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amm1812
2 years ago
11

You are given an array x of string elements along with an int variable n that contains the number of elements in the array. You

are also given a string variable mode that has been declared. Assign to mode the mode value of the array. (Assume there are no "ties".)NOTE: The mode is the value that occurs most frequently.EXAMPLE: Given "msft" "appl" "msft" "csco" "ibm" "csco" "msft", the mode is "msft" because it appears the most number of times in the list.
Computers and Technology
1 answer:
Slav-nsk [51]2 years ago
8 0

Answer:

The code to this question can be given as:

Code:

int i,j,count_previous=0,count_next=0; //define variable

for (j=0; j<n; j++) //loop for array

{

if (x[0]==x[j]) //check condition

{

count_previous++; //increment value by 1.

}

}

for (i=0; i<n; i++) //loop

{

for (j=0; j<n; j++)

{

if (x[i]==x[j]) //check condition

{

count_next++; //increment value by 1.

}

}

if (count_previous>count_next) //check condition

{

mode=x[i-1];

}

else

{

mode=x[i];

count_previous=count_next; //change value.

count_next= 0 ; //assign value.

}

}

Explanation:

In the question it is define that x is array of the string elements that is already define in the question so the code for perform operation in the array is given above. In the code firstly we define the variable that is i, j, count_previous, count_next. The variable i,j is used in the loop and variable count_previous and count_next we assign value 0 that is used for check the values of array. Then we define the for loop in this loop we use conditional statement in the if block we check that array of zero element is equal to array of j value then the count_previous is increase by 1. Then we use nested loop It is also known as loop in a loop. In this first loop is used for array and the second loop is used for check array element.In this we use the condition that if array x of i value is equal to array x of j then count_next will increment by 1.Then we use another condition that is if count_previous is greater then count_next then mode of x is decrement by 1. else mode equal to array and count_previous holds the value of count_next and count_next is equal to 0.

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<u>Explanation:</u>

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2 years ago
In this exercise you will debug the code which has been provided in the starter file. The code is intended to take two strings,
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Answer:

Here is the corrected program:

import java.util.Scanner; //to accept input from user

public class 02_14_Activity_one { //class name

    public static void main(String[] args) { //start of main method

    Scanner scan = new Scanner(System.in); //creates Scanner class object

  System.out.println("Enter first string"); //prompts user to enter first string

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Explanation:

The errors were:

1.

Scanner scan = Scanner(System.in);

Here new keyword is missing to create object scan of Scanner class.

Corrected statement:

 Scanner scan = new Scanner(System.in);

2.

String s1 = nextLine();  

Here object scan is missing to call nextLine() method of class Scanner

Corrected statement:

String s1 = scan.nextLine();

3.

String s2 = Scanner.nextLine();

Here class is used instead of its object scan to access the method nextLine

Corrected statement:

String s2 = scan.nextLine();

4.

String n = scan.nextLine();

Here n is of type String but n is a whole number so it should be of type int. Also the method nextInt will be used to scan and accept an integer value

Corrected statement:

int n = scan.nextInt();

5.

System.out.println(s1.substring(1,n-1) + s2.substring(s1.length()-n));

This statement is also not correct

Corrected statement:

System.out.println(s1.substring(0,n) + s2.substring(s2.length() - n ));

This works as follows:

s1.substring(0,n) uses substring method to return a new string that is a substring of this s1. The substring begins at the 0th index of s1 and extends to the character at index n.

s2.substring(s2.length() - n ) uses substring method to return a new string that is a substring of this s2. The substring then uses length() method to get the length of s2 and subtracts integer n from it and thus returns the last n characters of s2.

The screenshot of program along with its output is attached.

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Explanation:

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Answer:

#include <iostream>

#include <cstdlib>

using namespace std;

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   }

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   }

   

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   }

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Explanation:

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Suppose a linked list of 20 nodes. The middle node has a data –250. Write the pseudocode to replace the middle node of the linke
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Answer:

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Explanation:

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