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Ainat [17]
1 year ago
6

Write code which takes a sentence as an input from the user and then prints the length of the first word in that sentence.

Computers and Technology
1 answer:
Afina-wow [57]1 year ago
7 0

import java.util.Scanner;

public class U2_L3_Activity_Four {

   public static void main(String[] args) {

       Scanner scan = new Scanner(System.in);

       System.out.println("Enter a sentence.");

       String sent = scan.nextLine();

       int count = 0;

       for (int i = 0; i < sent.length(); i++){

           char c = sent.charAt(i);

           if (c != ' '){

               count++;

       }

           else{

               break;

           }

       

   }

       System.out.println("The first word is " + count +" letters long");

   

   }

}

We check to see when the first space occurs in our string and we add one to our count variable for every letter before that. I hope this helps!

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Solve for <span><span>R<span>TH</span></span><span>R<span>TH</span></span></span>, and you know that <span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span><span><span>V<span>TH</span></span>=<span>V<span>OC</span></span></span></span>.

6 0
2 years ago
Remember that ""state space"" refers to the space of all potential possibilities. Which dichotomous questions below will success
egoroff_w [7]

Answer:

Please check options are not given. Please check explanation for corrected version.

Explanation:

Options are not mentioned. Please post the complete question.

However, if "below" is removed, the question makes sense. I am taking it that way.

Dichotomous question means those questions which has two outcomes: true or false.

For the given condition, this is possible only if:

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  • head, 4
  • head, 5
  • head, 6
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However, each time, each mentioned condition should be strictly followed.

And fewer outcome than 1 is virtually or realistically impossible, as both coin and dice will roll out one outcome in any condition certainly.

7 0
2 years ago
Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their
vekshin1

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

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solve we get

k = 1.5

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and

when f = 0.4 and S = 125 %

put the value in equation 1

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1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

7 0
2 years ago
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