

        System.out.println("t1.compareTo(t1): " + t1.compareTo(t1));

   }

}

/*OUTPUT*/

New object t1: 13h30m

Adding 3 hours, 40 minutes to t1

New t1 state: 17h10m

New object t2: 10h20m

t1.compareTo(t2): 1

t2.compareTo(t1): -1

t1.compareTo(t1): 0

4 0
2 years ago
3.A customer has a system with a Gigabyte B450 Aorus Pro motherboard. He wants to upgrade the processor from the AMD Athlon X4 9
Burka [1]

Answer:

The upgrade is possible and it will yield a remarkable  increase in performance

Explanation:

It is a newer product, there is tendency of having a better application compatibility/performance

It has much higher multi threaded performance which is around 522% higher. This allows for higher performance in professional applications like encoding and heavy multitasking compared to the previous.

When considering gaming, it has higher performance compared to the previous.

5 0
2 years ago
Rupa would like to quickly insert a table into her document without having to worry about formatting the data in the table. Whic
USPshnik [31]
Internet tap and log on application
6 0
2 years ago
Read 2 more answers
Which of these statements regarding mobile games is true? A. They are typically played indoors. B. They have detailed environmen
Lyrx [107]

Answer:

c and d

Explanation:

6 0
2 years ago
In a Diffie-Hellman Key Exchange, Alice and Bob have chosen prime value q = 19 and primitive root a = 10. If Alice's secret key
34kurt

Answer:

a) 6

b) 11

c) 11

Explanation:

Given

Prime value q =n= 19

primitive root (a) =10

Alice secret key = 4

Bob secret key = 6

a) The value Alice Sends to Bob

a​​​​​Private key of Alice mod n

= 10^4 mod 19

= 10000 mod 19

=6

b)The value Bob sends to Alice

a​​​​​Private key of Bob mod n

= a​​​​​​3​​​​​ mod n

= 10^6 mod 19

=1000000 mod 19

= 11

c)

Both the parties calculate the value of secret key at their respective side.

secret key obtained by Alice

= 11

secret key obtained by Bob

= 11

Finally, both the parties obtain the same value of secret key.

The value of common secret key = 17

6 0
2 years ago
Other questions:
  • Why would you copy an individual instead of listing that name on the to line?
    12·2 answers
  • Letitia is in high school. She wants to go to medical school in Kentucky and then become a pediatric surgeon to help children. W
    5·2 answers
  • Write the definition of a function printLarger, which has two int parameters and returns nothing. The function prints the larger
    15·1 answer
  • A client is asking for a printing solution that will print three sheets of paper with identical information on each page with a
    13·1 answer
  • George borrowed some equipment from his friend for recording his monologue for his art class. He got all the equipment except th
    15·1 answer
  • The effectiveness of a(n) _____ process is essential to ensure the success of a data warehouse. Select one: a. visual basic b. e
    15·2 answers
  • Write the notInVocab method. Assume that there are no duplicates in wordArray. You must call findWord and countNotInVocab approp
    10·1 answer
  • ) A byte is used to represent a single character in the computer ______<br> true or false?
    14·2 answers
  • Why are passive readers most likely to have difficulty focusing on a text?
    9·2 answers
  • In a system where Round Robin is used for CPU scheduling, the following is TRUE when a process cannot finish its computation dur
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!