Answer:
High level Language
understand
Explanation:
rocket is 0...4433456u888
Answer:
b
Explanation:
First, we need to initialize the classifier.
Then, we are required to train the classifier.
The next step is to predict the target.
And finally, we need to evaluate the classifier model.
You will find different algorithms for solving the classification problem. Some of them are like decision tree classification etc.
However, you need to know how these classifier works. And its explained before:
You need to initialize the classifier at first.
All kinds of classifiers in the scikit-learn make use of the method fit(x,y) for fitting the model or the training for the given training set in level y.
The predict(x) returns the y which is the predicted label.And this is prediction.
For evaluating the classifier model- the score(x,y) gives back the certain score for a mentioned test data x as well as the test label y.
<span>BCD only goes from digit 0 (0000) to digit 9 (1001), because for 10 you need two digits, so all you've got to do is make a function that produces high for numbers from 10 (1010) to 15 (1111) as follows:
A3 A2 A1 A0 F
0 0 0 0 0
0 0 0 1 0
0 0 1 0 0
...........................
1 0 0 0 0
1 0 1 0 1
1 0 1 1 1
1 1 0 0 1
1 1 0 1 1
1 1 1 0 1
1 1 1 1 1
Then simplify the function:
F = A3*A2 + A3*A1
Finally just draw or connect the circuit using NAND</span>
Answer:
Python Code:
def validate_url(url):
#Creating the list of valid protocols and file name extensions
valid_protocols = ['http', 'https', 'ftp']
valid_fileinfo = ['.html', '.csv', '.docx']
#splitting the url into two parts
url_split = url.split('://')
isProtocolValid = False
isFileValid = False
#iterating over the valid protocols and file names for validity
for x in valid_protocols:
if x in url_split[0]:
isProtocolValid = True
break
for x in valid_fileinfo:
if x in url_split[1]:
isFileValid = True
break
#Returning the result if the URL has both valid protocol and file extension
return (isProtocolValid and isFileValid)
url = input("Enter an URL: ")
print(validate_url(url))
Explanation:
The image of the output code is attached. Hope it helps.
