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Allushta [10]
2 years ago
5

Suppose your company has decided that it needs to make certain busy servers faster. Processes in the workload spend 60% of their

time using the CPU and 40% on I/O. To achieve an overall system speedup of 25%: a. How much faster does the CPU need to be? b. How much faster does the disk need to be?
Computers and Technology
1 answer:
vekshin12 years ago
7 0

Answer:

CPU need 50% much faster

disk need 100% much faster

Explanation:

given data

workload spend time CPU  = 60%

workload spend time I/O = 40%

achieve overall system speedup = 25%

to find out

How much faster does CPU need and How much faster does the disk need

solution

we apply here Amdahl’s law for the overall speed of a computer that is express as

S = \frac{1}{(1-f)+ \frac{f}{k} }      .............................1

here f is fraction of work i.e 0.6 and S is overall speed  i.e 100% + 25% = 125 % and k is speed up of component

so put all value in equation 1 we get

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.6)+ \frac{0.6}{k} }  

solve we get

k = 1.5

so we can say  CPU need 50% much faster

and

when f = 0.4 and S = 125 %

put the value in equation 1

S = \frac{1}{(1-f)+ \frac{f}{k} }  

1.25 = \frac{1}{(1-0.4)+ \frac{0.4}{k} }  

solve we get

k = 2

so here disk need 100% much faster

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Budget Analysis (use while loop) Write a program that asks the user to enter the amount that he or she has budgeted for a month.
Agata [3.3K]

Answer:

print('This program will help you determine whether you\'ve budgeted enough ' +

     'for your expenses. You\'ll just need to enter your budget and the ' +

     'cost of each of your expenses for the month and we will calculate ' +

     'the balance.')

budget = float(input('How much have you budgeted this month? '))

expenses = 0

check = 0

while check >= 0:

   check = float(input('Enter an expense amount or -1 to quit: '))

   if check != -1:

       expenses += check

balance = budget - expenses

if balance < 0:

   print('\nYou haven\'t budgeted enough. You\'re going to be $', \

         format(-1 * balance, ',.2f'), ' short this month.', sep = '')

elif balance == 0:

   print('\nBe careful. You\'ve budgeted just enough to make it through ' +

         'the month.')

else:

   print('\nYou will have $', format(balance, ',.2f'), ' extra this month.', \

         sep = '')

6 0
1 year ago
Describe a strategy for avoiding nested conditionals. Give your own example of a nested conditional that can be modified to beco
harina [27]

Answer:

One of the strategies to avoid nested conditional is to use logical expressions such as the use of AND & operator.

One strategy is to use an  interface class with a method. That method can be created to be used for a common functionality or purpose. This is also called strategy design pattern. You can move the chunk of conditional statement to that method. Then each class can implement that interface class and use that shared method according to their own required task by creating objects of sub classes and call that common method for any such object. This is called polymorphism.

Explanation:

Nested conditionals refers to the use of if or else if statement inside another if or else if statement or you can simply say a condition inside another condition. For example:

if( condition1) {  

//executes when condition1 evaluates to true

 if(condition2) {

//executes when condition1  and condition2 evaluate to true

 }  else if(condition3) {

 //when condition1 is true and condition3 is true

} else {

 //condition1  is true but neither condition2 nor conditions3 are true

}  }

The deeply nested conditionals make the program difficult to understand or read if the nested conditionals are not indented properly. Also the debugging gets difficult when the program has a lot of nested conditionals.

So in order to avoid nested conditionals some strategies are used such as using a switch statement.

Here i will give an example of one of the strategies i have mentioned in the answer.

Using Logical Expressions:

A strategy to avoid nested conditionals is to use logical expressions with logical operators such as AND operator. The above described example of nested conditionals can be written as:

if(condition1 && condition2){  //this executes only when both condition1 and condition2 are true

} else if(condition1 && condition3) {

this executes only when both condition1 and condition3 are true

} else if(condition1 ){

//condition1  is true but neither condtion2 nor condtion3 are true  }

This can further be modified to one conditional as:

if(!condition3){

// when  condition1 and condition2 are true

}

else

// condition3 is true

Now lets take a simple example of deciding to go to school or not based on some conditions.

if (temperature< 40){

  if (busArrived=="yes")   {

      if (!sick)       {

          if (homework=="done")           {

              printf("Go to school.");

          }

      }     

  }

}

This uses nested conditionals. This can be changed to a single conditional using AND logical operator.

if ((temperature <40) && (busArrived=="yes") &&

(!sick) && (homework=="done"))

{    cout<<"Go to school."; }

6 0
2 years ago
In object oriented programming, what is another name for the "attributes" of an object?
Ket [755]
I believe the word you're looking for is properties.
7 0
2 years ago
Dante wants to calculate the currently monthly subtotals for the sales of golf balls in his store. Which of the following will h
cupoosta [38]
I believe the answer is B
3 0
2 years ago
Row array gameScores contains all player scores. Construct a row array highScores than contains all player scores greater than m
Sever21 [200]

Answer:

The solution is written using Python as it has a simple syntax.

  1. def getHighScores(gameScores, minScore):
  2.    meetsThreshold = []
  3.    for score in gameScores:
  4.        if(score > minScore):
  5.            meetsThreshold.append(score)
  6.    return meetsThreshold
  7. gameScores = [2, 5, 7, 6, 1, 9, 1]
  8. minScore = 5
  9. highScores = getHighScores(gameScores, minScore)
  10. print(highScores)

Explanation:

Line 1-8

  • Create a function and name it as <em>getHighScores</em> which accepts two values, <em>gameScores</em> and <em>minScore</em>. (Line 1)
  • Create an empty list/array and assign it to variable <em>meetsThreshold</em>. (Line 2)
  • Create a for loop to iterate through each of the score in the <em>gameScores</em> (Line 4)
  • Set a condition if the current score is bigger than the <em>minScore</em>, add the score into the <em>meetsThreshold</em> list (Line 5-6)
  • Return <em>meetsThreshold</em> list as the output

Line 11-12

  • create a random list of <em>gameScores</em> (Line 11)
  • Set the minimum score to 5 (Line 12)

Line 13-14

  • Call the function <em>getHighScores()</em> and pass the<em> gameScores</em> and <em>minScore </em>as the arguments. The codes within the function <em>getHighScores()</em>  will run and return the <em>meetsThreshold </em>list and assign it to <em>highScores.</em> (Line 13)
  • Display <em>highScores</em> using built-in function print().
8 0
2 years ago
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