Answer:
Pseudo CODE
a)
n= Input “Enter 5 integer value”
b)
sum=0.0
For loop with i ranging from 0 - 5
Inside loop sum=n[i]+sum
Outside loop avg= sum/5
Print avg
c)
small=n[0] # assume the first number in the list is smallest
large= n[0] # assume the first number in the list is largest
For loop with i ranging from 0 - 5
Inside loop if n[i]<small #if any another number is smaller than small(variable)
Inside if Then small=n[i]
Inside loop if n[i]>large # if any another number is larger than large(variable)
Inside if then large=n[i]
Print small
Print large
d)
print avg
print small
print large
Answer:
Procurement
Explanation:
Characteristics hardware lifecycle:
- Procurement- Acquiring new IT hardware assets involves evaluating vendors, purchase orders, receiving, and device labeling.
- Deployment - Hardware configuration and installment, placing hardware and software assets into production environments.
- Maintenance & Support - Management of assets include scheduling scans and getting audit history.
- Upgrade - Before you retire your IT hardware assets, you’ll reach a processing plateau that can be restored with hardware upgrades.
Answer:
#include<iostream>
using namespace std;
void main()
{
int townA_pop,townB_pop,count_years=1;
double rateA,rateB;
cout<<"please enter the population of town A"<<endl;
cin>>townA_pop;
cout<<"please enter the population of town B"<<endl;
cin>>townB_pop;
cout<<"please enter the grothw rate of town A"<<endl;
cin>>rateA;
cout<<"please enter the grothw rate of town B"<<endl;
cin>>rateB;
while(townA_pop < townB_pop)//IF town A pop is equal or greater than town B it will break
{
townA_pop = townA_pop +( townA_pop * (rateA /100) );
townB_pop = townB_pop +( townB_pop * (rateB /100) );
count_years++;
}
cout<<"after "<<count_years<<" of years the pop of town A will be graeter than or equal To the pop of town B"<<endl;
}
Explanation:
Bdbxhdhdhdbxbdhdhxhxhdhdhdhdhdhdhdhdhdbdhdhdhdhdhdhrhrhrhrhrhdhdhdhdisisieiejjdidieieieieieiei
Solution:
The flagging of an uncommon last name as a spelling error can be stopped by opening the shortcut menu on the first occurrence of the name and selecting of ignoring all.
Thus the required right answer is B.
