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sergiy2304 [10]

2 years ago

14

As you are planning your informative speech on the prevalence of Internet memes in pop culture and you wonder if your audience w

ould know what Internet memes are. You are concerned with this aspect of information comprehension and retention.

Computers and Technology

1 answer:

Tasya [4]2 years ago

4 0

Answer:

i dont get it

Explanation:

what is the question?

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Which of the following is ideal for long distance communication ?

Vinvika [58]

Microwave transmission is ideal for long distance communication. It is so good that it is used for satellite and space probe communication.

3 0

2 years ago

When long labels are required, which of these commands can you use to improve readability of a worksheet?

Morgarella [4.7K]

I believe it is wrap text! Hope this helped

6 0

2 years ago

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Consider a single-platter disk with the following parameters: rotation speed: 7200 rpm; number of tracks on one side ofplatter:

horsena [70]

Answer:

Given Data:

Rotation Speed = 7200 rpm

No. of tracks on one side of platter = 30000

No. of sectors per track = 600

Seek time for every 100 track traversed = 1 ms

To find:

Average Seek Time.

Average Rotational Latency.

Transfer time for a sector.

Total Average time to satisfy a request.

Explanation:

a) As given, the disk head starts at track 0. At this point the seek time is 0.

Seek time is time to traverse from 0 to 29999 tracks (it makes 30000)

Average Seek Time is the time taken by the head to move from one track to another/2

29999 / 2 = 14999.5 ms

As the seek time is one ms for every hundred tracks traversed. So the seek time for 29,999 tracks traversed is

14999.5 / 100 = 149.995 ms

b) The rotations per minute are 7200

1 min = 60 sec

7200 / 60 = 120 rotations / sec

Rotational delay is the inverses of this. So

1 / 120 = 0.00833 sec

= 0.00833 * 100

= 0.833 ms

So there is 1 rotation is at every 0.833 ms

Average Rotational latency is one half the amount of time taken by disk to make one revolution or complete 1 rotation.

So average rotational latency is: 1 / 2r

8.333 / 2 = 4.165 ms

c) No. of sectors per track = 600

Time for one disk rotation = 0.833 ms

So transfer time for a sector is: one disk revolution time / number of sectors

8.333 / 600 = 0.01388 ms = 13.88 μs

d) Total average time to satisfy a request is calculated as :

Average seek time + Average rotational latency + Transfer time for a sector

= 149.99 ms + 4.165 ms + 0.01388 ms

= 154.168 ms

4 0

1 year ago

A computer has 4 GB of RAM of which the operating system occupies 512 MB. The processes are all 256 MB (for simplicity) and have

Afina-wow [57]

Answer:

$1-p^{14} = 0.99$

$p^{14}= 0.01$

$p =(0.01)^{1/14}= 0.720$

So then the value of the maximum I/O wait that can be tolerated is 0.720 or 72 %

Explanation:

Previous concepts

Input/output operations per second (IOPS, pronounced eye-ops) "is an input/output performance measurement used to characterize computer storage devices like hard disk drives (HDD)"

Solution to the problem

For this case since we have 4GB, but 512 MB are destinated to the operating system, we can begin finding the available RAM like this:

Available = 4096 MB - 512 MB = 3584 MB

Now we can find the maximum simultaneous process than can use with this:

$\frac{3584 MB}{256 MB/proc}= 14 processes$

And then we can find the maximum wait I/O that can be tolerated with the following formula:

$1- p^{14}= rate$

The expeonent for p = 14 since we got 14 simultaneous processes, and the rate for this case would be 99% or 0.99, if we solve for p we got:

$1-p^{14} = 0.99$

$p^{14}= 0.01$

$p =(0.01)^{1/14}= 0.720$

So then the value of the maximum I/O wait that can be tolerated is 0.720 or 72 %

3 0

1 year ago

A student made a model of isostasy by placing a block of wood in a beaker of water. What does the wooden block represent in the

Komok [63]

I am almost positive the answer is B, Earth's crust. I know it cannot be A or C because isostasy has nothing to do with sea level or glaciers, and Earth's mantle is inside.

7 0

2 years ago

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