Answer:
Option (D) is the correct answer of this question.
Explanation:
Moore's Law relates to Moore's theory that the number of transistors on a microchip doubles every two years while device costs are halved.
Interpretations of Moore's law assert the computing power doubles every 18 months.The Moore's Law theory states that development is exponential.Moore's Law states that every couple of years we should expect our computers to increase their speed and capacity and we'll pay less for them.h
Option(A),Option(B) ,Option(c) and option(E) do not belongs to Moore's law so these options are incorrect options.
Answer:To check spelling in a Word document, open up the document, head to the “Review” tab, then click on “Spelling & Grammar” (part of the “Proofing” group of tools). Then a window will appear showing the first word the program believes to be misspelled. Click through the options to review the whole document.
Explanation:Hope this helped u out btw can i plz have brainlist only if u wanna give me brainlist though have an great day kind sir or ma'am!
Answer: Provided in the explanation section
Explanation:
The question says :
You are working on a documentation file userNotes.txt with some members of your software development team. Just before the file needs to be submitted, you manager tells you that a company standard requires that one blank space be left between the end-of-sentence period (.) and the start of the next sentence. (This rule does not affect sentences at the very end of a line.) For example, this is OK: Turn the knob. Push the "on" button. This is not: Turn the knob. Push the "on" button. Asking around among your team members, you discover that some of them have already typed their sentences in the approved manner, but others have inserted two or even more blanks between sentences. You need to fix this fast, and the first thing you want to do is to find out how bad the problem is. What command would you give to list all lines of userNotes.txt that contain sentence endings with two or more blanks before the start of the next sentence?
Solution:
Here, our fundamental aim is to look for the content which is having single space between different sentences. As it sentences finishing with . Going before with single and various spaces we have to channel and match just e the sentences which are finishing with ". "
For this we use order called "GREP" in Unix. "GREP " represents worldwide quest for standard articulation. This order is utilized inquiry and print the lines that are coordinating with determined string or an example. The example or indicated string that we have to look through we call it as customary articulation.
Syntax of GREP:
GREP [OPTIONS] PATTERN [FILE_NAME]
For our solution please follow the command
GREP "*\•\s$" userNotes.txt
Now it will display a all the lines having . Followed by single space.
Base on the question, and in my further computation, the possible answers would be the following and I hope you are satisfied with my answer and feel free to ask for more.
- If you want to determine the Thevenin equivalent voltage and resistance without overloading the battery, then apply some known resistance
<span><span>RL</span><span>RL</span></span> and measure the output voltage as <span><span>VL</span><span>VL</span></span>. Measure the voltage without a load as <span><span>V<span>OC</span></span><span>V<span>OC</span></span></span>. The voltage divider equation tells us that
<span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span><span><span>VL</span>=<span>V<span>OC</span></span><span><span>RL</span><span><span>R<span>TH</span></span>×<span>RL</span></span></span></span></span>
Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.
Answer:
See explaination for the program code
Explanation:
code:
public static int[] countLastDigits(int[] list) {
int[] count = new int[10];
for (int i = 0; i < list.length; i++) {
int digit = list[i] % 10;
count[digit]++;
}
return count;
}
