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Morgarella [4.7K]

2 years ago

10

Show the stack with all activation record instances, including static and dynamic chains, when execution reaches position 1 in t

he following skeletal program. Assume bigsub is at level 1. function bigsub() { function a(flag) { function b() { ... a(false); ... } // end of b ... if (flag) b(); else c(); ... } // end of a function c() { function d() { ... <------------------------1 } // end of d ... d(); ... } // end of c ... a(true); ... } // end of bigsub The calling sequence for this program for execution to reach d is bigsub calls a a calls b

Computers and Technology

1 answer:

il63 [147K]2 years ago

8 0

Answer:

<u>Stack for all the active record instances:</u>

The initial calling sequences is bigsub

-The bigsub calls funa.

In static chain funa finishes their processes then it return back to bigsub
In dynamic chain funa finishes their processes then it return back to bigsub

-The funa calls funb.

In static chain funb finishes their processes then it return back to funa
In dynamic chain funb finishes their processes then it return back to funa

-The funb calls funa.

In static chain funa finishes their processes then it return back to bigsub
In dynamic chain funa finishes their processes then it return back to funb

-The funa calls func.

In static chain func finishes their processes then it return back to bigsub
In dynamic chain func finishes their processes then it return back to funa

-The func calls fund.

In static chain fund finishes their processes then it return back to func
In dynamic chain fund finishes their processes then it return back to func

Explanation:

See the stack diagram.

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When looking at security standard and compliance, which three (3) are characteristics of best practices, baselines and framework

Brilliant_brown [7]

Answer:

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Explanation:

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2 years ago

Create a program named Auction that allows a user to enter an amount bid on an online auction item. Include three overloaded met

Olin [163]

Answer:

Explanation:

The following code is written in Java and creates the overloaded methods as requested. It has been tested and is working without bugs. The test cases are shown in the first red square within the main method and the output results are shown in the bottom red square...

class Auction {

public static void main(String[] args) {

bid(10);

bid(10.00);

bid("10 dollars");

bid("$10");

bid("150 bills");

}

public static void bid(int bid) {

if(bid >= 10) {

System.out.println("Bid Accepted");

} else {

System.out.println("Bid not high enough");

}

}

public static void bid(double bid) {

if(bid >= 10) {

System.out.println("Bid Accepted");

} else {

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}

public static void bid(String bid) {

if (bid.charAt(0) == '$') {

if (Integer.parseInt(bid.substring(1, bid.length())) > 0) {

System.out.println("Bid Accepted");

return;

} else {

System.out.println("Bid not in correct Format");

return;

}

}

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for (int x = 0; x < bid.length(); x++) {

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if (bid.substring(x, x + 7).equals("dollars")) {

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}

if (dollarStartingPoint > 1) {

if (Integer.parseInt(bid.substring(0, dollarStartingPoint-1)) > 0) {

System.out.println("Bid Accepted");

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} else {

System.out.println("Bid not in correct format");

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}

} else {

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3 0

2 years ago

The ____________ protocol enables two users to establish a secret key using a public-key scheme based on discrete logarithms

strojnjashka [21]

The answer in the space provided is the Diffie-Hellman Key Exchange. This is entitled to be the first published key algorithm in which has a limit in which the exchange occurs in secret values and that its purpose was to enable two users to have an exchange of key in a secure manner in means of using it for a subsequent symmetric encryption in terms of messages.

7 0

2 years ago

Together with some anthropologists, you’re studying a sparsely populated region of a rainforest, where 50 farmers live along a 5

Varvara68 [4.7K]

Answer:

Explanation:

Farmers are always both directly and indirectly connected to each other

Their network is mostly strong

Networks become weak only on the edges (ends) of the river but doesn't completely dimnish

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The network is very well structurally balanced and we can see that through the below image

20 miles 10 20 30 40 50

See attachment file for diagram

Considering the total length of river as 50miles and and the center of the whole length will be at 25th mile. From that point, if we consider a farmer will be be having friends for a length of 20miles both along upstream and downstream.

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6 0

2 years ago

Find a 95% confidence interval for the mean failure pressure for this type of roof panel.The article "Wind-Uplift Capacity of Re

aliya0001 [1]

Answer:

The 95% confidence interval would be given by (2.351;3.525)

Explanation:

1) Previous concepts

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

$\bar X$ represent the sample mean

$\mu$ population mean (variable of interest)

s represent the sample standard deviation

n represent the sample size

2) Confidence interval

The confidence interval for the mean is given by the following formula:

$\bar X \pm t_{\alpha/2}\frac{s}{\sqrt{n}}$ (1)

In order to calculate the mean and the sample deviation we can use the following formulas:

$\bar X= \sum_{i=1}^n \frac{x_i}{n}$ (2)

$s=\sqrt{\frac{\sum_{i=1}^n (x_i-\bar X)}{n-1}}$ (3)

The mean calculated for this case is $\bar X=2.938$

The sample deviation calculated $s=0.472$

In order to calculate the critical value $t_{\alpha/2}$ we need to find first the degrees of freedom, given by:

$df=n-1=5-1=4$

Since the Confidence is 0.95 or 95%, the value of $\alpha=0.05$ and $\alpha/2 =0.025$ , and we can use excel, a calculator or a table to find the critical value. The excel command would be: "=-T.INV(0.025,4)".And we see that $t_{\alpha/2}=2.78$

Now we have everything in order to replace into formula (1):

$2.938-2.78\frac{0.472}{\sqrt{5}}=2.351$

$2.938+2.78\frac{0.472}{\sqrt{5}}=3.525$

So on this case the 95% confidence interval would be given by (2.351;3.525)

5 0

2 years ago