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Taya2010 [7]
2 years ago
8

Suppose that you need to maintain a collection of data whose contents are fixed- i.e., you need to search for and retrieve exist

ing items, but never need to add or delete items. Although the collection of data may be quite large, you may assume that it can fit in the computer's memory. Which of the following data structures is the most efficient one to use for this task?
a. a sorted array
b. a linked list
c. a binary search tree
d. a queue
e. they are all the same
Computers and Technology
1 answer:
Keith_Richards [23]2 years ago
4 0

Answer:

Option a: a sorted array

Explanation:

Since the expectation on the data structure never need to add or delete items, a sorted array is the most desirable option. An array is known for its difficulty to modify the size (either by adding item or removing item). However, this disadvantage would no longer be a concern for this task. This is also the reason, linked list, binary search tree and queue is not a better option here although they offer much greater efficiency to add and remove item from collection.

On another hand,  any existing items from the sorted array can be easily retrieved using address indexing and therefore the data query process can be very fast and efficient.

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Answer:

See explaination for the program code

Explanation:

code:

public static int[] countLastDigits(int[] list) {

int[] count = new int[10];

for (int i = 0; i < list.length; i++) {

int digit = list[i] % 10;

count[digit]++;

}

return count;

}

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6. Write pseudo code that will perform the following. a) Read in 5 separate numbers. b) Calculate the average of the five number
Alex

Answer:

Pseudo CODE

a)

n= Input “Enter 5 integer value”

b)

sum=0.0

For loop with i ranging from 0 - 5

Inside loop sum=n[i]+sum

Outside loop avg= sum/5

Print avg

c)

small=n[0] # assume the first number in the list is smallest

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For loop with i ranging from 0 - 5

Inside loop if n[i]<small #if any another number is smaller than small(variable)

Inside if Then small=n[i]

Inside loop if n[i]>large # if any another number is larger than large(variable)

Inside if then large=n[i]

Print small

Print large

d)

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timurjin [86]

Answer:

people

Explanation:

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Write a function PrintShampooInstructions(), with int parameter numCycles, and void return type. If numCycles is less than 1, pr
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Answer:

public static void PrintShampooInstructions(int numberOfCycles){

       if (numberOfCycles<1){

           System.out.println("Too Few");

       }

       else if(numberOfCycles>4){

           System.out.println("Too many");

       }

       else

           for(int i = 1; i<=numberOfCycles; i++){

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           }

       System.out.println("Done");

   }

Explanation:

I have used Java Programming language to solve this

Use if...elseif and else statement to determine and print "Too Few" or "Too Many".

If within range use a for loop to print the number of times

8 0
2 years ago
Read 2 more answers
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