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natita [175]
2 years ago
12

In a system containing CPU 1 and Disk Drive A, the system is instructed to access Track 1, Track 9, Track 1, and then Track 9 of

Drive A. The arm is initially located at Track 1. Drive A requires 35 ms for each move. Without reordering, Drive A requires ____ to complete the access.
Computers and Technology
1 answer:
BartSMP [9]2 years ago
5 0

Answer:

Drive A requires 105 miliseconds to complete the access.

Explanation:

Hard Drives actually have physical reading and writing arms inside them which are used for reading and writing data on the drives. To perform these actions they have to move from one location to another.

The example given in the question states that the arm is moving between track 1 and track 9. With it's initial position at track 1, it makes the same movement exactly 3 times from track 1 to track 9. If it requires 35 miliseconds for this movement, then drive A should require a total time of 105 miliseconds or 0.105 seconds to complete the given task.

I hope this answer helps.

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Exercise 4: Bring in program grades.cpp and grades.txt from the Lab 10 folder. Fill in the code in bold so that the data is prop
Alex73 [517]

Answer:

Here is the C++ program:

#include <fstream>  //to create, write and read a file

#include <iostream>  // to use input output functions

using namespace std;  //to access objects like cin cout

const int MAXNAME = 20;  //MAXNAME is set to 20 as a constant

int main(){  //start of main() function

ifstream inData;  //creates an object of ifstream class

inData.open("grades.txt");  //uses that object to access and opens the text file using open() method

char name[MAXNAME + 1];   // holds the names

float average;   //stores the average

inData.get(name,MAXNAME+1);  //Extracts names characters from the file and stores them as a c-string until MAXNAME+1 characters have been extracted

while (inData){  //iterates through the file

 inData >> average;  //reads averages from file using the stream extraction operator

 cout << name << " has a(n) " << average << " average." << endl; //prints the names along with their averages

 inData.ignore(50,'\n');  //ignores 50 characters and resumes when  new line character is reached. It is used to clear characters from input buffer

 inData.get(name,MAXNAME+1);}  //keeps extracting names from file

return 0; }

Explanation:  

The program is well explained in the comments added to each line of the code. The program uses fstream object inData to access the grades.txt file. It gets and extracts the contents of the file using get() method, reads and extracts averages from file using the stream extraction operator. Then program displays the names along with their averages from grades.txt on output screen.

The grades.txt file, program and its output is attached.

3 0
2 years ago
One form of competition-based pricing is going-rate pricing, inwhich a firm bases its price largely on competitors' prices, with
Kobotan [32]

Answer:

Out of the four options , the option that is most suitable  is

option b. Cost, demand

<u>cost</u> or to <u>demand</u>

Explanation:

Going rate pricing is a form of competition based pricing. This pricing is commonly used for homogeneous products i.e., products with very minute distinction or variation among producers.

This type of pricing is based on setting price on the basis of the prevailing market trends in pricing of goods or services, so, the prices are largely based on the competition in the market rather than considering its own cost and demand.

8 0
2 years ago
When excel follows the order of operations the formula 8 * 3 + 2 equals?
Airida [17]
It follows the normal convention of BODMAS , which is the order of precedence of operations , so the answer equals to 26
3 0
2 years ago
What is the name of the item that supplies the exact or near exact voltage at the required wattage to all of the circuitry insid
gizmo_the_mogwai [7]

Answer:

It's the <u><em>power supply</em></u>

Explanation:

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4 0
2 years ago
12) Suppose you wanted a subroutine to return to an address that was 3 bytes higher in memory than the return address currently
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Answer:

.code

main proc

mov ecx,ebp

mov ecx, 787878

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invoke ExitProcess,0

main endp

MySe7en PROC

pop ecx

sub ecx, 3

mov

push ecx

ret

end main

8 0
2 years ago
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