Answer:
// A optimized school method based C++ program to check
// if a number is composite.
#include <bits/stdc++.h>
using namespace std;
bool isComposite(int n)
{
// Corner cases
if (n <= 1) return false;
if (n <= 3) return false;
// This is checked so that we can skip
// middle five numbers in below loop
if (n%2 == 0 || n%3 == 0) return true;
for (int i=5; i*i<=n; i=i+6)
if (n%i == 0 || n%(i+2) == 0)
return true;
return false;
}
// Driver Program to test above function
int main()
{
isComposite(11)? cout << " true\n": cout << " false\n";
isComposite(15)? cout << " true\n": cout << " false\n";
return 0;
}
Explanation:
Answer:
the homepage bounce rate
Explanation:
Bounce rate is defined as the percentage of people that visits a page on a website and then exit or leave. That is, the visitors did not view any other page except the first one and they just leave the page after that visit. In order to get the bounce rate, the total number of visitors to a single page is taken and its then divided by the total number of visits to the website. For example, if the total number of visitors to a website over a period of time is 3000, while those that only visited a page on the website is 500, then the bounce rate is
(500/3000) * 100 = 16%
For this question, the homepage recorded 100 visited only once out of 200 which means homepage bounce rate is 50% : (100/200)*100
While website bounce rate is total number of bounces across the website/total visit to the website
100+100 =200 this is the total bounces across the website
200/500 :500 is the total visit to the website
(200/500)*100 = 40 %
Therefore the homepage bounce rate is higher than the site bounce rate
Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
Answer:
identifying/acknowledging
Explanation:
C would be the correct answer to this question
