Answer:
Option (c) is the correct answer of this question.
Explanation:
RAM (Random Access Memory) It is a type of computer memory which can also be retrieved and adjusted in either sequence, usually still had to preserve operating memory and bytecode.
It is a type storage device, and maintains the data used when the device is operating.RAM makes file access more frequently compared with certain digital storage types.
<u>For Example</u>:- PCs, tablets, smartphones ,printers etc.
Other options are not related to the given scenario.
A business plan and a <u>financial plan</u> to show the both his plan to make money, and how much money he will make, spend, use.
The below code will help you to solve the given problem and you can execute and cross verify with sample input and output.
#include<stdio.h>
#include<string.h>
int* uniqueValue(int input1,int input2[])
{
int left, current;
static int arr[4] = {0};
int i = 0;
for(i=0;i<input1;i++)
{
current = input2[i];
left = 0;
if(current > 0)
left = arr[(current-1)];
if(left == 0 && arr[current] == 0)
{
arr[current] = input1-current;
}
else
{
for(int j=(i+1);j<input1;j++)
{
if(arr[j] == 0)
{
left = arr[(j-1)];
arr[j] = left - 1;
}
}
}
}
return arr;
}
Answer:
The program in Python is as follows:
n = int(input("Enter an integer: "))
if n < 0:
n = 0
print("Sequence:",end=" ")
for i in range(n,-1,-1):
if i%2 == 0:
print(i,end = " ")
Explanation:
This gets input for n
n = int(input("Enter an integer: "))
This sets n to 0 if n is negative
<em>if n < 0:</em>
<em> n = 0</em>
This prints the string "Sequence"
print("Sequence:",end=" ")
This iterates from n to 0
for i in range(n,-1,-1):
This check if current iteration value is even
if i%2 == 0:
If yes, the number is printed
print(i,end = " ")
