Answer:
e) Code segment II produces correct output for all values of str, but code segment I produces correct output only for values of str that contain "pea" but not "pear".
Explanation:
<em>if - elseif - else statements work in sequence in which they are written. </em>
- <em> </em>In case <em>if() statement is true, </em>else if() and else statements will not get executed.
- In case <em>else if() statement is true</em>, conditions in if() and else if() will be checked and else statement will not be executed.
- In case <em>if() and else if() both are false</em>, else statement will be executed<em>.</em>
First, let us consider code segment I.
In this, first of all "pea" is checked in if() statement which will look for "pea" only in the String str. So, even if "pearl" or "pear" or "pea" is present in 'str' the result will be true and "pea" will get printed always.
After that there are else if() and else statements which will not get executed because if() statement was already true. As a result else if() and else statements will be skipped.
Now, let us consider code segment II.
In this, "pearl" is checked in if() condition, so it will result in desired output.
Executable code is attached hereby.
Correct option is (e).
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== is an operator that returns a boolean if both operand are equal.
1101 * 10 is 11010
11000 + 10 is 11010
11010 == 11010
Thus the output would be True.
Answer:
Explanation:
There many commercial documents or formats to store like image, video, photos, audio file, web page, PDF, presentations, and we can use some tools to store this commercial data, for example, excel, microsoft access, mysql, sql, mongo db, and any tool to manage, store in our data with some structures and big data.
Answer:
Python Code:
def validate_url(url):
#Creating the list of valid protocols and file name extensions
valid_protocols = ['http', 'https', 'ftp']
valid_fileinfo = ['.html', '.csv', '.docx']
#splitting the url into two parts
url_split = url.split('://')
isProtocolValid = False
isFileValid = False
#iterating over the valid protocols and file names for validity
for x in valid_protocols:
if x in url_split[0]:
isProtocolValid = True
break
for x in valid_fileinfo:
if x in url_split[1]:
isFileValid = True
break
#Returning the result if the URL has both valid protocol and file extension
return (isProtocolValid and isFileValid)
url = input("Enter an URL: ")
print(validate_url(url))
Explanation:
The image of the output code is attached. Hope it helps.
Answer:
a
Explanation:
Megan doesn't have a registered business. She can't claim insurance
