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icang [17]
2 years ago
11

#Write a function called is_composite. is_composite should #take as input one integer. It should return True if the #integer is

composite, False if the integer is not not #composite. You may assume the integer will be greater than #2 and less than 1000.
Computers and Technology
1 answer:
malfutka [58]2 years ago
3 0

Answer:

// A optimized school method based C++ program to check  

// if a number is composite.  

#include <bits/stdc++.h>  

using namespace std;  

bool isComposite(int n)  

{  

// Corner cases  

if (n <= 1) return false;  

if (n <= 3) return false;  

// This is checked so that we can skip  

// middle five numbers in below loop  

if (n%2 == 0 || n%3 == 0) return true;  

for (int i=5; i*i<=n; i=i+6)  

 if (n%i == 0 || n%(i+2) == 0)  

 return true;  

return false;  

}  

// Driver Program to test above function  

int main()  

{  

isComposite(11)? cout << " true\n": cout << " false\n";  

isComposite(15)? cout << " true\n": cout << " false\n";  

return 0;  

}

Explanation:

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Answer:

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Explanation:

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This could also be as a results of single matrix created when the student use an incorrect indicator variables and included an additional indicator column which created linearly dependent columns.

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Given sphereRadius and piVal, compute the volume of a sphere and assign to sphereVolume. Look up the equation online (e.g., http
fenix001 [56]

Answer:

  1. #include <stdio.h>
  2. int main()
  3. {
  4.    const double piVal = 3.14159;
  5.    double sphereVolume = 0.0;
  6.    double sphereRadius = 0.0;
  7.    
  8.    sphereRadius = 1.0;
  9.    sphereVolume = 4.0/ 3.0 * piVal * sphereRadius * sphereRadius * sphereRadius;
  10.    
  11.    
  12.    printf("Sphere volume: %lf\n", sphereVolume);
  13.    return 0;
  14. }

Explanation:

Firstly we can identify the formula to calculate volume of sphere which is

Volume = 4/3 \pi r^{3}

With this formula in mind, we can apply this formula to calculate the volume of sphere in Line 10. This is important to perform floating-point division 4.0/3.0 to ensure the resulting value is a floating value as well. Since we have been given piVal and sphereRadius, we can just multiply the result of floating-point division with piVal and sphereRadius and get the sphereVolume value.

At last, display the sphere volume using printf method (Line 13).

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