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2 years ago

A(n) _____ is the highest educational degree available at a community college. master bachelor associate specialist

2 answers:

5 0

An associate's degree requires two years of academic study and is the highest degree available at a community college

Verdich [7]2 years ago

4 0

an assosciates degree is the highest level of schooling that can be completed at a community college

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Carl knows that water moves through different kinds of soil at different rates. How easily water moves through a soil is known a

Serggg [28]

Answer:

To get the same same results from all pots "amount of water should be same" for all pots.

Explanation:

As Carl want to measure and compare the amount of water that flows in pot in one minute from all all pots. He should keep the amount of water constant for all pots to get the desired results.

6 0

2 years ago

A 1.17 g sample of an alkane hydrocarbon gas occupies a volume of 674 mL at 28°C and 741 mmHg. Alkanes are known to have the gen

Nina [5.8K]

Answer:

C3H8

Explanation:

Step 1:

Data obtained from the question. This includes the following:

Mass of alkane = 1.17g

Volume (V) = 674 mL

Temperature (T) = 28°C

Pressure (P) = 741 mmHg.

Gas constant (R) = 0.08206 atm.L/Kmol

Step 2:

Conversion to appropriate unit.

For Volume:

1000mL = 1L

Therefore, 674mL = 674/1000 = 0.674L

For Temperature:

Temperature (Kelvin) = Temperature (celsius) + 273

Temperature (celsius) = 28°C

Temperature (Kelvin) = 28°C + 273 = 301K

For Pressure:

760mmHg = 1atm

Therefore, 741 mmHg = 741/760 = 0.975atm

Step 3:

Determination of the number of mole of the alkane..

The number of mole of the alkane can be obtained by using the ideal gas equation. This is illustrated below:

Volume (V) = 0.674L

Temperature (T) = 301K

Pressure (P) = 0.975atm

Gas constant (R) = 0.08206 atm.L/Kmol

Number of mole (n) =?

PV = nRT

n = PV /RT

n = (0.975 x 0.674)/(0.08206x301)

n = 0.0266 mole

Step 4:

Determination of the molar mass of the alkane.

Mass of alkane = 1.17g

Number of mole of the alkane = 0.0266mole

Molar Mass of the alkane =?

Number of mole = Mass/Molar Mass

Molar Mass = Mass/number of mole

Molar Mass of the alkane = 1.17/0.0266 = 44g/mol

Step 5:

Determination of the molecular formula of the alkane.

This is illustrated below:

The general formula for the alkane is CnH2n+2

To obtain the molecular formula for the alkane we shall assume n = 1, 2, 3 or more till we arrive at molar Mass of 44.

When n = 1

CnH2n+2 = CH4 = 12 + (4x1) = 16g/mol

When n = 2

CnH2n+2 = C2H6 = (12x2) + (6x1) = 30g/mol

When n = 3

CnH2n+2 = C3H8 = (12x3) + (8x1) = 44g/mol

We can see that when n is 3, the molar mass is 44g/mol.

Therefore, the molecular formula for the alkane is C3H8.

7 0

2 years ago

When a range of IP addresses is set aside for client devices, and one of these IPs is issued to these devices when they request

Pepsi [2]

Answer:

The answer is "Dynamic".

Explanation:

The dynamic allocation of the IP address describes the difference from once in a while, unlike with a static IP address.

In this many residential networks are work on different IP addresses, which requires, and provides clarification.
It is also known as an economical, Provides by "ISP" to allocate a dynamic IP address to certain subscribers.

7 0

2 years ago

What might be one reason why a stock becomes more valuable over time

Nikolay [14]

1. The General Market is Down This is for the most part the most evident reason that a stock is underestimated and happens when the large scale perspective of the economy is poor. It is helpful for financial specialists to have some fundamental apparatuses to esteem the general market so they can get ready as the market progresses toward becoming underestimated.

7 0

2 years ago

Given class Triangle (in file Triangle.java), complete main() to read and set the base and height of triangle1 and of triangle2,

kodGreya [7K]

Answer:

The Triangle.java file is not provided; However, the program is as follows;

Comments are used for explanatory purpose

Also see attachment for Triangle.java program file

import java.util.*;

public class triangle

{

public static void main(String [] args)

{

Scanner input = new Scanner(System.in);

//Declare variables

double base1, height1, base2, height2;

//Prompt user for inputs

System.out.println("Provide values for the base and height of the two triangles");

System.out.print("Base of Triangle 1: ");

base1 = input.nextDouble();

System.out.print("Height of Triangle 1: ");

height1 = input.nextDouble();

System.out.print("Base of Triangle 2: ");

base2 = input.nextDouble();

System.out.print("Height of Triangle 2: ");

height2 = input.nextDouble();

//Compare and Print Results

if(0.5 *base1 * height1 > 0.5 * base2 * height2)

{

System.out.print("Triangle with larger area: Base: "+base1+" Height: "+height1+" Area: "+(0.5 * base1 * height1));

}

else

{

System.out.print("Triangle with larger area: Base: "+base2+" Height: "+height2+" Area: "+(0.5 * base2 * height2));

}

Download java

8 0

2 years ago