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kakasveta [241]
2 years ago
12

A sine wave is offset 1/9 cycle with respect to time 0. What is its phase in degrees and radians? Which simple signal has a wide

r bandwidth, a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz?
Computers and Technology
1 answer:
kumpel [21]2 years ago
5 0

Answer:

A.) Phase in degree= 40° ; phase in radian

B.) Bandwidth is the same.

Explanation:

1 complete cycle = 360°

Therefore, 1/9 of a cycle :

Phase in degree ;

(1/9) × 360° = 40°

Phase in radian:

40 × (2π/360)

80π/360

= 0.222πrad

0.698rad

In simple terms, A bandwidth could be explained as the difference between the upper and lower frequencies of the signal. However, the signal described above is a simple signal with no upper or lower frequency boundary.

hence, the bandwidth is assumed to be the same.

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What is wrong with line 1?
Gelneren [198K]

Answer:

The set is a object of the class 'H' and the setY method is a member of G class which is not called by the object of H class.

Explanation:

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Most injury crashes in Florida happen in __________ conditions.
ivolga24 [154]

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The amount of tourism happening in the state is also a condition that takes part in injury crashes due to increased traffic on the roads.

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​to add notes or comments, insert a comment tag using the syntax _____.
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The needed syntax would be:
<!--comment-->
Hope I could be of assistance! ;)
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2 years ago
Read 2 more answers
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