Answer:
See explaination for the program code
Explanation:
code:
public static int[] countLastDigits(int[] list) {
int[] count = new int[10];
for (int i = 0; i < list.length; i++) {
int digit = list[i] % 10;
count[digit]++;
}
return count;
}
1. Cloud Computing
2. Web Conferencing
3. Ribbon
4. PowerPoint
5. Sadie should share the document in One Drive and give her sister permission to edit the document
6. The design and arrangement of items for efficiency and safety
Answer:
Pseudo CODE
a)
n= Input “Enter 5 integer value”
b)
sum=0.0
For loop with i ranging from 0 - 5
Inside loop sum=n[i]+sum
Outside loop avg= sum/5
Print avg
c)
small=n[0] # assume the first number in the list is smallest
large= n[0] # assume the first number in the list is largest
For loop with i ranging from 0 - 5
Inside loop if n[i]<small #if any another number is smaller than small(variable)
Inside if Then small=n[i]
Inside loop if n[i]>large # if any another number is larger than large(variable)
Inside if then large=n[i]
Print small
Print large
d)
print avg
print small
print large
Answer:
public static void PrintShampooInstructions(int numberOfCycles){
if (numberOfCycles<1){
System.out.println("Too Few");
}
else if(numberOfCycles>4){
System.out.println("Too many");
}
else
for(int i = 1; i<=numberOfCycles; i++){
System.out.println(i +": Lather and rinse");
}
System.out.println("Done");
}
Explanation:
I have used Java Programming language to solve this
Use if...elseif and else statement to determine and print "Too Few" or "Too Many".
If within range use a for loop to print the number of times