answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ivahew [28]
2 years ago
9

Which expansion slot is used by an NVMe compliant device?

Computers and Technology
1 answer:
miskamm [114]2 years ago
5 0

Answer:

3. PCIe

Explanation:

An expansion card is a slot on the motherboard of a computer which allow users use an additional feature such as network, video, sound that may not be available before.

PCIe is an expansion slot that is used by an NVMe compliant device. NVMe is the short form or acronym for “Non–Volatile Memory express. ”

You might be interested in
The terminal window wants to evaluate your current bash knowledge by using the ~/workspace/nested-directories folder:
tia_tia [17]

Answer:

a. cd into the nested directories/ nested - level - 1 / directory using an absolute path

Explanation:

The directory is a location on the hard disk, which is also called a folder. It contains the files and also contains the other directories called sub directories.

A path to a file is merged with a slash and determines the file or directory in the operating system. An absolute path is the location file or directory from the actual file system

The directory's absolute path starts with a slash, and all slashed in the directory separates the directions.

All directions in the absolute path are written on the left side. The last name in the path may belong to the file, and the pwd command can determine the current directory.

The relative path is the location of the file. It begins with the working directory. An absolute path is unambiguous and working with deeply nested directories.

There are two commands which are used such as

  • cd
  • pwd
  1. cd is used for changing directory
  2. pwd is used for the working directory

We easily navigate the file system with the help of an absolute path.

7 0
2 years ago
in a small office, there are 5 computers, a network printer, and a broadband connection to the internet. what devices are needed
Nataly [62]

Answer:

<em>Ethernet cables, Network Adapters, Modem, Routers, Switches.</em>

Explanation:

<em>The devices that are required in setting up a wired network for the 5 computer comprises of the following devices </em>

  • <em>Ethernet Cables</em>
  • <em>Network Adapters</em>
  • <em>Modem/Router</em>
  • <em>Network Switch</em>

<em>Ethernet cables: They are called network cables or RJ-45 cables used to in connecting two or more computers together. it has different categories called, the untwisted pair and twisted pair Ethernet, with a speed from 10-1000</em>

<em>Network Adapters : This adapters allows a computer device to connect and interface with a network computer</em>

<em>Modem/Routers : A router is a device that that sits in the  middle  between your local computers and modems. it takes receives information or gets information from the modem and delivers it to the computer</em>

<em>Network switch: it connects more than two computers together to a network and share data among themselves and other devices on the network</em>

6 0
2 years ago
8.Change the following IP addresses from binary notation to dotted-decimal notation: a.01111111 11110000 01100111 01111101 b.101
Andrews [41]

Answer:

a. 01111111 11110000 01100111 01111101 dotted decimal notation:

(127.240.103.125)

b. 10101111 11000000 11111000 00011101 dotted decimal notation: (175.192.248.29)

c. 11011111 10110000 00011111 01011101 dotted decimal notation:

(223.176.31.93)

d. 11101111 11110111 11000111 00011101 dotted decimal notation:

(239.247.199.29)

a. 208.34.54.12 class is C

b. 238.34.2.1 class is D

c. 242.34.2.8 class is E

d. 129.14.6.8 class is B

a.11110111 11110011 10000111 11011101 class is E

b.10101111 11000000 11110000 00011101 class is B

c.11011111 10110000 00011111 01011101 class is C

d.11101111 11110111 11000111 00011101 class is D

Explanation:

8 a. 01111111 11110000 01100111 01111101

we have to convert this binary notation to dotted decimal notation.

01111111 = 0*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

           = 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1*4 + 1*2 + 1

           = 64 + 32 + 16 + 8 + 4 + 2 + 1

           = 127

11110000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

               = 1*128 + 1*64 + 1*32 + 16 + 0 + 0 + 0 + 0

               = 128 + 64 + 32 + 16

               = 240

01100111 = 0*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

               = 0 + 1*64 + 1*32 + 0 + 0 + 4 + 2 + 1

               = 64 + 32 + 4 + 2 + 1

               = 103

01111101   = 0*2^7 + 1*2^6 + 1*2^5+ 1*2^4 +1*2^3 +1*2^2 + 0*2^1 + 1*2^0

               = 0 + 1*64 + 1*32 + 1*16 + 1*8 + 1* 4 + 0 + 1

               = 64 + 32 + 16 + 8 + 4 + 1

               = 125

So the IP address from binary notation 01111111 11110000 01100111 01111101 to dotted decimal notation is : 127.240.103.125

b) 10101111 11000000 11111000 00011101

10101111 = 1*2^7 + 0*2^6 + 1*2^5 + 0*2^4 + 1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

             = 175

11000000 = 1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 + 0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

                 = 192

11111000 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +1*2^3 + 0*2^2 + 0*2^1 + 0*2^0

              = 248

00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

               = 29

So the IP address from binary notation 10101111 11000000 11111000 00011101  to dotted decimal notation is : 175.192.248.29

c) 11011111 10110000 00011111 01011101

11011111 = 1*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

           = 223

10110000 =  1*2^7 + 0*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 0*2^2 + 0*2^1 + 0*2^0

