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kakasveta [241]
1 year ago
12

A sine wave is offset 1/9 cycle with respect to time 0. What is its phase in degrees and radians? Which simple signal has a wide

r bandwidth, a sine wave with a frequency of 200 Hz or a sine wave with a frequency of 500 Hz?
Computers and Technology
1 answer:
kumpel [21]1 year ago
5 0

Answer:

A.) Phase in degree= 40° ; phase in radian

B.) Bandwidth is the same.

Explanation:

1 complete cycle = 360°

Therefore, 1/9 of a cycle :

Phase in degree ;

(1/9) × 360° = 40°

Phase in radian:

40 × (2π/360)

80π/360

= 0.222πrad

0.698rad

In simple terms, A bandwidth could be explained as the difference between the upper and lower frequencies of the signal. However, the signal described above is a simple signal with no upper or lower frequency boundary.

hence, the bandwidth is assumed to be the same.

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Answer:

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Explanation:

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1. (1 point) Which flag is set when the result of an unsigned arithmetic operation is too large to fit into the destination? 2.
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Answer:

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Explanation:

Solution

(1) The carry flag : It refers to the adding or subtracting. a two registers has a borrow or carry bit

(2) The over flow flag: This flag specify that a sign bit has been modified during subtracting or adding of operations

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2 years ago
Driving is expensive. Write a program with a car's miles/gallon and gas dollars/gallon (both floats) as input, and output the ga
Alexus [3.1K]

Answer:

  1. def driving_cost(driven_miles, miles_per_gallon, dollars_per_gallon):
  2.    gallon_used = driven_miles / miles_per_gallon
  3.    cost = gallon_used * dollars_per_gallon  
  4.    return cost  
  5. miles_per_gallon = float(input("Input miles per gallon: "))
  6. dollars_per_gallon = float(input("Input dollar per gallon: "))
  7. cost1 = driving_cost(10, miles_per_gallon, dollars_per_gallon)
  8. cost2 = driving_cost(50, miles_per_gallon, dollars_per_gallon)
  9. cost3 = driving_cost(400, miles_per_gallon, dollars_per_gallon)
  10. print("$ %.2f" % cost1)
  11. print("$ %.2f" % cost2)
  12. print("$ %.2f" % cost3)

Explanation:

The solution is written in Python 3.

Firstly, create a function driving_cost that takes three parameters, driven_miles, miles_per_gallon and dollars_per_gallon (Line 1). In the function, calculate the gallon consumption by applying formula driven_miles / miles_per_gallon and then use it to calculate the cost (Line 2 - 3). Return the cost as output (Line 4).

In the main program, prompt user to input miles per gallon and dollars per gallon and then use these input values as arguments to call the function driving_cost function for three times with each time with different driven_miles value (Line 6 - 11).

At last, use formatted print to display the output to two decimal points (Line 13 - 15).

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