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Alexus [3.1K]
1 year ago
8

1. The precious metals needed to make computer chips, graphic cards, and transistors are found in only a small population of cou

ntries. What economic implications does this have for the countries that have these metals to mine?
Computers and Technology
1 answer:
dexar [7]1 year ago
3 0

Answer:

it means that they can charge companies to come mine it making them more wealthy they can also upscale the materials needed to make it as they are the only countries that sell it so they have no one to compete with

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Given an n-element array X, algorithm D calls algorithm E on each element X[i]. Algorithm E runs in O(i) time when it is called
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Answer:

O(n^2)

Explanation:

The number of elements in the array X is proportional to the algorithm E runs time:

For one element (i=1) -> O(1)

For two elements (i=2) -> O(2)

.

.

.

For n elements (i=n) -> O(n)

If the array has n elements the algorithm D will call the algorithm E n times, so we have a maximum time of n times n, therefore the worst-case running time of D is O(n^2)  

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Write a program that has the following String variables: firstName, middleName, and lastName. Initialize these with your first,
Licemer1 [7]

Answer:

The programming language is not stated; However, I'll answer your question using C++ programming language.

Comments are used for explanatory purpose

Program starts here

#include<iostream>

#include <string>

using namespace std;

int main()

{

//Declare Variables

string firstName, middleName, lastName;

char firstInitial, middleInitial, lastInitial;

/*Initialize firstName, middleName and lastName (Replace values with your details)*/

firstName = "First Name";

middleName = "Middle Name";

lastName = "Last Name";

 

// Get Initials

firstInitial = firstName.at(0);

middleInitial = middleName.at(0);

lastInitial = lastName.at(0);

 

//Print Results

cout<<"Lastname: "<<lastName<<endl;

cout<<"Firstname: "<<firstName<<endl;

cout<<"Middlename: "<<middleName<<endl;

cout<<"Last Initial: "<<lastInitial<<endl;

cout<<"First Initial: "<<firstInitial<<endl;

cout<<"Middle Initial: "<<middleInitial<<endl;

return 0;

}

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2 years ago
Following are groups of three​ phrases, which group states three ways to improve your​ concentration?
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3 0
1 year ago
3.14 LAB: Simple statistics for Python
Ad libitum [116K]

Answer:

Following are the correct python code to this question:

n1 = float(input('Input first number: '))#input first number  

n2 = float(input('Input second number: '))#input second number  

n3 = float(input('Input third number: '))#input third number  

n4 = float(input('Input fourth number: '))#input fourth number  

average = (n1+n2+n3+n4)/4 #calculate input number average

product = n1*n2*n3*n4 # calculate input number product

print('product: {:.0f}  average: {:.0f}'.format(round(product),round(average))) #print product and average using round function

print('product: {:.3f}  average: {:.3f}'.format(product,average)) #print product and average value

Output:

Please find the attachment.

Explanation:

The description of the above python code can be defined as follows:

  • In the above python program four variable "n1, n2, n3, and n4" is defined, in which we take input from the user end, and in these user inputs we use the float method, that converts all the input value in to float value.
  • In the next step, two variable average and product are defined, that calculate all input numbers product, average, and hold value in its variable.
  • In the last line, the print method is used, which prints its variable value by using a round and format method.

8 0
2 years ago
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