                = 176

00011111 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

              = 31

01011101 = 0*2^7 + 1*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

              = 93

So the IP address from binary notation 11011111 10110000 00011111 01011101 to dotted decimal notation is :223.176.31.93

d) 11101111 11110111 11000111 00011101

11101111 = 1*2^7 + 1*2^6 + 1*2^5 + 0*2^4 +1*2^3 + 1*2^2 + 1*2^1 + 1*2^0

            = 239

11110111 = 1*2^7 + 1*2^6 + 1*2^5 + 1*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

           = 247

11000111 =  1*2^7 + 1*2^6 + 0*2^5 + 0*2^4 +0*2^3 + 1*2^2 + 1*2^1 + 1*2^0

              = 199

00011101 = 0*2^7 + 0*2^6 + 0*2^5 + 1*2^4 +1*2^3 + 1*2^2 + 0*2^1 + 1*2^0

               = 29

So the IP address from binary notation 11101111 11110111 11000111 00011101 to dotted decimal notation is : 239.247.199.29

9. In order to the find the class check the first byte of the IP address which is first 8 bits and check the corresponding class as follows:                

Class A is from 0 to 127

Class B is from 128 to 191

Class C is from 192 to 223

Class D is from 224 to 239

Class E is from 240 to 255

a. 208.34.54.12

If we see the first byte of the IP address which is 208, it belongs to class C as class C ranges from 192 to 223.

b. 238.34.2.1

If we see the first byte of the IP address which is 238, it belongs to class D as Class D ranges from 224 to 239.

c. 242.34.2.8

If we see the first byte of the IP address which is 242, it belongs to class E as Class E ranges from 240 to 255.

d. 129.14.6.8

If we see the first byte of the IP address which is 129, it belongs to class B as Class B ranges from 128 to 191.

10. In order to find the class of the IP addresses in easy way, start checking bit my bit from the left of the IP address and follow this pattern:

0 = Class A

1 - 0 = Class B

1 - 1 - 0 = Class C

1 - 1 - 1 - 0 = Class D

1 - 1 - 1 - 1 = Class E

a. 11110111 11110011 10000111 11011101

If we see the first four bits of the IP address they are 1111 which matches the pattern of class E given above. So this IP address belongs to class E.

b. 10101111 11000000 11110000 00011101

If we see the first bit is 1, the second bit is 0 which shows that this is class B address as 1 0 = Class B given above.

c. 11011111 10110000 00011111 01011101

The first bit is 1, second bit is 1 and third bit is 0 which shows this address belongs to class C as 110 = Class C given above.

d. 11101111 11110111 11000111 00011101

The first bit is 1, the second bit is also 1 and third bit is also 1 which shows that this address belongs to class D.

3 0
2 years ago
An attacker distributes hostile content on Internet-accessible Web sites that exploit unpatched and improperly secured client so
julia-pushkina [17]

Answer:

Since the attack impacts the client SANS Critical Security Controls. This act affects the Inventory of authorized and unauthorized software running on the victim's machine.

5 0
2 years ago
Read 2 more answers
Why are smartphones and tablets capable of handling rich content and interactivity?
NikAS [45]

Answer:

Explanation:

With the advance in technology, smartphones, and tablets are built to meet the ever-increasing needs of users.

Smartphones are mobile phones that also have internet connectivity, they can be used to make calls and perform many tasks just like the conventional desktop. Smartphones and tablets are indeed considered computers because they also process inputs in form of commands and they produce outputs.

Smartphones and tablets are capable of handling rich content and interactivity because:

1. Wireless synchronization with other devices: Just like desktops, laptops, they can interact with other devices, and can receive and also send information doesn't matter the distance.

2. They have Internet connectivity.

3. They have strong hardware, good storage capacity.

4. They have inbuilt software and are capable of accepting other software and programs.

5. They are built with an appealing user interface.

6. Just as computers have processors, smartphones and tablets also have processors to ensure their speed at processing informations.

3 0
2 years ago
Other questions:
  • Sharon reads two different articles about avocados. The first article, in a weight loss magazine, claims that avocados are unhea
    10·2 answers
  • The ______ is the information center that drivers need to refer to when they're NOT scanning the road.
    7·1 answer
  • What output is produced by the following program segment? Why? (Recall that name.charAt(i) is the i-th character in the string,
    11·1 answer
  • __________ access control is a form of __________ access control in which users are assigned a matrix of authorizations for part
    8·1 answer
  • Question 1 :Which type of unshielded twisted pair (UTP) cable is commonly used for 1000BASE-T Ethernet networks and is often mad
    8·1 answer
  • Write a function named max that accepts two integer values as arguments and returns the value that is the greater of the two. Fo
    12·1 answer
  • 7.8.1: Function pass by reference: Transforming coordinates. Define a function CoordTransform() that transforms the function's f
    6·1 answer
  • 1. Assign to maxSum the max of (numA, numB) PLUS the max of (numY, numZ). Use just one statement. Hint: Call FindMax() twice in
    7·1 answer
  • A variable like userNum can store a value like an integer. Extend the given program to print userNum values as indicated. (1) Ou
    15·1 answer
  • Write a MATLAB function named lin_spaced_vector with two inputs and one return value. The first input will be a single real numb
    7·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!