It could be old ... could be your connection to the internet... could be a virus. You can go to walmart or your super store and buy a usb for your computer. There are ones that can speed up your computer. I had to buy it for mine and it worked. It might be over 20 dollars depends on where you go.
Answer:
Option a: a sorted array
Explanation:
Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.
On another hand, any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.
Answer:
1)
officeAC = new AirConditioner();
officeAC.turnOn();
2)
officeAC = new AirConditioner();
officeAC.turnOn();
officeAC.setTemp(69);
Explanation:
1)
In the first statement a new object of the class AirConditioner whose reference is assigned to the officeAC. new is a keyword which creates an object of the class.
Next statement uses the method turnOn(). Reference to the new object officeAC is used to invoke this method turnOn().
2) The first two statements works the same as in 1)
The last statement invokes a method setTemp() using the reference variable and passes the value 69 to this method to set the desired temperature.
Solution :
class Employee:
#Define the
#constructor.
def __
__(
, ID_number, 
, email):
#Set the values of
#the data members of the class.
= name
_number = ID_number
= salary
self.email_address = email
#Define the function
#make_employee_dict().
def make_employee_dict(list_names, list_ID, list_salary, list_email):
#Define the dictionary
#to store the results.
employee_dict = {}
#Store the length
#of the list.
list_len = len(list_ID)
#Run the loop to
#traverse the list.
for i in range(list_len):
#Access the lists to
#get the required details.
name = list_names[i]
id_num = list_ID[i]
salary = list_salary[i]
email = list_email[i]
#Define the employee
#object and store
#it in the dictionary.
employee_dict[id_num] = Employee(name, id_num, salary, email)
#Return the
#resultant dictionary.
return employee_dict
