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Orlov [11]
1 year ago
9

Elaine is upset with her group members because she wanted to lead the group but is not allowed to. She found that other group me

mbers are also finding it difficult to adjust in their roles. Which stage of group development is Elaine’s group going through?
Computers and Technology
2 answers:
11111nata11111 [884]1 year ago
6 0
The stage the group is in is forming
zubka84 [21]1 year ago
4 0

the answer it not forming

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Create a program named Auction that allows a user to enter an amount bid on an online auction item. Include three overloaded met
Olin [163]

Answer:

Explanation:

The following code is written in Java and creates the overloaded methods as requested. It has been tested and is working without bugs. The test cases are shown in the first red square within the main method and the output results are shown in the bottom red square...

class Auction {

   public static void main(String[] args) {

       bid(10);

       bid(10.00);

       bid("10 dollars");

       bid("$10");

       bid("150 bills");

   }

   public static void bid(int bid) {

       if(bid >= 10) {

           System.out.println("Bid Accepted");

       } else {

           System.out.println("Bid not high enough");

       }

   }

   public static void bid(double bid) {

       if(bid >= 10) {

           System.out.println("Bid Accepted");

       } else {

           System.out.println("Bid not high enough");

       }

   }

   public static void bid(String bid) {

       if (bid.charAt(0) == '$') {

           if (Integer.parseInt(bid.substring(1, bid.length())) > 0) {

               System.out.println("Bid Accepted");

               return;

           } else {

               System.out.println("Bid not in correct Format");

               return;

           }

       }

       int dollarStartingPoint = 0;

       for (int x = 0; x < bid.length(); x++) {

           if (bid.charAt(x) == 'd') {

               if (bid.substring(x, x + 7).equals("dollars")) {

                   dollarStartingPoint = x;

               } else {

                   break;

               }

           }

       }

       if (dollarStartingPoint > 1) {

           if (Integer.parseInt(bid.substring(0, dollarStartingPoint-1)) > 0) {

               System.out.println("Bid Accepted");

               return;

           } else {

               System.out.println("Bid not in correct format");

               return;

           }

       } else {

           System.out.println("Bid not in correct format");

           return;

       }

   }

}

3 0
1 year ago
Assume the array of integers values has been created. Which condition must be used in the indicated area so the loop below will
scZoUnD [109]

Answer:

val > max

Explanation:

Assuming the values array is already created, inside the loop, we need to check if the val, a value in the values array, is greater than max. If it is greater than the max, that means it is our new max. Then we would set the max as the val. This way, if there is any value greater than max, it will be our max at the end of the loop.

7 0
1 year ago
Suppose you are given an unknown chip which could be any one of the of the following: 7400, 7402, 7404, 7408, 7410, 7420, 7427,
Olenka [21]

The answer & explanation for this question is given in the attachment below.

3 0
1 year ago
Algorithmic Complexity: what is the asymptotic complexity (Big-O) of each code section? Identify the critical section of each.\
AleksandrR [38]

Answer:

Check the explanation

Explanation:

1) f(n) = O( 1 ), since the loops runs a constant number of times independent of any input size

there is no critical section in the code, as a critical section is some part of code which is shared by multiple threads or even processes to modify any shared variable.This code does not contain any variable which can be shared.

2) f(n) = O( log n! ), the outer loop runs for n times, and the inner loop runs log k times when i = k,ie the total number of print will be – log 1 + log2 +log3 +log4+…...+ log n = log (1 . 2 . 3 . 4 . ……. . n ) =log n!

there is no critical section in the code, as a critical section is some part of code which is shared by multiple threads or even processes to modify any shared variable.This code does not contain any variable which can be shared.

Note : Log (m *n) = Log m + Log n : this is property of logarithm

3) f(n) = O( n^2 ), since both outer and inner loop runs n times hence , the total iterations of print statement will be : n +n+n+…+n

for n times, this makes the complexity – n * n = n2

there is no critical section in the code, as a critical section is some part of code which is shared by multiple threads or even processes to modify any shared variable.This code does not contain any variable which can be shared.

4 0
2 years ago
Create a program to deteate a program to determine whether a user-specified altitude [meters] is in the troposphere, lower strat
allsm [11]

Answer:

#include <iostream>

using namespace std;

int main()

{

   float altitude;

   cout<<"Enter alttitude in meter";

cin >>altitude;

if(altitude<0 || altitude > 50000)

{

   cout<<"Invalid value entered";

   return 0;

}

else{

   if(altitude<= 10000)

   {cout <<"In troposphere "<<endl;}

   

   else if(altitude>10000 && altitude<=30000)

   {cout <<"In lower stratosphere"<<endl;}

   

   else if(altitude>30000 && altitude<=50000)

   {cout <<"In upper stratosphere"<<endl;}

   

}

   return 0;

}

Explanation:

Define a float type variable. Ask user to enter altitude in meters. Store value to altitude variable.

Now check if value entered is positive and less than 5000,if its not in the range of 0-50,000 display a termination message and exit else check if it's in less than 10000, in between 10000 and 30000 or in between 30000 and 50000.

10,000 is above sea level is troposphere.

10,000-30,000 is lower stratosphere.

30,000-50,000 is upper stratosphere.

8 0
2 years ago
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