Which of the following is a benefit, as well as a risk, associated with client/server networks?

Brittany just pulled up a database table with employee information that contains 50 records of employees at her company. Which o

lesantik [10]

Answer:

The answer is: Operations.

Explanation:

A database operation accesses to information of a relational database. In this case, Brittany has creates the database operation that select employee information of her company and the database has returned a result set. The SQL statement to perform operations on a database are:

INSERT

SELECT

UPDATE

DELETE

3 0

2 years ago

The microprogram counter (MPC) contains the address of the next microcode statement for the Mic1 emulator to execute. The MPC va

Ray Of Light [21]

Answer:

MAR bit

Explanation:

The MPC computers area set of software and hardware standards that was developed by the consortium of computer firms which is led by Microsoft. It contains the address of a next microcode for the Mic1 emulator foe execution.

The part of the executing microcode instruction that determines the value which is placed in the MOC is the MAR bit. The MAR is the memory address register in the CPU which stores the memory address or such addresses to which some data will be sent and also stored.

6 0

1 year ago

_____ remove the part of an image starting from an edge

Lapatulllka [165]

I think it’s cropping could be wrong though

4 0

2 years ago

We have said that the average number of comparisons need to find a target value in an n-element list using sequential search is

bija089 [108]

Answer:

Part a: If the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b: If the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c: The average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

Explanation:

Suppose the list is such that the starting index is 0.

Part a

If list has 15 elements, the middle item would be given at 7th index i.e.

there are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(8,9,10,11,12,13,14) above it. It will have to run 8 comparisons to find the middle term.

If list has 17 elements, the middle item would be given at 8th index i.e.

there are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(9,10,11,12,13,14,15,16) above it.It will have to run 9 comparisons to find the middle term.

If list has 21 elements, the middle item would be given at 10th index i.e.

there are 10 indices (0,1,2,3,4,5,6,7,8,9) below it and 10 indices (11,12,13,14,15,16,17,18,19,20) above it.It will have to run 11 comparisons to find the middle term.

Now this indicates that if the list contains n elements (where n is odd) the middle term is at index (n-1)/2 and the number of comparisons are (n+1)/2.

Part b

If list has 16 elements, there are two middle terms as one at would be at 7th index and the one at 8th index .There are 7 indices(0,1,2,3,4,5,6) below it and 7 indices(9,10,11,12,13,14,15) above it. It will have to run 9 comparisons to find the middle terms.

If list has 18 elements, there are two middle terms as one at would be at 8th index and the one at 9th index .There are 8 indices(0,1,2,3,4,5,6,7) below it and 8 indices(10,11,12,13,14,15,16,17) above it. It will have to run 10 comparisons to find the middle terms.

If list has 20 elements, there are two middle terms as one at would be at 9th index and the one at 10th index .There are 9 indices(0,1,2,3,4,5,6,7,8) below it and 9 indices(11,12,13,14,15,16,17,18,19) above it. It will have to run 11 comparisons to find the middle terms.

Now this indicates that if the list contains n elements (where n is even) the middle terms are at index (n-2)/2 & n/2 and the number of comparisons are (n+2)/2.

Part c

So the average number of comparisons is given as

((n+1)/2+(n+2)/2)/2=(2n+3)/4

So the average number of comparisons for a list bearing n elements is 2n+3/4 comparisons.

6 0

2 years ago

Why are digital calendars considered to be a convenient way to maintain a study schedule?

marysya [2.9K]

Hey there!

Let's assume that this question is referring to every digital calendar ever made. As in, even those made on devices without internet connectivity or any other fancy features that we utilize with many digital calendars today.

If a planning device that came with a digital calendar didn't have internet connectivity, it wouldn't be able to be connected to the cloud. Back when these devices were around, it wasn't even plausible to store things like calendar events and contacts in what we know as the "cloud". Also, these devices probably had to be hardwired to a computer and new software had to be downloaded to them, so the updates weren't automatic. Archaic, right?

Also, consider the fact that even reputable websites/companies such as Google with Google Calendars or Apple with iCalendar will never go without their malfunctions or threats. Sometimes, these websites can be hacked and the data that they contain can be compromised, especially if they're stored on the cloud. Also, even though it's not realistic, Google or Apple could one day decide to completely get rid of their calendar programs altogether. So, this means that digital calendars are definitely able to be destroyed or lost.

That just leaves "They can be used anywhere". This is true, even with those archaic devices specifically used for scheduling events and such. Nowadays, you have your phone and possibly a laptop on you at all times, which will likely have a calendar on it as a stock application. So, I think this is your answer.

Hope this helped you out! :-)

3 0

2 years ago

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